Optimal. Leaf size=26 \[ \frac {2}{5} x \left (x+\frac {3}{8 x \left (-3+x+x^2\right ) \log (x)}\right ) \]
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Rubi [F] time = 0.28, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {9-3 x-3 x^2+\left (-3 x-6 x^2\right ) \log (x)+\left (144 x^2-96 x^3-80 x^4+32 x^5+16 x^6\right ) \log ^2(x)}{\left (180 x-120 x^2-100 x^3+40 x^4+20 x^5\right ) \log ^2(x)} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {1}{20} \left (16 x-\frac {3}{x \left (-3+x+x^2\right ) \log ^2(x)}-\frac {3 (1+2 x)}{\left (-3+x+x^2\right )^2 \log (x)}\right ) \, dx\\ &=\frac {1}{20} \int \left (16 x-\frac {3}{x \left (-3+x+x^2\right ) \log ^2(x)}-\frac {3 (1+2 x)}{\left (-3+x+x^2\right )^2 \log (x)}\right ) \, dx\\ &=\frac {2 x^2}{5}-\frac {3}{20} \int \frac {1}{x \left (-3+x+x^2\right ) \log ^2(x)} \, dx-\frac {3}{20} \int \frac {1+2 x}{\left (-3+x+x^2\right )^2 \log (x)} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 1.32, size = 24, normalized size = 0.92 \begin {gather*} \frac {1}{20} \left (8 x^2+\frac {3}{\left (-3+x+x^2\right ) \log (x)}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.60, size = 32, normalized size = 1.23 \begin {gather*} \frac {8 \, {\left (x^{4} + x^{3} - 3 \, x^{2}\right )} \log \relax (x) + 3}{20 \, {\left (x^{2} + x - 3\right )} \log \relax (x)} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.22, size = 25, normalized size = 0.96 \begin {gather*} \frac {2}{5} \, x^{2} + \frac {3}{20 \, {\left (x^{2} \log \relax (x) + x \log \relax (x) - 3 \, \log \relax (x)\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 21, normalized size = 0.81
method | result | size |
risch | \(\frac {2 x^{2}}{5}+\frac {3}{20 \left (x^{2}+x -3\right ) \ln \relax (x )}\) | \(21\) |
norman | \(\frac {\frac {3}{20}-\frac {18 \ln \relax (x )}{5}+\frac {6 x \ln \relax (x )}{5}+\frac {2 x^{3} \ln \relax (x )}{5}+\frac {2 x^{4} \ln \relax (x )}{5}}{\left (x^{2}+x -3\right ) \ln \relax (x )}\) | \(39\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.39, size = 32, normalized size = 1.23 \begin {gather*} \frac {8 \, {\left (x^{4} + x^{3} - 3 \, x^{2}\right )} \log \relax (x) + 3}{20 \, {\left (x^{2} + x - 3\right )} \log \relax (x)} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.65, size = 40, normalized size = 1.54 \begin {gather*} \frac {\frac {2\,x^4}{5}+\frac {2\,x^3}{5}-\frac {6\,x^2}{5}}{x^2+x-3}+\frac {3}{20\,\ln \relax (x)\,\left (x^2+x-3\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.14, size = 20, normalized size = 0.77 \begin {gather*} \frac {2 x^{2}}{5} + \frac {3}{\left (20 x^{2} + 20 x - 60\right ) \log {\relax (x )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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