Optimal. Leaf size=40 \[ x \text {Li}_2\left (-e^x\right )-x \text {Li}_2\left (e^x\right )-\text {Li}_3\left (-e^x\right )+\text {Li}_3\left (e^x\right )+x^2 \tanh ^{-1}\left (e^x\right ) \]
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Rubi [A] time = 0.10, antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.389, Rules used = {2249, 206, 2245, 6213, 2531, 2282, 6589} \[ x \text {PolyLog}\left (2,-e^x\right )-x \text {PolyLog}\left (2,e^x\right )-\text {PolyLog}\left (3,-e^x\right )+\text {PolyLog}\left (3,e^x\right )+x^2 \tanh ^{-1}\left (e^x\right ) \]
Antiderivative was successfully verified.
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Rule 206
Rule 2245
Rule 2249
Rule 2282
Rule 2531
Rule 6213
Rule 6589
Rubi steps
\begin {align*} \int \frac {e^x x^2}{1-e^{2 x}} \, dx &=x^2 \tanh ^{-1}\left (e^x\right )-2 \int x \tanh ^{-1}\left (e^x\right ) \, dx\\ &=x^2 \tanh ^{-1}\left (e^x\right )+\int x \log \left (1-e^x\right ) \, dx-\int x \log \left (1+e^x\right ) \, dx\\ &=x^2 \tanh ^{-1}\left (e^x\right )+x \text {Li}_2\left (-e^x\right )-x \text {Li}_2\left (e^x\right )-\int \text {Li}_2\left (-e^x\right ) \, dx+\int \text {Li}_2\left (e^x\right ) \, dx\\ &=x^2 \tanh ^{-1}\left (e^x\right )+x \text {Li}_2\left (-e^x\right )-x \text {Li}_2\left (e^x\right )-\operatorname {Subst}\left (\int \frac {\text {Li}_2(-x)}{x} \, dx,x,e^x\right )+\operatorname {Subst}\left (\int \frac {\text {Li}_2(x)}{x} \, dx,x,e^x\right )\\ &=x^2 \tanh ^{-1}\left (e^x\right )+x \text {Li}_2\left (-e^x\right )-x \text {Li}_2\left (e^x\right )-\text {Li}_3\left (-e^x\right )+\text {Li}_3\left (e^x\right )\\ \end {align*}
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Mathematica [A] time = 0.04, size = 60, normalized size = 1.50 \[ x \text {Li}_2\left (-e^x\right )-x \text {Li}_2\left (e^x\right )-\text {Li}_3\left (-e^x\right )+\text {Li}_3\left (e^x\right )-\frac {1}{2} x^2 \log \left (1-e^x\right )+\frac {1}{2} x^2 \log \left (e^x+1\right ) \]
Antiderivative was successfully verified.
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fricas [C] time = 0.44, size = 48, normalized size = 1.20 \[ \frac {1}{2} \, x^{2} \log \left (e^{x} + 1\right ) - \frac {1}{2} \, x^{2} \log \left (-e^{x} + 1\right ) + x {\rm Li}_2\left (-e^{x}\right ) - x {\rm Li}_2\left (e^{x}\right ) - {\rm polylog}\left (3, -e^{x}\right ) + {\rm polylog}\left (3, e^{x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int -\frac {x^{2} e^{x}}{e^{\left (2 \, x\right )} - 1}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.02, size = 51, normalized size = 1.28 \[ -\frac {x^{2} \ln \left (-{\mathrm e}^{x}+1\right )}{2}+\frac {x^{2} \ln \left ({\mathrm e}^{x}+1\right )}{2}+x \polylog \left (2, -{\mathrm e}^{x}\right )-x \polylog \left (2, {\mathrm e}^{x}\right )-\polylog \left (3, -{\mathrm e}^{x}\right )+\polylog \left (3, {\mathrm e}^{x}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.45, size = 48, normalized size = 1.20 \[ \frac {1}{2} \, x^{2} \log \left (e^{x} + 1\right ) - \frac {1}{2} \, x^{2} \log \left (-e^{x} + 1\right ) + x {\rm Li}_2\left (-e^{x}\right ) - x {\rm Li}_2\left (e^{x}\right ) - {\rm Li}_{3}(-e^{x}) + {\rm Li}_{3}(e^{x}) \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.02 \[ -\int \frac {x^2\,{\mathrm {e}}^x}{{\mathrm {e}}^{2\,x}-1} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - \int \frac {x^{2} e^{x}}{e^{2 x} - 1}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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