Optimal. Leaf size=30 \[ \frac {e^2 \log (5)}{5+e^{\frac {e^{e^x}}{-1+\frac {x}{3+x}}}+x} \]
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Rubi [F] time = 44.06, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {-3 e^2 \log (5)+e^{e^x+\frac {1}{3} e^{e^x} (-3-x)} \left (e^2 \log (5)+e^{2+x} (3+x) \log (5)\right )}{75+3 e^{\frac {2}{3} e^{e^x} (-3-x)}+30 x+3 x^2+e^{\frac {1}{3} e^{e^x} (-3-x)} (30+6 x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {e^2 \left (-3+e^{e^x-\frac {1}{3} e^{e^x} (3+x)}+e^{e^x+x-\frac {1}{3} e^{e^x} (3+x)} (3+x)\right ) \log (5)}{3 \left (5+e^{-\frac {1}{3} e^{e^x} (3+x)}+x\right )^2} \, dx\\ &=\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {-3+e^{e^x-\frac {1}{3} e^{e^x} (3+x)}+e^{e^x+x-\frac {1}{3} e^{e^x} (3+x)} (3+x)}{\left (5+e^{-\frac {1}{3} e^{e^x} (3+x)}+x\right )^2} \, dx\\ &=\frac {1}{3} \left (e^2 \log (5)\right ) \int \left (-\frac {3}{(5+x)^2}-\frac {3+5 e^{e^x}+15 e^{e^x+x}+e^{e^x} x+8 e^{e^x+x} x+e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {6+5 e^{e^x}+15 e^{e^x+x}+e^{e^x} x+8 e^{e^x+x} x+e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}\right ) \, dx\\ &=\frac {e^2 \log (5)}{5+x}-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {3+5 e^{e^x}+15 e^{e^x+x}+e^{e^x} x+8 e^{e^x+x} x+e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {6+5 e^{e^x}+15 e^{e^x+x}+e^{e^x} x+8 e^{e^x+x} x+e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx\\ &=\frac {e^2 \log (5)}{5+x}-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {3+e^{e^x} (5+x)+e^{e^x+x} \left (15+8 x+x^2\right )}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {6+e^{e^x} (5+x)+e^{e^x+x} \left (15+8 x+x^2\right )}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx\\ &=\frac {e^2 \log (5)}{5+x}-\frac {1}{3} \left (e^2 \log (5)\right ) \int \left (\frac {3}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {5 e^{e^x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {15 e^{e^x+x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {e^{e^x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {8 e^{e^x+x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}+\frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2}\right ) \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \left (\frac {6}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}+\frac {5 e^{e^x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}+\frac {15 e^{e^x+x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}+\frac {e^{e^x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}+\frac {8 e^{e^x+x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}+\frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )}\right ) \, dx\\ &=\frac {e^2 \log (5)}{5+x}-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx-\left (e^2 \log (5)\right ) \int \frac {1}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx-\frac {1}{3} \left (5 e^2 \log (5)\right ) \int \frac {e^{e^x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx+\frac {1}{3} \left (5 e^2 \log (5)\right ) \int \frac {e^{e^x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx+\left (2 e^2 \log (5)\right ) \int \frac {1}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx-\frac {1}{3} \left (8 e^2 \log (5)\right ) \int \frac {e^{e^x+x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx+\frac {1}{3} \left (8 e^2 \log (5)\right ) \int \frac {e^{e^x+x} x}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx-\left (5 e^2 \log (5)\right ) \int \frac {e^{e^x+x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )^2} \, dx+\left (5 e^2 \log (5)\right ) \int \frac {e^{e^x+x}}{(5+x)^2 \left (1+5 e^{\frac {1}{3} e^{e^x} (3+x)}+e^{\frac {1}{3} e^{e^x} (3+x)} x\right )} \, dx\\ &=\frac {e^2 \log (5)}{5+x}-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x} x}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx-\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x} x}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx+\frac {1}{3} \left (e^2 \log (5)\right ) \int \frac {e^{e^x+x} x^2}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx-\left (e^2 \log (5)\right ) \int \frac {1}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx-\frac {1}{3} \left (5 e^2 \log (5)\right ) \int \frac {e^{e^x}}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx+\frac {1}{3} \left (5 e^2 \log (5)\right ) \int \frac {e^{e^x}}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx+\left (2 e^2 \log (5)\right ) \int \frac {1}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx-\frac {1}{3} \left (8 e^2 \log (5)\right ) \int \frac {e^{e^x+x} x}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx+\frac {1}{3} \left (8 e^2 \log (5)\right ) \int \frac {e^{e^x+x} x}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx-\left (5 e^2 \log (5)\right ) \int \frac {e^{e^x+x}}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )^2} \, dx+\left (5 e^2 \log (5)\right ) \int \frac {e^{e^x+x}}{(5+x)^2 \left (1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)\right )} \, dx\\ &=\text {Rest of rules removed due to large latex content} \end {aligned} \end {gather*}
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Mathematica [A] time = 5.21, size = 41, normalized size = 1.37 \begin {gather*} \frac {e^{2+\frac {1}{3} e^{e^x} (3+x)} \log (5)}{1+e^{\frac {1}{3} e^{e^x} (3+x)} (5+x)} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.56, size = 39, normalized size = 1.30 \begin {gather*} \frac {e^{\left (e^{x} + 2\right )} \log \relax (5)}{{\left (x + 5\right )} e^{\left (e^{x}\right )} + e^{\left (-\frac {1}{3} \, {\left ({\left (x + 3\right )} e^{\left (e^{x} + 2\right )} - 3 \, e^{\left (x + 2\right )}\right )} e^{\left (-2\right )}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 1.48, size = 2069, normalized size = 68.97 result too large to display
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.08, size = 20, normalized size = 0.67
method | result | size |
risch | \(\frac {{\mathrm e}^{2} \ln \relax (5)}{5+{\mathrm e}^{-\frac {\left (3+x \right ) {\mathrm e}^{{\mathrm e}^{x}}}{3}}+x}\) | \(20\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.59, size = 34, normalized size = 1.13 \begin {gather*} \frac {e^{\left (\frac {1}{3} \, x e^{\left (e^{x}\right )} + e^{\left (e^{x}\right )} + 2\right )} \log \relax (5)}{{\left (x + 5\right )} e^{\left (\frac {1}{3} \, x e^{\left (e^{x}\right )} + e^{\left (e^{x}\right )}\right )} + 1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.26, size = 23, normalized size = 0.77 \begin {gather*} \frac {{\mathrm {e}}^2\,\ln \relax (5)}{x+{\mathrm {e}}^{-{\mathrm {e}}^{{\mathrm {e}}^x}-\frac {x\,{\mathrm {e}}^{{\mathrm {e}}^x}}{3}}+5} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.30, size = 22, normalized size = 0.73 \begin {gather*} \frac {e^{2} \log {\relax (5 )}}{x + e^{\left (- \frac {x}{3} - 1\right ) e^{e^{x}}} + 5} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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