Optimal. Leaf size=22 \[ \frac {12}{(2-x) \left (3+\frac {5 x}{4 \log (x)}\right )} \]
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Rubi [F] time = 0.50, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {480-240 x+(-480+480 x) \log (x)+576 \log ^2(x)}{100 x^2-100 x^3+25 x^4+\left (480 x-480 x^2+120 x^3\right ) \log (x)+\left (576-576 x+144 x^2\right ) \log ^2(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {48 \left (-5 (-2+x)+10 (-1+x) \log (x)+12 \log ^2(x)\right )}{(2-x)^2 (5 x+12 \log (x))^2} \, dx\\ &=48 \int \frac {-5 (-2+x)+10 (-1+x) \log (x)+12 \log ^2(x)}{(2-x)^2 (5 x+12 \log (x))^2} \, dx\\ &=48 \int \left (\frac {1}{12 (-2+x)^2}-\frac {5 (12+5 x)}{12 (-2+x) (5 x+12 \log (x))^2}-\frac {5}{6 (-2+x)^2 (5 x+12 \log (x))}\right ) \, dx\\ &=\frac {4}{2-x}-20 \int \frac {12+5 x}{(-2+x) (5 x+12 \log (x))^2} \, dx-40 \int \frac {1}{(-2+x)^2 (5 x+12 \log (x))} \, dx\\ &=\frac {4}{2-x}-20 \int \left (\frac {5}{(5 x+12 \log (x))^2}+\frac {22}{(-2+x) (5 x+12 \log (x))^2}\right ) \, dx-40 \int \frac {1}{(-2+x)^2 (5 x+12 \log (x))} \, dx\\ &=\frac {4}{2-x}-40 \int \frac {1}{(-2+x)^2 (5 x+12 \log (x))} \, dx-100 \int \frac {1}{(5 x+12 \log (x))^2} \, dx-440 \int \frac {1}{(-2+x) (5 x+12 \log (x))^2} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 0.17, size = 19, normalized size = 0.86 \begin {gather*} -\frac {48 \log (x)}{(-2+x) (5 x+12 \log (x))} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.62, size = 22, normalized size = 1.00 \begin {gather*} -\frac {48 \, \log \relax (x)}{5 \, x^{2} + 12 \, {\left (x - 2\right )} \log \relax (x) - 10 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.23, size = 31, normalized size = 1.41 \begin {gather*} \frac {20 \, x}{5 \, x^{2} + 12 \, x \log \relax (x) - 10 \, x - 24 \, \log \relax (x)} - \frac {4}{x - 2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 25, normalized size = 1.14
method | result | size |
norman | \(-\frac {48 \ln \relax (x )}{12 x \ln \relax (x )+5 x^{2}-24 \ln \relax (x )-10 x}\) | \(25\) |
risch | \(-\frac {4}{x -2}+\frac {20 x}{\left (x -2\right ) \left (5 x +12 \ln \relax (x )\right )}\) | \(27\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.61, size = 22, normalized size = 1.00 \begin {gather*} -\frac {48 \, \log \relax (x)}{5 \, x^{2} + 12 \, {\left (x - 2\right )} \log \relax (x) - 10 \, x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.54, size = 19, normalized size = 0.86 \begin {gather*} -\frac {48\,\ln \relax (x)}{\left (5\,x+12\,\ln \relax (x)\right )\,\left (x-2\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.16, size = 27, normalized size = 1.23 \begin {gather*} \frac {5 x}{\frac {5 x^{2}}{4} - \frac {5 x}{2} + \left (3 x - 6\right ) \log {\relax (x )}} - \frac {4}{x - 2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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