3.33.94 \(\int \frac {x^2+e^{-e^{-4+4 x}+x^2} (4+16 e^{-4+4 x} x-8 x^2)}{x^2} \, dx\)

Optimal. Leaf size=22 \[ -\frac {4 e^{-e^{-4+4 x}+x^2}}{x}+x \]

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Rubi [B]  time = 0.17, antiderivative size = 55, normalized size of antiderivative = 2.50, number of steps used = 3, number of rules used = 2, integrand size = 41, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.049, Rules used = {14, 2288} \begin {gather*} x-\frac {4 e^{x^2-e^{4 x-4}-4} \left (2 e^{4 x} x-e^4 x^2\right )}{\left (2 e^{4 x-4}-x\right ) x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^2 + E^(-E^(-4 + 4*x) + x^2)*(4 + 16*E^(-4 + 4*x)*x - 8*x^2))/x^2,x]

[Out]

x - (4*E^(-4 - E^(-4 + 4*x) + x^2)*(2*E^(4*x)*x - E^4*x^2))/((2*E^(-4 + 4*x) - x)*x^2)

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
&&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 2288

Int[(y_.)*(F_)^(u_)*((v_) + (w_)), x_Symbol] :> With[{z = (v*y)/(Log[F]*D[u, x])}, Simp[F^u*z, x] /; EqQ[D[z,
x], w*y]] /; FreeQ[F, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \left (1-\frac {4 e^{-4-e^{-4+4 x}+x^2} \left (-e^4-4 e^{4 x} x+2 e^4 x^2\right )}{x^2}\right ) \, dx\\ &=x-4 \int \frac {e^{-4-e^{-4+4 x}+x^2} \left (-e^4-4 e^{4 x} x+2 e^4 x^2\right )}{x^2} \, dx\\ &=x-\frac {4 e^{-4-e^{-4+4 x}+x^2} \left (2 e^{4 x} x-e^4 x^2\right )}{\left (2 e^{-4+4 x}-x\right ) x^2}\\ \end {aligned} \end {gather*}

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Mathematica [A]  time = 0.12, size = 22, normalized size = 1.00 \begin {gather*} -\frac {4 e^{-e^{-4+4 x}+x^2}}{x}+x \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^2 + E^(-E^(-4 + 4*x) + x^2)*(4 + 16*E^(-4 + 4*x)*x - 8*x^2))/x^2,x]

[Out]

(-4*E^(-E^(-4 + 4*x) + x^2))/x + x

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fricas [A]  time = 0.60, size = 23, normalized size = 1.05 \begin {gather*} \frac {x^{2} - 4 \, e^{\left (x^{2} - e^{\left (4 \, x - 4\right )}\right )}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((16*x*exp(2*x-2)^2-8*x^2+4)*exp(-exp(2*x-2)^2+x^2)+x^2)/x^2,x, algorithm="fricas")

[Out]

(x^2 - 4*e^(x^2 - e^(4*x - 4)))/x

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giac [A]  time = 0.24, size = 23, normalized size = 1.05 \begin {gather*} \frac {x^{2} - 4 \, e^{\left (x^{2} - e^{\left (4 \, x - 4\right )}\right )}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((16*x*exp(2*x-2)^2-8*x^2+4)*exp(-exp(2*x-2)^2+x^2)+x^2)/x^2,x, algorithm="giac")

[Out]

(x^2 - 4*e^(x^2 - e^(4*x - 4)))/x

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maple [A]  time = 0.06, size = 21, normalized size = 0.95

method	result	size
risch	\(x -\frac {4 \,{\mathrm e}^{-{\mathrm e}^{4 x -4}+x^{2}}}{x}\)	\(21\)
norman	\(\frac {x^{2}-4 \,{\mathrm e}^{-{\mathrm e}^{4 x -4}+x^{2}}}{x}\)	\(26\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((16*x*exp(2*x-2)^2-8*x^2+4)*exp(-exp(2*x-2)^2+x^2)+x^2)/x^2,x,method=_RETURNVERBOSE)

[Out]

x-4*exp(-exp(4*x-4)+x^2)/x

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maxima [A]  time = 0.48, size = 20, normalized size = 0.91 \begin {gather*} x - \frac {4 \, e^{\left (x^{2} - e^{\left (4 \, x - 4\right )}\right )}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((16*x*exp(2*x-2)^2-8*x^2+4)*exp(-exp(2*x-2)^2+x^2)+x^2)/x^2,x, algorithm="maxima")

[Out]

x - 4*e^(x^2 - e^(4*x - 4))/x

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mupad [B]  time = 1.98, size = 20, normalized size = 0.91 \begin {gather*} x-\frac {4\,{\mathrm {e}}^{x^2}\,{\mathrm {e}}^{-{\mathrm {e}}^{4\,x}\,{\mathrm {e}}^{-4}}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((exp(x^2 - exp(4*x - 4))*(16*x*exp(4*x - 4) - 8*x^2 + 4) + x^2)/x^2,x)

[Out]

x - (4*exp(x^2)*exp(-exp(4*x)*exp(-4)))/x

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sympy [A]  time = 0.39, size = 15, normalized size = 0.68 \begin {gather*} x - \frac {4 e^{x^{2} - e^{4 x - 4}}}{x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((16*x*exp(2*x-2)**2-8*x**2+4)*exp(-exp(2*x-2)**2+x**2)+x**2)/x**2,x)

[Out]

x - 4*exp(x**2 - exp(4*x - 4))/x

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