Optimal. Leaf size=167 \[ -\frac {5 a^2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{a x^3-b}}{\sqrt {a x^3-b}-\sqrt {b}}\right )}{48 \sqrt {2} b^{9/4}}-\frac {5 a^2 \tanh ^{-1}\left (\frac {\frac {\sqrt {a x^3-b}}{\sqrt {2} \sqrt [4]{b}}+\frac {\sqrt [4]{b}}{\sqrt {2}}}{\sqrt [4]{a x^3-b}}\right )}{48 \sqrt {2} b^{9/4}}+\frac {\left (a x^3-b\right )^{3/4} \left (5 a x^3+4 b\right )}{24 b^2 x^6} \]
________________________________________________________________________________________
Rubi [A] time = 0.27, antiderivative size = 260, normalized size of antiderivative = 1.56, number of steps used = 13, number of rules used = 9, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.529, Rules used = {266, 51, 63, 297, 1162, 617, 204, 1165, 628} \begin {gather*} \frac {5 a^2 \log \left (-\sqrt {2} \sqrt [4]{b} \sqrt [4]{a x^3-b}+\sqrt {a x^3-b}+\sqrt {b}\right )}{96 \sqrt {2} b^{9/4}}-\frac {5 a^2 \log \left (\sqrt {2} \sqrt [4]{b} \sqrt [4]{a x^3-b}+\sqrt {a x^3-b}+\sqrt {b}\right )}{96 \sqrt {2} b^{9/4}}-\frac {5 a^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{a x^3-b}}{\sqrt [4]{b}}\right )}{48 \sqrt {2} b^{9/4}}+\frac {5 a^2 \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{a x^3-b}}{\sqrt [4]{b}}+1\right )}{48 \sqrt {2} b^{9/4}}+\frac {5 a \left (a x^3-b\right )^{3/4}}{24 b^2 x^3}+\frac {\left (a x^3-b\right )^{3/4}}{6 b x^6} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 51
Rule 63
Rule 204
Rule 266
Rule 297
Rule 617
Rule 628
Rule 1162
Rule 1165
Rubi steps
\begin {align*} \int \frac {1}{x^7 \sqrt [4]{-b+a x^3}} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {1}{x^3 \sqrt [4]{-b+a x}} \, dx,x,x^3\right )\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {(5 a) \operatorname {Subst}\left (\int \frac {1}{x^2 \sqrt [4]{-b+a x}} \, dx,x,x^3\right )}{24 b}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt [4]{-b+a x}} \, dx,x,x^3\right )}{96 b^2}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}+\frac {(5 a) \operatorname {Subst}\left (\int \frac {x^2}{\frac {b}{a}+\frac {x^4}{a}} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{24 b^2}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}-\frac {(5 a) \operatorname {Subst}\left (\int \frac {\sqrt {b}-x^2}{\frac {b}{a}+\frac {x^4}{a}} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{48 b^2}+\frac {(5 a) \operatorname {Subst}\left (\int \frac {\sqrt {b}+x^2}{\frac {b}{a}+\frac {x^4}{a}} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{48 b^2}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt [4]{b}+2 x}{-\sqrt {b}-\sqrt {2} \sqrt [4]{b} x-x^2} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt [4]{b}-2 x}{-\sqrt {b}+\sqrt {2} \sqrt [4]{b} x-x^2} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {b}-\sqrt {2} \sqrt [4]{b} x+x^2} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{96 b^2}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {b}+\sqrt {2} \sqrt [4]{b} x+x^2} \, dx,x,\sqrt [4]{-b+a x^3}\right )}{96 b^2}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}+\frac {5 a^2 \log \left (\sqrt {b}-\sqrt {2} \sqrt [4]{b} \sqrt [4]{-b+a x^3}+\sqrt {-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}-\frac {5 a^2 \log \left (\sqrt {b}+\sqrt {2} \sqrt [4]{b} \sqrt [4]{-b+a x^3}+\sqrt {-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}+\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{-b+a x^3}}{\sqrt [4]{b}}\right )}{48 \sqrt {2} b^{9/4}}-\frac {\left (5 a^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{-b+a x^3}}{\sqrt [4]{b}}\right )}{48 \sqrt {2} b^{9/4}}\\ &=\frac {\left (-b+a x^3\right )^{3/4}}{6 b x^6}+\frac {5 a \left (-b+a x^3\right )^{3/4}}{24 b^2 x^3}-\frac {5 a^2 \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{-b+a x^3}}{\sqrt [4]{b}}\right )}{48 \sqrt {2} b^{9/4}}+\frac {5 a^2 \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{-b+a x^3}}{\sqrt [4]{b}}\right )}{48 \sqrt {2} b^{9/4}}+\frac {5 a^2 \log \left (\sqrt {b}-\sqrt {2} \sqrt [4]{b} \sqrt [4]{-b+a x^3}+\sqrt {-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}-\frac {5 a^2 \log \left (\sqrt {b}+\sqrt {2} \sqrt [4]{b} \sqrt [4]{-b+a x^3}+\sqrt {-b+a x^3}\right )}{96 \sqrt {2} b^{9/4}}\\ \end {align*}
________________________________________________________________________________________
Mathematica [C] time = 0.01, size = 42, normalized size = 0.25 \begin {gather*} \frac {4 a^2 \left (a x^3-b\right )^{3/4} \, _2F_1\left (\frac {3}{4},3;\frac {7}{4};1-\frac {a x^3}{b}\right )}{9 b^3} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
IntegrateAlgebraic [A] time = 0.29, size = 166, normalized size = 0.99 \begin {gather*} \frac {\left (-b+a x^3\right )^{3/4} \left (4 b+5 a x^3\right )}{24 b^2 x^6}+\frac {5 a^2 \tan ^{-1}\left (\frac {-\frac {\sqrt [4]{b}}{\sqrt {2}}+\frac {\sqrt {-b+a x^3}}{\sqrt {2} \sqrt [4]{b}}}{\sqrt [4]{-b+a x^3}}\right )}{48 \sqrt {2} b^{9/4}}-\frac {5 a^2 \tanh ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt [4]{-b+a x^3}}{\sqrt {b}+\sqrt {-b+a x^3}}\right )}{48 \sqrt {2} b^{9/4}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
fricas [A] time = 0.85, size = 240, normalized size = 1.44 \begin {gather*} -\frac {20 \, b^{2} x^{6} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {1}{4}} \arctan \left (-\frac {125 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}} a^{6} b^{2} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {1}{4}} - \sqrt {-15625 \, a^{8} b^{5} \sqrt {-\frac {a^{8}}{b^{9}}} + 15625 \, \sqrt {a x^{3} - b} a^{12}} b^{2} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {1}{4}}}{125 \, a^{8}}\right ) - 5 \, b^{2} x^{6} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {1}{4}} \log \left (125 \, b^{7} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {3}{4}} + 125 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}} a^{6}\right ) + 5 \, b^{2} x^{6} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {1}{4}} \log \left (-125 \, b^{7} \left (-\frac {a^{8}}{b^{9}}\right )^{\frac {3}{4}} + 125 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}} a^{6}\right ) - 4 \, {\left (5 \, a x^{3} + 4 \, b\right )} {\left (a x^{3} - b\right )}^{\frac {3}{4}}}{96 \, b^{2} x^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
giac [A] time = 0.33, size = 224, normalized size = 1.34 \begin {gather*} \frac {\frac {10 \, \sqrt {2} a^{3} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} + 2 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}}\right )}}{2 \, b^{\frac {1}{4}}}\right )}{b^{\frac {9}{4}}} + \frac {10 \, \sqrt {2} a^{3} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} - 2 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}}\right )}}{2 \, b^{\frac {1}{4}}}\right )}{b^{\frac {9}{4}}} - \frac {5 \, \sqrt {2} a^{3} \log \left (\sqrt {2} {\left (a x^{3} - b\right )}^{\frac {1}{4}} b^{\frac {1}{4}} + \sqrt {a x^{3} - b} + \sqrt {b}\right )}{b^{\frac {9}{4}}} + \frac {5 \, \sqrt {2} a^{3} \log \left (-\sqrt {2} {\left (a x^{3} - b\right )}^{\frac {1}{4}} b^{\frac {1}{4}} + \sqrt {a x^{3} - b} + \sqrt {b}\right )}{b^{\frac {9}{4}}} + \frac {8 \, {\left (5 \, {\left (a x^{3} - b\right )}^{\frac {7}{4}} a^{3} + 9 \, {\left (a x^{3} - b\right )}^{\frac {3}{4}} a^{3} b\right )}}{a^{2} b^{2} x^{6}}}{192 \, a} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maple [F] time = 0.00, size = 0, normalized size = 0.00 \[\int \frac {1}{x^{7} \left (a \,x^{3}-b \right )^{\frac {1}{4}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
maxima [A] time = 0.43, size = 241, normalized size = 1.44 \begin {gather*} \frac {5 \, {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} + 2 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}}\right )}}{2 \, b^{\frac {1}{4}}}\right )}{b^{\frac {1}{4}}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} b^{\frac {1}{4}} - 2 \, {\left (a x^{3} - b\right )}^{\frac {1}{4}}\right )}}{2 \, b^{\frac {1}{4}}}\right )}{b^{\frac {1}{4}}} - \frac {\sqrt {2} \log \left (\sqrt {2} {\left (a x^{3} - b\right )}^{\frac {1}{4}} b^{\frac {1}{4}} + \sqrt {a x^{3} - b} + \sqrt {b}\right )}{b^{\frac {1}{4}}} + \frac {\sqrt {2} \log \left (-\sqrt {2} {\left (a x^{3} - b\right )}^{\frac {1}{4}} b^{\frac {1}{4}} + \sqrt {a x^{3} - b} + \sqrt {b}\right )}{b^{\frac {1}{4}}}\right )} a^{2}}{192 \, b^{2}} + \frac {5 \, {\left (a x^{3} - b\right )}^{\frac {7}{4}} a^{2} + 9 \, {\left (a x^{3} - b\right )}^{\frac {3}{4}} a^{2} b}{24 \, {\left ({\left (a x^{3} - b\right )}^{2} b^{2} + 2 \, {\left (a x^{3} - b\right )} b^{3} + b^{4}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
mupad [B] time = 1.32, size = 98, normalized size = 0.59 \begin {gather*} \frac {3\,{\left (a\,x^3-b\right )}^{3/4}}{8\,b\,x^6}+\frac {5\,{\left (a\,x^3-b\right )}^{7/4}}{24\,b^2\,x^6}+\frac {5\,a^2\,\mathrm {atan}\left (\frac {{\left (a\,x^3-b\right )}^{1/4}}{{\left (-b\right )}^{1/4}}\right )}{48\,{\left (-b\right )}^{9/4}}+\frac {a^2\,\mathrm {atan}\left (\frac {{\left (a\,x^3-b\right )}^{1/4}\,1{}\mathrm {i}}{{\left (-b\right )}^{1/4}}\right )\,5{}\mathrm {i}}{48\,{\left (-b\right )}^{9/4}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
sympy [C] time = 1.44, size = 42, normalized size = 0.25 \begin {gather*} - \frac {\Gamma \left (\frac {9}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {9}{4} \\ \frac {13}{4} \end {matrix}\middle | {\frac {b e^{2 i \pi }}{a x^{3}}} \right )}}{3 \sqrt [4]{a} x^{\frac {27}{4}} \Gamma \left (\frac {13}{4}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________