Optimal. Leaf size=169 \[ \frac {(1+m+b d n) (e x)^{1+m}}{b d e (1+m) n}+\frac {(e x)^{1+m} \left (1-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{b d e n \left (1+e^{2 a d} \left (c x^n\right )^{2 b d}\right )}-\frac {2 (e x)^{1+m} \, _2F_1\left (1,\frac {1+m}{2 b d n};1+\frac {1+m}{2 b d n};-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{b d e n} \]
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Rubi [A]
time = 0.15, antiderivative size = 169, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {5658, 5656,
516, 470, 371} \begin {gather*} -\frac {2 (e x)^{m+1} \, _2F_1\left (1,\frac {m+1}{2 b d n};\frac {m+1}{2 b d n}+1;-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{b d e n}+\frac {(e x)^{m+1} \left (1-e^{2 a d} \left (c x^n\right )^{2 b d}\right )}{b d e n \left (e^{2 a d} \left (c x^n\right )^{2 b d}+1\right )}+\frac {(e x)^{m+1} (b d n+m+1)}{b d e (m+1) n} \end {gather*}
Antiderivative was successfully verified.
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Rule 371
Rule 470
Rule 516
Rule 5656
Rule 5658
Rubi steps
\begin {align*} \int (e x)^m \tanh ^2\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx &=\int (e x)^m \tanh ^2\left (d \left (a+b \log \left (c x^n\right )\right )\right ) \, dx\\ \end {align*}
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Mathematica [A]
time = 12.98, size = 317, normalized size = 1.88 \begin {gather*} (e x)^m \left (\frac {x}{1+m}-\frac {e^{-\frac {(1+2 m) \left (a-b n \log (x)+b \log \left (c x^n\right )\right )}{b n}} x^{-2 m} \left (e^{\frac {(1+2 m) \left (a+b \log \left (c x^n\right )\right )}{b n}} (1+m+2 b d n) \, _2F_1\left (1,\frac {1+m}{2 b d n};1+\frac {1+m}{2 b d n};-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )-e^{\frac {(1+2 m+2 b d n) \left (a-b n \log (x)+b \log \left (c x^n\right )\right )}{b n}} (1+m) x^{1+2 m+2 b d n} \, _2F_1\left (1,\frac {1+m+2 b d n}{2 b d n};\frac {1+m+4 b d n}{2 b d n};-e^{2 d \left (a+b \log \left (c x^n\right )\right )}\right )+e^{\frac {(1+2 m) \left (a+b \log \left (c x^n\right )\right )}{b n}} (1+m+2 b d n) \tanh \left (d \left (a+b \log \left (c x^n\right )\right )\right )\right )}{b d n (1+m+2 b d n)}\right ) \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.49, size = 0, normalized size = 0.00 \[\int \left (e x \right )^{m} \left (\tanh ^{2}\left (d \left (a +b \ln \left (c \,x^{n}\right )\right )\right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (e x\right )^{m} \tanh ^{2}{\left (a d + b d \log {\left (c x^{n} \right )} \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\mathrm {tanh}\left (d\,\left (a+b\,\ln \left (c\,x^n\right )\right )\right )}^2\,{\left (e\,x\right )}^m \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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