Integrand size = 9, antiderivative size = 12 \[ \int \frac {x}{1-x} \, dx=-x-\log (1-x) \]
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Time = 0.01 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {45} \[ \int \frac {x}{1-x} \, dx=-x-\log (1-x) \]
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Rule 45
Rubi steps \begin{align*} \text {integral}& = \int \left (-1+\frac {1}{1-x}\right ) \, dx \\ & = -x-\log (1-x) \\ \end{align*}
Time = 0.00 (sec) , antiderivative size = 12, normalized size of antiderivative = 1.00 \[ \int \frac {x}{1-x} \, dx=-x-\log (1-x) \]
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Time = 0.07 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.92
method | result | size |
default | \(-x -\ln \left (-1+x \right )\) | \(11\) |
norman | \(-x -\ln \left (-1+x \right )\) | \(11\) |
risch | \(-x -\ln \left (-1+x \right )\) | \(11\) |
parallelrisch | \(-x -\ln \left (-1+x \right )\) | \(11\) |
meijerg | \(-\ln \left (1-x \right )-x\) | \(13\) |
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none
Time = 0.24 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.83 \[ \int \frac {x}{1-x} \, dx=-x - \log \left (x - 1\right ) \]
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Time = 0.03 (sec) , antiderivative size = 7, normalized size of antiderivative = 0.58 \[ \int \frac {x}{1-x} \, dx=- x - \log {\left (x - 1 \right )} \]
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none
Time = 0.20 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.83 \[ \int \frac {x}{1-x} \, dx=-x - \log \left (x - 1\right ) \]
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none
Time = 0.26 (sec) , antiderivative size = 11, normalized size of antiderivative = 0.92 \[ \int \frac {x}{1-x} \, dx=-x - \log \left ({\left | x - 1 \right |}\right ) \]
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Time = 0.03 (sec) , antiderivative size = 10, normalized size of antiderivative = 0.83 \[ \int \frac {x}{1-x} \, dx=-x-\ln \left (x-1\right ) \]
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