Integrand size = 13, antiderivative size = 67 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=-\frac {\sqrt {a+b x}}{a x}-\frac {b \log \left (\frac {-\sqrt {a}+\sqrt {a+b x}}{\sqrt {a}+\sqrt {a+b x}}\right )}{2 \sqrt {a} x} \]
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Time = 0.02 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.61, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {44, 65, 214} \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=\frac {b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{3/2}}-\frac {\sqrt {a+b x}}{a x} \]
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Rule 44
Rule 65
Rule 214
Rubi steps \begin{align*} \text {integral}& = -\frac {\sqrt {a+b x}}{a x}-\frac {b \int \frac {1}{x \sqrt {a+b x}} \, dx}{2 a} \\ & = -\frac {\sqrt {a+b x}}{a x}-\frac {\text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x}\right )}{a} \\ & = -\frac {\sqrt {a+b x}}{a x}+\frac {b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{3/2}} \\ \end{align*}
Time = 0.08 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.61 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=-\frac {\sqrt {a+b x}}{a x}+\frac {b \text {arctanh}\left (\frac {\sqrt {a+b x}}{\sqrt {a}}\right )}{a^{3/2}} \]
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Time = 0.09 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.51
method | result | size |
risch | \(-\frac {\sqrt {b x +a}}{a x}+\frac {b \,\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{a^{\frac {3}{2}}}\) | \(34\) |
pseudoelliptic | \(\frac {\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right ) b x -\sqrt {b x +a}\, \sqrt {a}}{a^{\frac {3}{2}} x}\) | \(36\) |
derivativedivides | \(2 b \left (-\frac {\sqrt {b x +a}}{2 a b x}+\frac {\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2 a^{\frac {3}{2}}}\right )\) | \(40\) |
default | \(2 b \left (-\frac {\sqrt {b x +a}}{2 a b x}+\frac {\operatorname {arctanh}\left (\frac {\sqrt {b x +a}}{\sqrt {a}}\right )}{2 a^{\frac {3}{2}}}\right )\) | \(40\) |
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Time = 0.24 (sec) , antiderivative size = 93, normalized size of antiderivative = 1.39 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=\left [\frac {\sqrt {a} b x \log \left (\frac {b x + 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) - 2 \, \sqrt {b x + a} a}{2 \, a^{2} x}, -\frac {\sqrt {-a} b x \arctan \left (\frac {\sqrt {b x + a} \sqrt {-a}}{a}\right ) + \sqrt {b x + a} a}{a^{2} x}\right ] \]
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Time = 1.14 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.66 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=- \frac {\sqrt {b} \sqrt {\frac {a}{b x} + 1}}{a \sqrt {x}} + \frac {b \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} \sqrt {x}} \right )}}{a^{\frac {3}{2}}} \]
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Time = 0.30 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.90 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=-\frac {\sqrt {b x + a} b}{{\left (b x + a\right )} a - a^{2}} - \frac {b \log \left (\frac {\sqrt {b x + a} - \sqrt {a}}{\sqrt {b x + a} + \sqrt {a}}\right )}{2 \, a^{\frac {3}{2}}} \]
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Time = 0.27 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.70 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=-\frac {\frac {b^{2} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a} a} + \frac {\sqrt {b x + a} b}{a x}}{b} \]
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Time = 0.06 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.49 \[ \int \frac {1}{x^2 \sqrt {a+b x}} \, dx=\frac {b\,\mathrm {atanh}\left (\frac {\sqrt {a+b\,x}}{\sqrt {a}}\right )}{a^{3/2}}-\frac {\sqrt {a+b\,x}}{a\,x} \]
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