Optimal. Leaf size=24 \[ x+\frac {x}{-5+x-24 x^2+\frac {\log (x)}{5-2 x}} \]
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Rubi [F] time = 0.96, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {495-648 x+6905 x^2-6540 x^3+16420 x^4-11712 x^5+2304 x^6+\left (-45+26 x-244 x^2+96 x^3\right ) \log (x)+\log ^2(x)}{625-750 x+6325 x^2-6060 x^3+16324 x^4-11712 x^5+2304 x^6+\left (-50+30 x-244 x^2+96 x^3\right ) \log (x)+\log ^2(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {495-648 x+6905 x^2-6540 x^3+16420 x^4-11712 x^5+2304 x^6+\left (-45+26 x-244 x^2+96 x^3\right ) \log (x)+\log ^2(x)}{\left (25-15 x+122 x^2-48 x^3-\log (x)\right )^2} \, dx\\ &=\int \left (1+\frac {-5-73 x+1250 x^2-1208 x^3+288 x^4}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}+\frac {5-4 x}{-25+15 x-122 x^2+48 x^3+\log (x)}\right ) \, dx\\ &=x+\int \frac {-5-73 x+1250 x^2-1208 x^3+288 x^4}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx+\int \frac {5-4 x}{-25+15 x-122 x^2+48 x^3+\log (x)} \, dx\\ &=x+\int \left (-\frac {5}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}-\frac {73 x}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}+\frac {1250 x^2}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}-\frac {1208 x^3}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}+\frac {288 x^4}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2}\right ) \, dx+\int \left (\frac {5}{-25+15 x-122 x^2+48 x^3+\log (x)}-\frac {4 x}{-25+15 x-122 x^2+48 x^3+\log (x)}\right ) \, dx\\ &=x-4 \int \frac {x}{-25+15 x-122 x^2+48 x^3+\log (x)} \, dx-5 \int \frac {1}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx+5 \int \frac {1}{-25+15 x-122 x^2+48 x^3+\log (x)} \, dx-73 \int \frac {x}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx+288 \int \frac {x^4}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx-1208 \int \frac {x^3}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx+1250 \int \frac {x^2}{\left (-25+15 x-122 x^2+48 x^3+\log (x)\right )^2} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.28, size = 29, normalized size = 1.21 \begin {gather*} x-\frac {x (-5+2 x)}{-25+15 x-122 x^2+48 x^3+\log (x)} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.63, size = 43, normalized size = 1.79 \begin {gather*} \frac {48 \, x^{4} - 122 \, x^{3} + 13 \, x^{2} + x \log \relax (x) - 20 \, x}{48 \, x^{3} - 122 \, x^{2} + 15 \, x + \log \relax (x) - 25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.27, size = 32, normalized size = 1.33 \begin {gather*} x - \frac {2 \, x^{2} - 5 \, x}{48 \, x^{3} - 122 \, x^{2} + 15 \, x + \log \relax (x) - 25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 30, normalized size = 1.25
method | result | size |
risch | \(x -\frac {x \left (2 x -5\right )}{48 x^{3}-122 x^{2}+\ln \relax (x )+15 x -25}\) | \(30\) |
norman | \(\frac {x \ln \relax (x )-122 x^{3}-20 x +13 x^{2}+48 x^{4}}{48 x^{3}-122 x^{2}+\ln \relax (x )+15 x -25}\) | \(44\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.53, size = 43, normalized size = 1.79 \begin {gather*} \frac {48 \, x^{4} - 122 \, x^{3} + 13 \, x^{2} + x \log \relax (x) - 20 \, x}{48 \, x^{3} - 122 \, x^{2} + 15 \, x + \log \relax (x) - 25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.33, size = 31, normalized size = 1.29 \begin {gather*} x+\frac {5\,x-2\,x^2}{15\,x+\ln \relax (x)-122\,x^2+48\,x^3-25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.16, size = 27, normalized size = 1.12 \begin {gather*} x + \frac {- 2 x^{2} + 5 x}{48 x^{3} - 122 x^{2} + 15 x + \log {\relax (x )} - 25} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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