Optimal. Leaf size=16 \[ \frac {\tanh ^{-1}(\tanh (a+b x))^2}{2 b} \]
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Rubi [A]
time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {2188, 30}
\begin {gather*} \frac {\tanh ^{-1}(\tanh (a+b x))^2}{2 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 30
Rule 2188
Rubi steps
\begin {align*} \int \tanh ^{-1}(\tanh (a+b x)) \, dx &=\frac {\text {Subst}\left (\int x \, dx,x,\tanh ^{-1}(\tanh (a+b x))\right )}{b}\\ &=\frac {\tanh ^{-1}(\tanh (a+b x))^2}{2 b}\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 18, normalized size = 1.12 \begin {gather*} -\frac {b x^2}{2}+x \tanh ^{-1}(\tanh (a+b x)) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.10, size = 15, normalized size = 0.94
method | result | size |
derivativedivides | \(\frac {\arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{2 b}\) | \(15\) |
default | \(\frac {\arctanh \left (\tanh \left (b x +a \right )\right )^{2}}{2 b}\) | \(15\) |
risch | \(x \ln \left ({\mathrm e}^{b x +a}\right )-\frac {i \pi \,\mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right ) x}{4}+\frac {i \pi \,\mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2} x}{4}-\frac {i \pi \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{3} x}{4}+\frac {i \pi \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{2} \mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right ) x}{2}+\frac {i \pi \,\mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2} x}{4}-\frac {i \pi \,\mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right )^{2} x}{4}-\frac {i \pi \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{3} x}{4}-\frac {b \,x^{2}}{2}\) | \(287\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.29, size = 16, normalized size = 1.00 \begin {gather*} -\frac {1}{2} \, b x^{2} + x \operatorname {artanh}\left (\tanh \left (b x + a\right )\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.33, size = 10, normalized size = 0.62 \begin {gather*} \frac {1}{2} \, b x^{2} + a x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 0.06, size = 19, normalized size = 1.19 \begin {gather*} \begin {cases} \frac {\operatorname {atanh}^{2}{\left (\tanh {\left (a + b x \right )} \right )}}{2 b} & \text {for}\: b \neq 0 \\x \operatorname {atanh}{\left (\tanh {\left (a \right )} \right )} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.39, size = 10, normalized size = 0.62 \begin {gather*} \frac {1}{2} \, b x^{2} + a x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.05, size = 16, normalized size = 1.00 \begin {gather*} x\,\mathrm {atanh}\left (\mathrm {tanh}\left (a+b\,x\right )\right )-\frac {b\,x^2}{2} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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