3.10.40 \(\int \frac {e^{3 x} (8-72 x)+e^{4 x} (36 x-108 x^2+36 x^3)+(24 e^{3 x} x+e^{4 x} (-24 x+72 x^2-24 x^3)) \log (x)+e^{4 x} (4 x-12 x^2+4 x^3) \log ^2(x)}{16 x+e^x (48 x^2-24 x^3)+e^{2 x} (36 x^3-36 x^4+9 x^5)+(e^x (-16 x^2+8 x^3)+e^{2 x} (-24 x^3+24 x^4-6 x^5)) \log (x)+e^{2 x} (4 x^3-4 x^4+x^5) \log ^2(x)} \, dx\)

Optimal. Leaf size=31 \[ \frac {2 e^{2 x}}{x \left (-2+x+\frac {4 e^{-x}}{x (-3+\log (x))}\right )} \]

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Rubi [F]  time = 40.70, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {e^{3 x} (8-72 x)+e^{4 x} \left (36 x-108 x^2+36 x^3\right )+\left (24 e^{3 x} x+e^{4 x} \left (-24 x+72 x^2-24 x^3\right )\right ) \log (x)+e^{4 x} \left (4 x-12 x^2+4 x^3\right ) \log ^2(x)}{16 x+e^x \left (48 x^2-24 x^3\right )+e^{2 x} \left (36 x^3-36 x^4+9 x^5\right )+\left (e^x \left (-16 x^2+8 x^3\right )+e^{2 x} \left (-24 x^3+24 x^4-6 x^5\right )\right ) \log (x)+e^{2 x} \left (4 x^3-4 x^4+x^5\right ) \log ^2(x)} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(E^(3*x)*(8 - 72*x) + E^(4*x)*(36*x - 108*x^2 + 36*x^3) + (24*E^(3*x)*x + E^(4*x)*(-24*x + 72*x^2 - 24*x^3
))*Log[x] + E^(4*x)*(4*x - 12*x^2 + 4*x^3)*Log[x]^2)/(16*x + E^x*(48*x^2 - 24*x^3) + E^(2*x)*(36*x^3 - 36*x^4
+ 9*x^5) + (E^x*(-16*x^2 + 8*x^3) + E^(2*x)*(-24*x^3 + 24*x^4 - 6*x^5))*Log[x] + E^(2*x)*(4*x^3 - 4*x^4 + x^5)
*Log[x]^2),x]

[Out]

-24*Defer[Int][E^(3*x)/(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])^2, x] - 24*Defer[Int][E^(3*x)/((-2 + x)*
(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])^2), x] - 16*Defer[Int][E^(3*x)/(x*(4 - 3*E^x*(-2 + x)*x + E^x*(
-2 + x)*x*Log[x])^2), x] + 8*Defer[Int][(E^(3*x)*Log[x])/(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])^2, x]
+ 8*Defer[Int][(E^(3*x)*Log[x])/((-2 + x)*(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])^2), x] + 8*Defer[Int]
[(E^(3*x)*Log[x])/(x*(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])^2), x] - 12*Defer[Int][E^(3*x)/(4 - 3*E^x*
(-2 + x)*x + E^x*(-2 + x)*x*Log[x]), x] + 6*Defer[Int][E^(3*x)/((-2 + x)*(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*
x*Log[x])), x] + 6*Defer[Int][E^(3*x)/(x*(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])), x] + 4*Defer[Int][(E
^(3*x)*Log[x])/(4 - 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x]), x] - 2*Defer[Int][(E^(3*x)*Log[x])/((-2 + x)*(4
- 3*E^x*(-2 + x)*x + E^x*(-2 + x)*x*Log[x])), x] - 2*Defer[Int][(E^(3*x)*Log[x])/(x*(4 - 3*E^x*(-2 + x)*x + E
^x*(-2 + x)*x*Log[x])), x]

Rubi steps

\begin {gather*} \begin {aligned} \text {integral} &=\int \frac {4 e^{3 x} \left (2+9 \left (-2+e^x\right ) x-27 e^x x^2+9 e^x x^3-6 x \left (-1+e^x \left (1-3 x+x^2\right )\right ) \log (x)+e^x x \left (1-3 x+x^2\right ) \log ^2(x)\right )}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx\\ &=4 \int \frac {e^{3 x} \left (2+9 \left (-2+e^x\right ) x-27 e^x x^2+9 e^x x^3-6 x \left (-1+e^x \left (1-3 x+x^2\right )\right ) \log (x)+e^x x \left (1-3 x+x^2\right ) \log ^2(x)\right )}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx\\ &=4 \int \left (\frac {2 e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{(-2+x) x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} \left (1-3 x+x^2\right ) (-3+\log (x))}{(-2+x) x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}\right ) \, dx\\ &=4 \int \frac {e^{3 x} \left (1-3 x+x^2\right ) (-3+\log (x))}{(-2+x) x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx+8 \int \frac {e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{(-2+x) x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx\\ &=4 \int \left (\frac {e^{3 x} (-3+\log (x))}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)}-\frac {e^{3 x} (-3+\log (x))}{2 (-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}-\frac {e^{3 x} (-3+\log (x))}{2 x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}\right ) \, dx+8 \int \left (\frac {e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{2 (-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}-\frac {e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{2 x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx\\ &=-\left (2 \int \frac {e^{3 x} (-3+\log (x))}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx\right )-2 \int \frac {e^{3 x} (-3+\log (x))}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx+4 \int \frac {e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-4 \int \frac {e^{3 x} \left (4+x-3 x^2-2 \log (x)+x^2 \log (x)\right )}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} (-3+\log (x))}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)} \, dx\\ &=-\left (2 \int \frac {e^{3 x} (-3+\log (x))}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx\right )-2 \int \left (-\frac {3 e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}+\frac {e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}\right ) \, dx+4 \int \frac {e^{3 x} (-3+\log (x))}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx-4 \int \frac {e^{3 x} \left (4+x-3 x^2+\left (-2+x^2\right ) \log (x)\right )}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+4 \int \left (\frac {4 e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} x}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}-\frac {3 e^{3 x} x^2}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}-\frac {2 e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} x^2 \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx\\ &=-\left (2 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx\right )-2 \int \left (-\frac {3 e^{3 x}}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}+\frac {e^{3 x} \log (x)}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )}\right ) \, dx+4 \int \frac {e^{3 x} x}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} x^2 \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-4 \int \left (\frac {e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {4 e^{3 x}}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}-\frac {3 e^{3 x} x}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}-\frac {2 e^{3 x} \log (x)}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} x \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx+4 \int \left (-\frac {3 e^{3 x}}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)}+\frac {e^{3 x} \log (x)}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)}\right ) \, dx+6 \int \frac {e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx-8 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x} x^2}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+16 \int \frac {e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx\\ &=-\left (2 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx\right )-2 \int \frac {e^{3 x} \log (x)}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx+4 \int \frac {e^{3 x} x}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} x^2 \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-4 \int \frac {e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-4 \int \frac {e^{3 x} x \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} \log (x)}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)} \, dx+6 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+6 \int \frac {e^{3 x}}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )} \, dx-8 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x} x^2}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+12 \int \frac {e^{3 x} x}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x}}{4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)} \, dx+16 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-16 \int \frac {e^{3 x}}{x \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx\\ &=-\left (2 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx\right )-2 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx-4 \int \frac {e^{3 x}}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-4 \int \frac {e^{3 x} x \log (x)}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} \log (x)}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx+4 \int \left (\frac {e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {2 e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx+4 \int \left (\frac {2 e^{3 x} \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {4 e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} x \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx+6 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+6 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx-8 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+12 \int \frac {e^{3 x} x}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x}}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx-12 \int \left (\frac {2 e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {4 e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}+\frac {e^{3 x} x}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2}\right ) \, dx+16 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-16 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx\\ &=-\left (2 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx\right )-2 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx-4 \int \frac {e^{3 x}}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-4 \int \frac {e^{3 x} x \log (x)}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} \log (x)}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx+4 \int \frac {e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+4 \int \frac {e^{3 x} x \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+6 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+6 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx-8 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+12 \int \frac {e^{3 x} x}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x}}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx-12 \int \frac {e^{3 x} x}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx+16 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-16 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+16 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-24 \int \frac {e^{3 x}}{\left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx-48 \int \frac {e^{3 x}}{(-2+x) \left (4+6 e^x x-3 e^x x^2-2 e^x x \log (x)+e^x x^2 \log (x)\right )^2} \, dx\\ &=-\left (2 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx\right )-2 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+4 \int \frac {e^{3 x} \log (x)}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx+6 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+6 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )} \, dx+8 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-8 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+8 \int \frac {e^{3 x} \log (x)}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-12 \int \frac {e^{3 x}}{4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)} \, dx+16 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-16 \int \frac {e^{3 x}}{x \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx+16 \int \frac {e^{3 x} \log (x)}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-24 \int \frac {e^{3 x}}{\left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx-48 \int \frac {e^{3 x}}{(-2+x) \left (4-3 e^x (-2+x) x+e^x (-2+x) x \log (x)\right )^2} \, dx\\ \end {aligned} \end {gather*}

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Mathematica [A]  time = 0.13, size = 35, normalized size = 1.13 \begin {gather*} \frac {4 e^{3 x} (-3+\log (x))}{8-6 e^x (-2+x) x+2 e^x (-2+x) x \log (x)} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(E^(3*x)*(8 - 72*x) + E^(4*x)*(36*x - 108*x^2 + 36*x^3) + (24*E^(3*x)*x + E^(4*x)*(-24*x + 72*x^2 -
24*x^3))*Log[x] + E^(4*x)*(4*x - 12*x^2 + 4*x^3)*Log[x]^2)/(16*x + E^x*(48*x^2 - 24*x^3) + E^(2*x)*(36*x^3 - 3
6*x^4 + 9*x^5) + (E^x*(-16*x^2 + 8*x^3) + E^(2*x)*(-24*x^3 + 24*x^4 - 6*x^5))*Log[x] + E^(2*x)*(4*x^3 - 4*x^4
+ x^5)*Log[x]^2),x]

[Out]

(4*E^(3*x)*(-3 + Log[x]))/(8 - 6*E^x*(-2 + x)*x + 2*E^x*(-2 + x)*x*Log[x])

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fricas [A]  time = 0.82, size = 43, normalized size = 1.39 \begin {gather*} \frac {2 \, {\left (e^{\left (3 \, x\right )} \log \relax (x) - 3 \, e^{\left (3 \, x\right )}\right )}}{{\left (x^{2} - 2 \, x\right )} e^{x} \log \relax (x) - 3 \, {\left (x^{2} - 2 \, x\right )} e^{x} + 4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^3-12*x^2+4*x)*exp(x)^4*log(x)^2+((-24*x^3+72*x^2-24*x)*exp(x)^4+24*x*exp(x)^3)*log(x)+(36*x^3-
108*x^2+36*x)*exp(x)^4+(-72*x+8)*exp(x)^3)/((x^5-4*x^4+4*x^3)*exp(x)^2*log(x)^2+((-6*x^5+24*x^4-24*x^3)*exp(x)
^2+(8*x^3-16*x^2)*exp(x))*log(x)+(9*x^5-36*x^4+36*x^3)*exp(x)^2+(-24*x^3+48*x^2)*exp(x)+16*x),x, algorithm="fr
icas")

[Out]

2*(e^(3*x)*log(x) - 3*e^(3*x))/((x^2 - 2*x)*e^x*log(x) - 3*(x^2 - 2*x)*e^x + 4)

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giac [A]  time = 0.91, size = 47, normalized size = 1.52 \begin {gather*} \frac {2 \, {\left (e^{\left (3 \, x\right )} \log \relax (x) - 3 \, e^{\left (3 \, x\right )}\right )}}{x^{2} e^{x} \log \relax (x) - 3 \, x^{2} e^{x} - 2 \, x e^{x} \log \relax (x) + 6 \, x e^{x} + 4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^3-12*x^2+4*x)*exp(x)^4*log(x)^2+((-24*x^3+72*x^2-24*x)*exp(x)^4+24*x*exp(x)^3)*log(x)+(36*x^3-
108*x^2+36*x)*exp(x)^4+(-72*x+8)*exp(x)^3)/((x^5-4*x^4+4*x^3)*exp(x)^2*log(x)^2+((-6*x^5+24*x^4-24*x^3)*exp(x)
^2+(8*x^3-16*x^2)*exp(x))*log(x)+(9*x^5-36*x^4+36*x^3)*exp(x)^2+(-24*x^3+48*x^2)*exp(x)+16*x),x, algorithm="gi
ac")

[Out]

2*(e^(3*x)*log(x) - 3*e^(3*x))/(x^2*e^x*log(x) - 3*x^2*e^x - 2*x*e^x*log(x) + 6*x*e^x + 4)

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maple [A]  time = 0.06, size = 61, normalized size = 1.97

method	result	size
risch	\(\frac {2 \,{\mathrm e}^{2 x}}{\left (x -2\right ) x}-\frac {8 \,{\mathrm e}^{2 x}}{\left (x -2\right ) x \left (x^{2} {\mathrm e}^{x} \ln \relax (x )-2 x \,{\mathrm e}^{x} \ln \relax (x )-3 \,{\mathrm e}^{x} x^{2}+6 \,{\mathrm e}^{x} x +4\right )}\)	\(61\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((4*x^3-12*x^2+4*x)*exp(x)^4*ln(x)^2+((-24*x^3+72*x^2-24*x)*exp(x)^4+24*x*exp(x)^3)*ln(x)+(36*x^3-108*x^2+
36*x)*exp(x)^4+(-72*x+8)*exp(x)^3)/((x^5-4*x^4+4*x^3)*exp(x)^2*ln(x)^2+((-6*x^5+24*x^4-24*x^3)*exp(x)^2+(8*x^3
-16*x^2)*exp(x))*ln(x)+(9*x^5-36*x^4+36*x^3)*exp(x)^2+(-24*x^3+48*x^2)*exp(x)+16*x),x,method=_RETURNVERBOSE)

[Out]

2*exp(2*x)/(x-2)/x-8*exp(2*x)/(x-2)/x/(x^2*exp(x)*ln(x)-2*x*exp(x)*ln(x)-3*exp(x)*x^2+6*exp(x)*x+4)

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maxima [A]  time = 0.54, size = 37, normalized size = 1.19 \begin {gather*} -\frac {2 \, {\left (\log \relax (x) - 3\right )} e^{\left (3 \, x\right )}}{{\left (3 \, x^{2} - {\left (x^{2} - 2 \, x\right )} \log \relax (x) - 6 \, x\right )} e^{x} - 4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x^3-12*x^2+4*x)*exp(x)^4*log(x)^2+((-24*x^3+72*x^2-24*x)*exp(x)^4+24*x*exp(x)^3)*log(x)+(36*x^3-
108*x^2+36*x)*exp(x)^4+(-72*x+8)*exp(x)^3)/((x^5-4*x^4+4*x^3)*exp(x)^2*log(x)^2+((-6*x^5+24*x^4-24*x^3)*exp(x)
^2+(8*x^3-16*x^2)*exp(x))*log(x)+(9*x^5-36*x^4+36*x^3)*exp(x)^2+(-24*x^3+48*x^2)*exp(x)+16*x),x, algorithm="ma
xima")

[Out]

-2*(log(x) - 3)*e^(3*x)/((3*x^2 - (x^2 - 2*x)*log(x) - 6*x)*e^x - 4)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} -\int -\frac {{\mathrm {e}}^{4\,x}\,\left (4\,x^3-12\,x^2+4\,x\right )\,{\ln \relax (x)}^2+\left (24\,x\,{\mathrm {e}}^{3\,x}-{\mathrm {e}}^{4\,x}\,\left (24\,x^3-72\,x^2+24\,x\right )\right )\,\ln \relax (x)+{\mathrm {e}}^{4\,x}\,\left (36\,x^3-108\,x^2+36\,x\right )-{\mathrm {e}}^{3\,x}\,\left (72\,x-8\right )}{{\mathrm {e}}^{2\,x}\,\left (x^5-4\,x^4+4\,x^3\right )\,{\ln \relax (x)}^2+\left (-{\mathrm {e}}^x\,\left (16\,x^2-8\,x^3\right )-{\mathrm {e}}^{2\,x}\,\left (6\,x^5-24\,x^4+24\,x^3\right )\right )\,\ln \relax (x)+16\,x+{\mathrm {e}}^x\,\left (48\,x^2-24\,x^3\right )+{\mathrm {e}}^{2\,x}\,\left (9\,x^5-36\,x^4+36\,x^3\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((exp(4*x)*(36*x - 108*x^2 + 36*x^3) - exp(3*x)*(72*x - 8) + log(x)*(24*x*exp(3*x) - exp(4*x)*(24*x - 72*x^
2 + 24*x^3)) + exp(4*x)*log(x)^2*(4*x - 12*x^2 + 4*x^3))/(16*x + exp(x)*(48*x^2 - 24*x^3) - log(x)*(exp(x)*(16
*x^2 - 8*x^3) + exp(2*x)*(24*x^3 - 24*x^4 + 6*x^5)) + exp(2*x)*(36*x^3 - 36*x^4 + 9*x^5) + exp(2*x)*log(x)^2*(
4*x^3 - 4*x^4 + x^5)),x)

[Out]

-int(-(exp(4*x)*(36*x - 108*x^2 + 36*x^3) - exp(3*x)*(72*x - 8) + log(x)*(24*x*exp(3*x) - exp(4*x)*(24*x - 72*
x^2 + 24*x^3)) + exp(4*x)*log(x)^2*(4*x - 12*x^2 + 4*x^3))/(16*x + exp(x)*(48*x^2 - 24*x^3) - log(x)*(exp(x)*(
16*x^2 - 8*x^3) + exp(2*x)*(24*x^3 - 24*x^4 + 6*x^5)) + exp(2*x)*(36*x^3 - 36*x^4 + 9*x^5) + exp(2*x)*log(x)^2
*(4*x^3 - 4*x^4 + x^5)), x)

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sympy [B]  time = 1.35, size = 447, normalized size = 14.42 \begin {gather*} \frac {\left (- 8 x^{2} + 16 x\right ) e^{x} + \left (2 x^{4} \log {\relax (x )} - 6 x^{4} - 8 x^{3} \log {\relax (x )} + 24 x^{3} + 8 x^{2} \log {\relax (x )} - 24 x^{2}\right ) e^{2 x}}{x^{6} \log {\relax (x )} - 3 x^{6} - 6 x^{5} \log {\relax (x )} + 18 x^{5} + 12 x^{4} \log {\relax (x )} - 36 x^{4} - 8 x^{3} \log {\relax (x )} + 24 x^{3}} - \frac {128}{4 x^{6} \log {\relax (x )}^{2} - 24 x^{6} \log {\relax (x )} + 36 x^{6} - 24 x^{5} \log {\relax (x )}^{2} + 144 x^{5} \log {\relax (x )} - 216 x^{5} + 48 x^{4} \log {\relax (x )}^{2} - 288 x^{4} \log {\relax (x )} + 432 x^{4} - 32 x^{3} \log {\relax (x )}^{2} + 192 x^{3} \log {\relax (x )} - 288 x^{3} + \left (x^{8} \log {\relax (x )}^{3} - 9 x^{8} \log {\relax (x )}^{2} + 27 x^{8} \log {\relax (x )} - 27 x^{8} - 8 x^{7} \log {\relax (x )}^{3} + 72 x^{7} \log {\relax (x )}^{2} - 216 x^{7} \log {\relax (x )} + 216 x^{7} + 24 x^{6} \log {\relax (x )}^{3} - 216 x^{6} \log {\relax (x )}^{2} + 648 x^{6} \log {\relax (x )} - 648 x^{6} - 32 x^{5} \log {\relax (x )}^{3} + 288 x^{5} \log {\relax (x )}^{2} - 864 x^{5} \log {\relax (x )} + 864 x^{5} + 16 x^{4} \log {\relax (x )}^{3} - 144 x^{4} \log {\relax (x )}^{2} + 432 x^{4} \log {\relax (x )} - 432 x^{4}\right ) e^{x}} + \frac {32}{9 x^{6} - 54 x^{5} + 108 x^{4} - 72 x^{3} + \left (- 6 x^{6} + 36 x^{5} - 72 x^{4} + 48 x^{3}\right ) \log {\relax (x )} + \left (x^{6} - 6 x^{5} + 12 x^{4} - 8 x^{3}\right ) \log {\relax (x )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(((4*x**3-12*x**2+4*x)*exp(x)**4*ln(x)**2+((-24*x**3+72*x**2-24*x)*exp(x)**4+24*x*exp(x)**3)*ln(x)+(3
6*x**3-108*x**2+36*x)*exp(x)**4+(-72*x+8)*exp(x)**3)/((x**5-4*x**4+4*x**3)*exp(x)**2*ln(x)**2+((-6*x**5+24*x**
4-24*x**3)*exp(x)**2+(8*x**3-16*x**2)*exp(x))*ln(x)+(9*x**5-36*x**4+36*x**3)*exp(x)**2+(-24*x**3+48*x**2)*exp(
x)+16*x),x)

[Out]

((-8*x**2 + 16*x)*exp(x) + (2*x**4*log(x) - 6*x**4 - 8*x**3*log(x) + 24*x**3 + 8*x**2*log(x) - 24*x**2)*exp(2*
x))/(x**6*log(x) - 3*x**6 - 6*x**5*log(x) + 18*x**5 + 12*x**4*log(x) - 36*x**4 - 8*x**3*log(x) + 24*x**3) - 12
8/(4*x**6*log(x)**2 - 24*x**6*log(x) + 36*x**6 - 24*x**5*log(x)**2 + 144*x**5*log(x) - 216*x**5 + 48*x**4*log(
x)**2 - 288*x**4*log(x) + 432*x**4 - 32*x**3*log(x)**2 + 192*x**3*log(x) - 288*x**3 + (x**8*log(x)**3 - 9*x**8
*log(x)**2 + 27*x**8*log(x) - 27*x**8 - 8*x**7*log(x)**3 + 72*x**7*log(x)**2 - 216*x**7*log(x) + 216*x**7 + 24
*x**6*log(x)**3 - 216*x**6*log(x)**2 + 648*x**6*log(x) - 648*x**6 - 32*x**5*log(x)**3 + 288*x**5*log(x)**2 - 8
64*x**5*log(x) + 864*x**5 + 16*x**4*log(x)**3 - 144*x**4*log(x)**2 + 432*x**4*log(x) - 432*x**4)*exp(x)) + 32/
(9*x**6 - 54*x**5 + 108*x**4 - 72*x**3 + (-6*x**6 + 36*x**5 - 72*x**4 + 48*x**3)*log(x) + (x**6 - 6*x**5 + 12*
x**4 - 8*x**3)*log(x)**2)

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