Optimal. Leaf size=298 \[ \frac {2 \sqrt {-e} \sqrt [4]{e} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} \sqrt {d+e x^2}}-\frac {4 \sqrt {-e} \sqrt [4]{e} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} \sqrt {d+e x^2}}+\frac {4 \sqrt {-e^2} \sqrt {x} \sqrt {d+e x^2}}{3 d \left (\sqrt {d}+\sqrt {e} x\right )}-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}} \]
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Rubi [A] time = 0.17, antiderivative size = 298, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, integrand size = 27, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.222, Rules used = {5151, 325, 329, 305, 220, 1196} \[ \frac {2 \sqrt {-e} \sqrt [4]{e} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} \sqrt {d+e x^2}}-\frac {4 \sqrt {-e} \sqrt [4]{e} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} \sqrt {d+e x^2}}+\frac {4 \sqrt {-e^2} \sqrt {x} \sqrt {d+e x^2}}{3 d \left (\sqrt {d}+\sqrt {e} x\right )}-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}} \]
Antiderivative was successfully verified.
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Rule 220
Rule 305
Rule 325
Rule 329
Rule 1196
Rule 5151
Rubi steps
\begin {align*} \int \frac {\tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{x^{5/2}} \, dx &=-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}}+\frac {1}{3} \left (2 \sqrt {-e}\right ) \int \frac {1}{x^{3/2} \sqrt {d+e x^2}} \, dx\\ &=-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}}-\frac {\left (2 (-e)^{3/2}\right ) \int \frac {\sqrt {x}}{\sqrt {d+e x^2}} \, dx}{3 d}\\ &=-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}}-\frac {\left (4 (-e)^{3/2}\right ) \operatorname {Subst}\left (\int \frac {x^2}{\sqrt {d+e x^4}} \, dx,x,\sqrt {x}\right )}{3 d}\\ &=-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}}-\frac {\left (4 (-e)^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {d+e x^4}} \, dx,x,\sqrt {x}\right )}{3 \sqrt {d} \sqrt {e}}+\frac {\left (4 (-e)^{3/2}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {e} x^2}{\sqrt {d}}}{\sqrt {d+e x^4}} \, dx,x,\sqrt {x}\right )}{3 \sqrt {d} \sqrt {e}}\\ &=-\frac {4 \sqrt {-e} \sqrt {d+e x^2}}{3 d \sqrt {x}}-\frac {4 (-e)^{3/2} \sqrt {x} \sqrt {d+e x^2}}{3 d \sqrt {e} \left (\sqrt {d}+\sqrt {e} x\right )}-\frac {2 \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )}{3 x^{3/2}}+\frac {4 (-e)^{3/2} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} e^{3/4} \sqrt {d+e x^2}}-\frac {2 (-e)^{3/2} \left (\sqrt {d}+\sqrt {e} x\right ) \sqrt {\frac {d+e x^2}{\left (\sqrt {d}+\sqrt {e} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{e} \sqrt {x}}{\sqrt [4]{d}}\right )|\frac {1}{2}\right )}{3 d^{3/4} e^{3/4} \sqrt {d+e x^2}}\\ \end {align*}
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Mathematica [C] time = 0.15, size = 121, normalized size = 0.41 \[ -\frac {2 \left (2 (-e)^{3/2} x^3 \sqrt {\frac {e x^2}{d}+1} \, _2F_1\left (\frac {1}{2},\frac {3}{4};\frac {7}{4};-\frac {e x^2}{d}\right )+6 \sqrt {-e} x \left (d+e x^2\right )+3 d \sqrt {d+e x^2} \tan ^{-1}\left (\frac {\sqrt {-e} x}{\sqrt {d+e x^2}}\right )\right )}{9 d x^{3/2} \sqrt {d+e x^2}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.54, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\arctan \left (\frac {\sqrt {-e} x}{\sqrt {e x^{2} + d}}\right )}{x^{\frac {5}{2}}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\arctan \left (\frac {\sqrt {-e} x}{\sqrt {e x^{2} + d}}\right )}{x^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.24, size = 0, normalized size = 0.00 \[ \int \frac {\arctan \left (\frac {x \sqrt {-e}}{\sqrt {e \,x^{2}+d}}\right )}{x^{\frac {5}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\mathrm {atan}\left (\frac {\sqrt {-e}\,x}{\sqrt {e\,x^2+d}}\right )}{x^{5/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 13.09, size = 78, normalized size = 0.26 \[ - \frac {2 \operatorname {atan}{\left (\frac {x \sqrt {- e}}{\sqrt {d + e x^{2}}} \right )}}{3 x^{\frac {3}{2}}} + \frac {\sqrt {- e} \Gamma \left (- \frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{4}, \frac {1}{2} \\ \frac {3}{4} \end {matrix}\middle | {\frac {e x^{2} e^{i \pi }}{d}} \right )}}{3 \sqrt {d} \sqrt {x} \Gamma \left (\frac {3}{4}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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