3.2.50 \(\int \frac {\tanh (a+2 \log (x))}{x} \, dx\) [150]

Optimal. Leaf size=12 \[ \frac {1}{2} \log (\cosh (a+2 \log (x))) \]

[Out]

1/2*ln(cosh(a+2*ln(x)))

________________________________________________________________________________________

Rubi [A]
time = 0.01, antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {3556} \begin {gather*} \frac {1}{2} \log (\cosh (a+2 \log (x))) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[Tanh[a + 2*Log[x]]/x,x]

[Out]

Log[Cosh[a + 2*Log[x]]]/2

Rule 3556

Int[tan[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-Log[RemoveContent[Cos[c + d*x], x]]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin {align*} \int \frac {\tanh (a+2 \log (x))}{x} \, dx &=\text {Subst}(\int \tanh (a+2 x) \, dx,x,\log (x))\\ &=\frac {1}{2} \log (\cosh (a+2 \log (x)))\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.02, size = 12, normalized size = 1.00 \begin {gather*} \frac {1}{2} \log (\cosh (a+2 \log (x))) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[Tanh[a + 2*Log[x]]/x,x]

[Out]

Log[Cosh[a + 2*Log[x]]]/2

________________________________________________________________________________________

Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(25\) vs. \(2(10)=20\).
time = 0.68, size = 26, normalized size = 2.17

method	result	size
risch	\(-\ln \left (x \right )+\frac {\ln \left (-{\mathrm e}^{2 a} x^{4}-1\right )}{2}\)	\(20\)
derivativedivides	\(-\frac {\ln \left (\tanh \left (a +2 \ln \left (x \right )\right )-1\right )}{4}-\frac {\ln \left (\tanh \left (a +2 \ln \left (x \right )\right )+1\right )}{4}\)	\(26\)
default	\(-\frac {\ln \left (\tanh \left (a +2 \ln \left (x \right )\right )-1\right )}{4}-\frac {\ln \left (\tanh \left (a +2 \ln \left (x \right )\right )+1\right )}{4}\)	\(26\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(a+2*ln(x))/x,x,method=_RETURNVERBOSE)

[Out]

-1/4*ln(tanh(a+2*ln(x))-1)-1/4*ln(tanh(a+2*ln(x))+1)

________________________________________________________________________________________

Maxima [A]
time = 0.26, size = 10, normalized size = 0.83 \begin {gather*} \frac {1}{2} \, \log \left (\cosh \left (a + 2 \, \log \left (x\right )\right )\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+2*log(x))/x,x, algorithm="maxima")

[Out]

1/2*log(cosh(a + 2*log(x)))

________________________________________________________________________________________

Fricas [A]
time = 0.36, size = 18, normalized size = 1.50 \begin {gather*} \frac {1}{2} \, \log \left (x^{4} e^{\left (2 \, a\right )} + 1\right ) - \log \left (x\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+2*log(x))/x,x, algorithm="fricas")

[Out]

1/2*log(x^4*e^(2*a) + 1) - log(x)

________________________________________________________________________________________

Sympy [A]
time = 0.09, size = 15, normalized size = 1.25 \begin {gather*} \log {\left (x \right )} - \frac {\log {\left (\tanh {\left (a + 2 \log {\left (x \right )} \right )} + 1 \right )}}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+2*ln(x))/x,x)

[Out]

log(x) - log(tanh(a + 2*log(x)) + 1)/2

________________________________________________________________________________________

Giac [A]
time = 0.41, size = 20, normalized size = 1.67 \begin {gather*} \frac {1}{2} \, \log \left (x^{4} e^{\left (2 \, a\right )} + 1\right ) - \frac {1}{4} \, \log \left (x^{4}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(a+2*log(x))/x,x, algorithm="giac")

[Out]

1/2*log(x^4*e^(2*a) + 1) - 1/4*log(x^4)

________________________________________________________________________________________

Mupad [B]
time = 1.12, size = 15, normalized size = 1.25 \begin {gather*} \ln \left (x\right )-\frac {\ln \left (\mathrm {tanh}\left (a+2\,\ln \left (x\right )\right )+1\right )}{2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(a + 2*log(x))/x,x)

[Out]

log(x) - log(tanh(a + 2*log(x)) + 1)/2

________________________________________________________________________________________