3.41.65 1x+log(log(5)4)dx

Optimal. Leaf size=17 log(11)+log(25(x+log(log(5)4)))

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Rubi [A]  time = 0.00, antiderivative size = 10, normalized size of antiderivative = 0.59, number of steps used = 1, number of rules used = 1, integrand size = 11, number of rulesintegrand size = 0.091, Rules used = {31} log(x+log(log(5)4))

Antiderivative was successfully verified.

[In]

Int[(x + Log[Log[5]/4])^(-1),x]

[Out]

Log[x + Log[Log[5]/4]]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rubi steps

integral=log(x+log(log(5)4))

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Mathematica [A]  time = 0.00, size = 10, normalized size = 0.59 log(x+log(log(5)4))

Antiderivative was successfully verified.

[In]

Integrate[(x + Log[Log[5]/4])^(-1),x]

[Out]

Log[x + Log[Log[5]/4]]

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fricas [A]  time = 0.57, size = 8, normalized size = 0.47 log(x+log(14log(5)))

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(log(1/4*log(5))+x),x, algorithm="fricas")

[Out]

log(x + log(1/4*log(5)))

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giac [A]  time = 0.15, size = 9, normalized size = 0.53 log(|x+log(14log(5))|)

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(log(1/4*log(5))+x),x, algorithm="giac")

[Out]

log(abs(x + log(1/4*log(5))))

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maple [A]  time = 0.13, size = 9, normalized size = 0.53




method result size



default ln(ln(ln(5)4)+x) 9
norman ln(ln(ln(5)4)+x) 9
risch ln(2ln(2)+ln(ln(5))+x) 11
meijerg ln(1+xln(ln(5)4)) 13



Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(ln(1/4*ln(5))+x),x,method=_RETURNVERBOSE)

[Out]

ln(ln(1/4*ln(5))+x)

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maxima [A]  time = 0.36, size = 8, normalized size = 0.47 log(x+log(14log(5)))

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(log(1/4*log(5))+x),x, algorithm="maxima")

[Out]

log(x + log(1/4*log(5)))

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mupad [B]  time = 0.09, size = 8, normalized size = 0.47 ln(x+ln(ln(5)4))

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x + log(log(5)/4)),x)

[Out]

log(x + log(log(5)/4))

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sympy [A]  time = 0.07, size = 12, normalized size = 0.71 log(x2log(2)+log(log(5)))

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(ln(1/4*ln(5))+x),x)

[Out]

log(x - 2*log(2) + log(log(5)))

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