3.80.8 \(\int \frac {4 x+x^2-4 (i \pi +\log (3))+(4 x+x^2) \log (2) (i \pi +\log (3))-x (i \pi +\log (3)) \log (x)+(i \pi -x+\log (3)-x \log (2) (i \pi +\log (3))) \log (3 x)+(-x-x \log (2) (i \pi +\log (3))+(i \pi +\log (3)) \log (x)) \log (x+x \log (2) (i \pi +\log (3))-(i \pi +\log (3)) \log (x))}{-x^2-x^2 \log (2) (i \pi +\log (3))+x (i \pi +\log (3)) \log (x)} \, dx\)

Optimal. Leaf size=32 \[ -x+(-4+\log (3 x)) \log (x+(i \pi +\log (3)) (x \log (2)-\log (x))) \]

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Rubi [F]  time = 3.63, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {4 x+x^2-4 (i \pi +\log (3))+\left (4 x+x^2\right ) \log (2) (i \pi +\log (3))-x (i \pi +\log (3)) \log (x)+(i \pi -x+\log (3)-x \log (2) (i \pi +\log (3))) \log (3 x)+(-x-x \log (2) (i \pi +\log (3))+(i \pi +\log (3)) \log (x)) \log (x+x \log (2) (i \pi +\log (3))-(i \pi +\log (3)) \log (x))}{-x^2-x^2 \log (2) (i \pi +\log (3))+x (i \pi +\log (3)) \log (x)} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(4*x + x^2 - 4*(I*Pi + Log[3]) + (4*x + x^2)*Log[2]*(I*Pi + Log[3]) - x*(I*Pi + Log[3])*Log[x] + (I*Pi - x
+ Log[3] - x*Log[2]*(I*Pi + Log[3]))*Log[3*x] + (-x - x*Log[2]*(I*Pi + Log[3]) + (I*Pi + Log[3])*Log[x])*Log[
x + x*Log[2]*(I*Pi + Log[3]) - (I*Pi + Log[3])*Log[x]])/(-x^2 - x^2*Log[2]*(I*Pi + Log[3]) + x*(I*Pi + Log[3])
*Log[x]),x]

[Out]

-x + (4*I)*Defer[Int][((-I)*x*(1 + Log[2]*(I*Pi + Log[3])) - Pi*(1 - (I*Log[3])/Pi)*Log[x])^(-1), x] + I*Defer
[Int][x/((-I)*x*(1 + Log[2]*(I*Pi + Log[3])) - Pi*(1 - (I*Log[3])/Pi)*Log[x]), x] + 4*Log[2]*(Pi - I*Log[3])*D
efer[Int][(I*x*(1 + Log[2]*(I*Pi + Log[3])) + Pi*(1 - (I*Log[3])/Pi)*Log[x])^(-1), x] - 4*(Pi - I*Log[3])*Defe
r[Int][1/(x*(I*x*(1 + Log[2]*(I*Pi + Log[3])) + Pi*(1 - (I*Log[3])/Pi)*Log[x])), x] + Log[2]*(Pi - I*Log[3])*D
efer[Int][x/(I*x*(1 + Log[2]*(I*Pi + Log[3])) + Pi*(1 - (I*Log[3])/Pi)*Log[x]), x] - (Pi*Log[2] - I*(1 + Log[2
]*Log[3]))*Defer[Int][x/(I*x*(1 + Log[2]*(I*Pi + Log[3])) + Pi*(1 - (I*Log[3])/Pi)*Log[x]), x] - I*(1 + Log[2]
*(I*Pi + Log[3]))*Defer[Int][Log[3*x]/((-I)*x*(1 + Log[2]*(I*Pi + Log[3])) - Pi*(1 - (I*Log[3])/Pi)*Log[x]), x
] + (Pi - I*Log[3])*Defer[Int][Log[3*x]/(x*(I*x*(1 + Log[2]*(I*Pi + Log[3])) + Pi*(1 - (I*Log[3])/Pi)*Log[x]))
, x] + Defer[Int][Log[x*(1 + Log[2]*(I*Pi + Log[3])) - (I*Pi + Log[3])*Log[x]]/x, x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {4 x+x^2-4 (i \pi +\log (3))+\left (4 x+x^2\right ) \log (2) (i \pi +\log (3))-x (i \pi +\log (3)) \log (x)+(i \pi -x+\log (3)-x \log (2) (i \pi +\log (3))) \log (3 x)+(-x-x \log (2) (i \pi +\log (3))+(i \pi +\log (3)) \log (x)) \log (x+x \log (2) (i \pi +\log (3))-(i \pi +\log (3)) \log (x))}{x^2 (-1-\log (2) (i \pi +\log (3)))+x (i \pi +\log (3)) \log (x)} \, dx\\ &=\int \frac {4 x+x^2-4 (i \pi +\log (3))+\left (4 x+x^2\right ) \log (2) (i \pi +\log (3))-x (i \pi +\log (3)) \log (x)+(i \pi -x+\log (3)-x \log (2) (i \pi +\log (3))) \log (3 x)+(-x-x \log (2) (i \pi +\log (3))+(i \pi +\log (3)) \log (x)) \log (x+x \log (2) (i \pi +\log (3))-(i \pi +\log (3)) \log (x))}{x (x (-1-\log (2) (i \pi +\log (3)))+(i \pi +\log (3)) \log (x))} \, dx\\ &=\int \left (\frac {4 i}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {i x}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {(4+x) \log (2) (\pi -i \log (3))}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {4 (-\pi +i \log (3))}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )}+\frac {(-\pi +i \log (3)) \log (x)}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {(\pi -i \log (3)-x (\pi \log (2)-i (1+\log (2) \log (3)))) \log (3 x)}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )}+\frac {\log (x (1+\log (2) (i \pi +\log (3)))-(i \pi +\log (3)) \log (x))}{x}\right ) \, dx\\ &=i \int \frac {x}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+4 i \int \frac {1}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx-(4 (\pi -i \log (3))) \int \frac {1}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )} \, dx+(\log (2) (\pi -i \log (3))) \int \frac {4+x}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+(-\pi +i \log (3)) \int \frac {\log (x)}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+\int \frac {(\pi -i \log (3)-x (\pi \log (2)-i (1+\log (2) \log (3)))) \log (3 x)}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )} \, dx+\int \frac {\log (x (1+\log (2) (i \pi +\log (3)))-(i \pi +\log (3)) \log (x))}{x} \, dx\\ &=i \int \frac {x}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+4 i \int \frac {1}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx-(4 (\pi -i \log (3))) \int \frac {1}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )} \, dx+(\log (2) (\pi -i \log (3))) \int \left (\frac {4}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {x}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}\right ) \, dx+(-\pi +i \log (3)) \int \left (\frac {1}{\pi -i \log (3)}+\frac {x (\pi \log (2)-i (1+\log (2) \log (3)))}{(\pi -i \log (3)) \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )}\right ) \, dx+\int \left (-\frac {i (1+\log (2) (i \pi +\log (3))) \log (3 x)}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)}+\frac {(\pi -i \log (3)) \log (3 x)}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )}\right ) \, dx+\int \frac {\log (x (1+\log (2) (i \pi +\log (3)))-(i \pi +\log (3)) \log (x))}{x} \, dx\\ &=-x+i \int \frac {x}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+4 i \int \frac {1}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+(\pi -i \log (3)) \int \frac {\log (3 x)}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )} \, dx-(4 (\pi -i \log (3))) \int \frac {1}{x \left (i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)\right )} \, dx+(\log (2) (\pi -i \log (3))) \int \frac {x}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+(4 \log (2) (\pi -i \log (3))) \int \frac {1}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx-(i (1+\log (2) (i \pi +\log (3)))) \int \frac {\log (3 x)}{-i x (1+\log (2) (i \pi +\log (3)))-\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+(-\pi \log (2)+i (1+\log (2) \log (3))) \int \frac {x}{i x (1+\log (2) (i \pi +\log (3)))+\pi \left (1-\frac {i \log (3)}{\pi }\right ) \log (x)} \, dx+\int \frac {\log (x (1+\log (2) (i \pi +\log (3)))-(i \pi +\log (3)) \log (x))}{x} \, dx\\ \end {aligned} \end {gather*}

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Mathematica [B]  time = 0.22, size = 153, normalized size = 4.78 \begin {gather*} -x+i \tan ^{-1}\left (\frac {\pi (-x \log (2)+\log (x))}{x+x \log (2) \log (3)-\log (3) \log (x)}\right ) (4+\log (x)-\log (3 x))+\log (x) \log (x+x \log (2) (i \pi +\log (3))-(i \pi +\log (3)) \log (x))-\frac {1}{2} (4+\log (x)-\log (3 x)) \log \left (x^2 \left (1+\pi ^2 \log ^2(2)+\log ^2(2) \log ^2(3)+\log (3) \log (4)\right )-x \left (\pi ^2 \log (4)+\log ^2(3) \log (4)+\log (9)\right ) \log (x)+\left (\pi ^2+\log ^2(3)\right ) \log ^2(x)\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(4*x + x^2 - 4*(I*Pi + Log[3]) + (4*x + x^2)*Log[2]*(I*Pi + Log[3]) - x*(I*Pi + Log[3])*Log[x] + (I*
Pi - x + Log[3] - x*Log[2]*(I*Pi + Log[3]))*Log[3*x] + (-x - x*Log[2]*(I*Pi + Log[3]) + (I*Pi + Log[3])*Log[x]
)*Log[x + x*Log[2]*(I*Pi + Log[3]) - (I*Pi + Log[3])*Log[x]])/(-x^2 - x^2*Log[2]*(I*Pi + Log[3]) + x*(I*Pi + L
og[3])*Log[x]),x]

[Out]

-x + I*ArcTan[(Pi*(-(x*Log[2]) + Log[x]))/(x + x*Log[2]*Log[3] - Log[3]*Log[x])]*(4 + Log[x] - Log[3*x]) + Log
[x]*Log[x + x*Log[2]*(I*Pi + Log[3]) - (I*Pi + Log[3])*Log[x]] - ((4 + Log[x] - Log[3*x])*Log[x^2*(1 + Pi^2*Lo
g[2]^2 + Log[2]^2*Log[3]^2 + Log[3]*Log[4]) - x*(Pi^2*Log[4] + Log[3]^2*Log[4] + Log[9])*Log[x] + (Pi^2 + Log[
3]^2)*Log[x]^2])/2

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fricas [A]  time = 1.57, size = 37, normalized size = 1.16 \begin {gather*} {\left (\log \relax (3) + \log \relax (x) - 4\right )} \log \left (i \, \pi x \log \relax (2) + x \log \relax (3) \log \relax (2) + {\left (-i \, \pi - \log \relax (3)\right )} \log \relax (x) + x\right ) - x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((log(3)+I*pi)*log(x)-x*(log(3)+I*pi)*log(2)-x)*log(-(log(3)+I*pi)*log(x)+x*(log(3)+I*pi)*log(2)+x)
+(-x*(log(3)+I*pi)*log(2)+log(3)+I*pi-x)*log(3*x)-x*(log(3)+I*pi)*log(x)+(x^2+4*x)*(log(3)+I*pi)*log(2)-4*log(
3)-4*I*pi+x^2+4*x)/(x*(log(3)+I*pi)*log(x)-x^2*(log(3)+I*pi)*log(2)-x^2),x, algorithm="fricas")

[Out]

(log(3) + log(x) - 4)*log(I*pi*x*log(2) + x*log(3)*log(2) + (-I*pi - log(3))*log(x) + x) - x

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giac [B]  time = 0.33, size = 66, normalized size = 2.06 \begin {gather*} {\left (\log \relax (3) - 4\right )} \log \left (\pi x \log \relax (2) - i \, x \log \relax (3) \log \relax (2) - \pi \log \relax (x) + i \, \log \relax (3) \log \relax (x) - i \, x\right ) + \log \left (i \, \pi x \log \relax (2) + x \log \relax (3) \log \relax (2) - i \, \pi \log \relax (x) - \log \relax (3) \log \relax (x) + x\right ) \log \relax (x) - x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((log(3)+I*pi)*log(x)-x*(log(3)+I*pi)*log(2)-x)*log(-(log(3)+I*pi)*log(x)+x*(log(3)+I*pi)*log(2)+x)
+(-x*(log(3)+I*pi)*log(2)+log(3)+I*pi-x)*log(3*x)-x*(log(3)+I*pi)*log(x)+(x^2+4*x)*(log(3)+I*pi)*log(2)-4*log(
3)-4*I*pi+x^2+4*x)/(x*(log(3)+I*pi)*log(x)-x^2*(log(3)+I*pi)*log(2)-x^2),x, algorithm="giac")

[Out]

(log(3) - 4)*log(pi*x*log(2) - I*x*log(3)*log(2) - pi*log(x) + I*log(3)*log(x) - I*x) + log(I*pi*x*log(2) + x*
log(3)*log(2) - I*pi*log(x) - log(3)*log(x) + x)*log(x) - x

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maple [B]  time = 0.20, size = 98, normalized size = 3.06

method	result	size
risch	\(\ln \relax (x ) \ln \left (-\left (\ln \relax (3)+i \pi \right ) \ln \relax (x )+x \left (\ln \relax (3)+i \pi \right ) \ln \relax (2)+x \right )-x +\ln \relax (3) \ln \left (\ln \relax (x )-\frac {x \left (-i \ln \relax (2) \ln \relax (3)-i+\pi \ln \relax (2)\right )}{\pi -i \ln \relax (3)}\right )-4 \ln \left (\ln \relax (x )-\frac {x \left (-i \ln \relax (2) \ln \relax (3)-i+\pi \ln \relax (2)\right )}{\pi -i \ln \relax (3)}\right )\)	\(98\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((((ln(3)+I*Pi)*ln(x)-x*(ln(3)+I*Pi)*ln(2)-x)*ln(-(ln(3)+I*Pi)*ln(x)+x*(ln(3)+I*Pi)*ln(2)+x)+(-x*(ln(3)+I*P
i)*ln(2)+ln(3)+I*Pi-x)*ln(3*x)-x*(ln(3)+I*Pi)*ln(x)+(x^2+4*x)*(ln(3)+I*Pi)*ln(2)-4*ln(3)-4*I*Pi+x^2+4*x)/(x*(l
n(3)+I*Pi)*ln(x)-x^2*(ln(3)+I*Pi)*ln(2)-x^2),x,method=_RETURNVERBOSE)

[Out]

ln(x)*ln(-(ln(3)+I*Pi)*ln(x)+x*(ln(3)+I*Pi)*ln(2)+x)-x+ln(3)*ln(ln(x)-x*(-I*ln(2)*ln(3)-I+Pi*ln(2))/(Pi-I*ln(3
)))-4*ln(ln(x)-x*(-I*ln(2)*ln(3)-I+Pi*ln(2))/(Pi-I*ln(3)))

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maxima [A]  time = 0.57, size = 38, normalized size = 1.19 \begin {gather*} {\left (\log \relax (3) + \log \relax (x) - 4\right )} \log \left ({\left (i \, \pi \log \relax (2) + \log \relax (3) \log \relax (2) + 1\right )} x + {\left (-i \, \pi - \log \relax (3)\right )} \log \relax (x)\right ) - x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((log(3)+I*pi)*log(x)-x*(log(3)+I*pi)*log(2)-x)*log(-(log(3)+I*pi)*log(x)+x*(log(3)+I*pi)*log(2)+x)
+(-x*(log(3)+I*pi)*log(2)+log(3)+I*pi-x)*log(3*x)-x*(log(3)+I*pi)*log(x)+(x^2+4*x)*(log(3)+I*pi)*log(2)-4*log(
3)-4*I*pi+x^2+4*x)/(x*(log(3)+I*pi)*log(x)-x^2*(log(3)+I*pi)*log(2)-x^2),x, algorithm="maxima")

[Out]

(log(3) + log(x) - 4)*log((I*pi*log(2) + log(3)*log(2) + 1)*x + (-I*pi - log(3))*log(x)) - x

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {\Pi \,4{}\mathrm {i}-4\,x+4\,\ln \relax (3)+\ln \left (x-\ln \relax (x)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )+x\,\ln \relax (2)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )\right )\,\left (x-\ln \relax (x)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )+x\,\ln \relax (2)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )\right )-\ln \left (3\,x\right )\,\left (\Pi \,1{}\mathrm {i}-x+\ln \relax (3)-x\,\ln \relax (2)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )\right )-x^2+x\,\ln \relax (x)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )-\ln \relax (2)\,\left (x^2+4\,x\right )\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )}{x^2+x^2\,\ln \relax (2)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )-x\,\ln \relax (x)\,\left (\ln \relax (3)+\Pi \,1{}\mathrm {i}\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((Pi*4i - 4*x + 4*log(3) + log(x - log(x)*(Pi*1i + log(3)) + x*log(2)*(Pi*1i + log(3)))*(x - log(x)*(Pi*1i
+ log(3)) + x*log(2)*(Pi*1i + log(3))) - log(3*x)*(Pi*1i - x + log(3) - x*log(2)*(Pi*1i + log(3))) - x^2 + x*l
og(x)*(Pi*1i + log(3)) - log(2)*(4*x + x^2)*(Pi*1i + log(3)))/(x^2 + x^2*log(2)*(Pi*1i + log(3)) - x*log(x)*(P
i*1i + log(3))),x)

[Out]

int((Pi*4i - 4*x + 4*log(3) + log(x - log(x)*(Pi*1i + log(3)) + x*log(2)*(Pi*1i + log(3)))*(x - log(x)*(Pi*1i
+ log(3)) + x*log(2)*(Pi*1i + log(3))) - log(3*x)*(Pi*1i - x + log(3) - x*log(2)*(Pi*1i + log(3))) - x^2 + x*l
og(x)*(Pi*1i + log(3)) - log(2)*(4*x + x^2)*(Pi*1i + log(3)))/(x^2 + x^2*log(2)*(Pi*1i + log(3)) - x*log(x)*(P
i*1i + log(3))), x)

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sympy [B]  time = 84.96, size = 75, normalized size = 2.34 \begin {gather*} - x + \log {\relax (x )} \log {\left (x \log {\relax (2 )} \log {\relax (3 )} + x + i \pi x \log {\relax (2 )} - \log {\relax (3 )} \log {\relax (x )} - i \pi \log {\relax (x )} \right )} + \left (-4 + \log {\relax (3 )}\right ) \log {\left (\frac {- x - x \log {\relax (2 )} \log {\relax (3 )} - i \pi x \log {\relax (2 )}}{\log {\relax (3 )} + i \pi } + \log {\relax (x )} \right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((((ln(3)+I*pi)*ln(x)-x*(ln(3)+I*pi)*ln(2)-x)*ln(-(ln(3)+I*pi)*ln(x)+x*(ln(3)+I*pi)*ln(2)+x)+(-x*(ln(
3)+I*pi)*ln(2)+ln(3)+I*pi-x)*ln(3*x)-x*(ln(3)+I*pi)*ln(x)+(x**2+4*x)*(ln(3)+I*pi)*ln(2)-4*ln(3)-4*I*pi+x**2+4*
x)/(x*(ln(3)+I*pi)*ln(x)-x**2*(ln(3)+I*pi)*ln(2)-x**2),x)

[Out]

-x + log(x)*log(x*log(2)*log(3) + x + I*pi*x*log(2) - log(3)*log(x) - I*pi*log(x)) + (-4 + log(3))*log((-x - x
*log(2)*log(3) - I*pi*x*log(2))/(log(3) + I*pi) + log(x))

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