Optimal. Leaf size=21 \[ b x-\left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \log (x) \]
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Rubi [A]
time = 0.02, antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps
used = 2, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {2189, 29}
\begin {gather*} b x-\log (x) \left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \end {gather*}
Antiderivative was successfully verified.
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Rule 29
Rule 2189
Rubi steps
\begin {align*} \int \frac {\tanh ^{-1}(\tanh (a+b x))}{x} \, dx &=b x-\left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \int \frac {1}{x} \, dx\\ &=b x-\left (b x-\tanh ^{-1}(\tanh (a+b x))\right ) \log (x)\\ \end {align*}
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Mathematica [A]
time = 0.01, size = 19, normalized size = 0.90 \begin {gather*} b x+\left (-b x+\tanh ^{-1}(\tanh (a+b x))\right ) \log (x) \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.06, size = 23, normalized size = 1.10
method | result | size |
default | \(\ln \left (x \right ) \arctanh \left (\tanh \left (b x +a \right )\right )-b \left (x \ln \left (x \right )-x \right )\) | \(23\) |
risch | \(\ln \left (x \right ) \ln \left ({\mathrm e}^{b x +a}\right )-\ln \left (x \right ) x b +b x +\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2}}{4}-\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{3}}{4}-\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right )^{2} \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )}{4}-\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )}{4}+\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (i {\mathrm e}^{b x +a}\right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{2}}{2}+\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (\frac {i}{{\mathrm e}^{2 b x +2 a}+1}\right ) \mathrm {csgn}\left (\frac {i {\mathrm e}^{2 b x +2 a}}{{\mathrm e}^{2 b x +2 a}+1}\right )^{2}}{4}-\frac {i \pi \ln \left (x \right ) \mathrm {csgn}\left (i {\mathrm e}^{2 b x +2 a}\right )^{3}}{4}\) | \(298\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.26, size = 34, normalized size = 1.62 \begin {gather*} -b {\left (x + \frac {a}{b}\right )} \log \left (x\right ) + b {\left (x + \frac {a \log \left (x\right )}{b}\right )} + \operatorname {artanh}\left (\tanh \left (b x + a\right )\right ) \log \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.34, size = 8, normalized size = 0.38 \begin {gather*} b x + a \log \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\operatorname {atanh}{\left (\tanh {\left (a + b x \right )} \right )}}{x}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.39, size = 9, normalized size = 0.43 \begin {gather*} b x + a \log \left ({\left | x \right |}\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.10, size = 58, normalized size = 2.76 \begin {gather*} b\,x-\frac {\ln \left (\frac {1}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )\,\ln \left (x\right )}{2}+\frac {\ln \left (\frac {{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}}{{\mathrm {e}}^{2\,a}\,{\mathrm {e}}^{2\,b\,x}+1}\right )\,\ln \left (x\right )}{2}-b\,x\,\ln \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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