Optimal. Leaf size=25 \[ 3+x-\frac {1+\log (5)}{x}+\frac {x}{\log \left (\frac {3 (13+x)}{x}\right )} \]
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Rubi [F] time = 0.42, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {13 x^2+\left (13 x^2+x^3\right ) \log \left (\frac {39+3 x}{x}\right )+\left (13+x+13 x^2+x^3+(13+x) \log (5)\right ) \log ^2\left (\frac {39+3 x}{x}\right )}{\left (13 x^2+x^3\right ) \log ^2\left (\frac {39+3 x}{x}\right )} \, dx \end {gather*}
Verification is not applicable to the result.
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Rubi steps
\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {13 x^2+\left (13 x^2+x^3\right ) \log \left (\frac {39+3 x}{x}\right )+\left (13+x+13 x^2+x^3+(13+x) \log (5)\right ) \log ^2\left (\frac {39+3 x}{x}\right )}{x^2 (13+x) \log ^2\left (\frac {39+3 x}{x}\right )} \, dx\\ &=\int \left (\frac {1+x^2+\log (5)}{x^2}+\frac {13}{(13+x) \log ^2\left (3+\frac {39}{x}\right )}+\frac {1}{\log \left (3+\frac {39}{x}\right )}\right ) \, dx\\ &=13 \int \frac {1}{(13+x) \log ^2\left (3+\frac {39}{x}\right )} \, dx+\int \frac {1+x^2+\log (5)}{x^2} \, dx+\int \frac {1}{\log \left (3+\frac {39}{x}\right )} \, dx\\ &=13 \int \frac {1}{(13+x) \log ^2\left (3+\frac {39}{x}\right )} \, dx+\int \left (1+\frac {1+\log (5)}{x^2}\right ) \, dx+\int \frac {1}{\log \left (3+\frac {39}{x}\right )} \, dx\\ &=x-\frac {1+\log (5)}{x}+13 \int \frac {1}{(13+x) \log ^2\left (3+\frac {39}{x}\right )} \, dx+\int \frac {1}{\log \left (3+\frac {39}{x}\right )} \, dx\\ \end {aligned} \end {gather*}
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Mathematica [A] time = 5.46, size = 24, normalized size = 0.96 \begin {gather*} x+\frac {-1-\log (5)}{x}+\frac {x}{\log \left (3+\frac {39}{x}\right )} \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.85, size = 38, normalized size = 1.52 \begin {gather*} \frac {x^{2} + {\left (x^{2} - \log \relax (5) - 1\right )} \log \left (\frac {3 \, {\left (x + 13\right )}}{x}\right )}{x \log \left (\frac {3 \, {\left (x + 13\right )}}{x}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.35, size = 58, normalized size = 2.32 \begin {gather*} -\frac {{\left (x + 13\right )} {\left (\log \relax (5) + 1\right )}}{13 \, x} + \frac {13}{\frac {{\left (x + 13\right )} \log \left (\frac {3 \, {\left (x + 13\right )}}{x}\right )}{x} - \log \left (\frac {3 \, {\left (x + 13\right )}}{x}\right )} + \frac {13}{\frac {x + 13}{x} - 1} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.20, size = 30, normalized size = 1.20
method | result | size |
risch | \(-\frac {-x^{2}+\ln \relax (5)+1}{x}+\frac {x}{\ln \left (\frac {3 x +39}{x}\right )}\) | \(30\) |
norman | \(\frac {x^{2}+x^{2} \ln \left (\frac {3 x +39}{x}\right )+\left (-\ln \relax (5)-1\right ) \ln \left (\frac {3 x +39}{x}\right )}{x \ln \left (\frac {3 x +39}{x}\right )}\) | \(52\) |
derivativedivides | \(-\frac {\left (\frac {\ln \left (1+\frac {13}{x}\right )}{x^{2}}-1+\frac {\ln \relax (3)}{x^{2}}-\ln \left (1+\frac {13}{x}\right )-\ln \relax (3)\right ) x}{\ln \relax (3)+\ln \left (1+\frac {13}{x}\right )}-\frac {\ln \relax (5)}{x}\) | \(59\) |
default | \(-\frac {\left (\frac {\ln \left (1+\frac {13}{x}\right )}{x^{2}}-1+\frac {\ln \relax (3)}{x^{2}}-\ln \left (1+\frac {13}{x}\right )-\ln \relax (3)\right ) x}{\ln \relax (3)+\ln \left (1+\frac {13}{x}\right )}-\frac {\ln \relax (5)}{x}\) | \(59\) |
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.54, size = 224, normalized size = 8.96 \begin {gather*} \frac {2}{13} \, {\left ({\left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right )} \log \left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right ) - \log \left (\frac {39}{x} + 3\right ) \log \left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right ) - \log \left (x + 13\right ) + \log \relax (x)\right )} \log \relax (5) - \frac {1}{13} \, {\left (\frac {13}{x} - \log \left (x + 13\right ) + \log \relax (x)\right )} \log \relax (5) + \frac {\log \relax (5) \log \left (\frac {39}{x} + 3\right )^{2}}{13 \, {\left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right )}} + \frac {2}{13} \, {\left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right )} \log \left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right ) - \frac {2}{13} \, \log \left (\frac {39}{x} + 3\right ) \log \left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right ) + \frac {\log \left (\frac {39}{x} + 3\right )^{2}}{13 \, {\left (\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)\right )}} + \frac {x {\left (\log \relax (3) + 1\right )} + x \log \left (x + 13\right ) - x \log \relax (x)}{\log \relax (3) + \log \left (x + 13\right ) - \log \relax (x)} - \frac {1}{x} - \frac {1}{13} \, \log \left (x + 13\right ) + \frac {1}{13} \, \log \relax (x) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.95, size = 111, normalized size = 4.44 \begin {gather*} \frac {x^5+\left (\frac {2\,\ln \relax (5)}{13}+\frac {340}{13}\right )\,x^4+\left (\ln \left (125\right )+172\right )\,x^3+\left (-169\,\ln \relax (5)-169\right )\,x}{x^4+26\,x^3+169\,x^2}+\frac {x^5+26\,x^4+169\,x^3}{169\,x^2\,\ln \left (\frac {3\,x+39}{x}\right )+26\,x^3\,\ln \left (\frac {3\,x+39}{x}\right )+x^4\,\ln \left (\frac {3\,x+39}{x}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.16, size = 19, normalized size = 0.76 \begin {gather*} x + \frac {x}{\log {\left (\frac {3 x + 39}{x} \right )}} + \frac {- \log {\relax (5 )} - 1}{x} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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