Integrand size = 30, antiderivative size = 79 \[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\frac {\sqrt {2-x^4+x^6} \left (8-28 x^4+8 x^6-3 x^8-14 x^{10}+2 x^{12}\right )}{6 x^6 \left (2+x^6\right )}-\frac {5}{2} \arctan \left (\frac {x^2}{\sqrt {2-x^4+x^6}}\right ) \]
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\[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {\left (2-x^4+x^6\right )^{5/2}}{x^7}+\frac {5 \left (2-x^4+x^6\right )^{5/2}}{4 x}-\frac {3 x^5 \left (2-x^4+x^6\right )^{5/2}}{2 \left (2+x^6\right )^2}-\frac {5 x^5 \left (2-x^4+x^6\right )^{5/2}}{4 \left (2+x^6\right )}\right ) \, dx \\ & = \frac {5}{4} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{x} \, dx-\frac {5}{4} \int \frac {x^5 \left (2-x^4+x^6\right )^{5/2}}{2+x^6} \, dx-\frac {3}{2} \int \frac {x^5 \left (2-x^4+x^6\right )^{5/2}}{\left (2+x^6\right )^2} \, dx-\int \frac {\left (2-x^4+x^6\right )^{5/2}}{x^7} \, dx \\ & = \frac {5}{8} \text {Subst}\left (\int \frac {\left (2-x^2+x^3\right )^{5/2}}{x} \, dx,x,x^2\right )-\frac {3}{4} \text {Subst}\left (\int \frac {x^2 \left (2-x^2+x^3\right )^{5/2}}{\left (2+x^3\right )^2} \, dx,x,x^2\right )-\frac {5}{4} \int \left (\frac {x^2 \left (2-x^4+x^6\right )^{5/2}}{2 \left (-i \sqrt {2}+x^3\right )}+\frac {x^2 \left (2-x^4+x^6\right )^{5/2}}{2 \left (i \sqrt {2}+x^3\right )}\right ) \, dx-\int \frac {\left (2-x^4+x^6\right )^{5/2}}{x^7} \, dx \\ & = -\left (\frac {5}{8} \int \frac {x^2 \left (2-x^4+x^6\right )^{5/2}}{-i \sqrt {2}+x^3} \, dx\right )-\frac {5}{8} \int \frac {x^2 \left (2-x^4+x^6\right )^{5/2}}{i \sqrt {2}+x^3} \, dx+\frac {5}{8} \text {Subst}\left (\int \frac {\left (\frac {52}{27}-\frac {x}{3}+x^3\right )^{5/2}}{\frac {1}{3}+x} \, dx,x,\frac {1}{3} \left (-1+3 x^2\right )\right )-\frac {3}{4} \text {Subst}\left (\int \frac {x^2 \left (2-x^2+x^3\right )^{5/2}}{\left (2+x^3\right )^2} \, dx,x,x^2\right )-\int \frac {\left (2-x^4+x^6\right )^{5/2}}{x^7} \, dx \\ & = -\left (\frac {5}{8} \int \left (-\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (\sqrt [6]{-2}-x\right )}-\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (-\sqrt [6]{-2} \sqrt [3]{-1}-x\right )}-\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (\sqrt [6]{-2} (-1)^{2/3}-x\right )}\right ) \, dx\right )-\frac {5}{8} \int \left (\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (\sqrt [6]{-2}+x\right )}+\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (-\sqrt [6]{-2} \sqrt [3]{-1}+x\right )}+\frac {\left (2-x^4+x^6\right )^{5/2}}{3 \left (\sqrt [6]{-2} (-1)^{2/3}+x\right )}\right ) \, dx-\frac {3}{4} \text {Subst}\left (\int \frac {x^2 \left (2-x^2+x^3\right )^{5/2}}{\left (2+x^3\right )^2} \, dx,x,x^2\right )+\frac {\left (1215 \left (2-x^4+x^6\right )^{5/2}\right ) \text {Subst}\left (\int \frac {\left (\frac {1+\left (26-15 \sqrt {3}\right )^{2/3}}{3 \sqrt [3]{26-15 \sqrt {3}}}+x\right )^{5/2} \left (\frac {1}{9} \left (-1+\frac {1}{\left (26-15 \sqrt {3}\right )^{2/3}}+\left (26-15 \sqrt {3}\right )^{2/3}\right )-\frac {\left (1+\left (26-15 \sqrt {3}\right )^{2/3}\right ) x}{3 \sqrt [3]{26-15 \sqrt {3}}}+x^2\right )^{5/2}}{\frac {1}{3}+x} \, dx,x,\frac {1}{3} \left (-1+3 x^2\right )\right )}{8 \left (\frac {1}{3} \left (-1+\frac {1}{\sqrt [3]{26-15 \sqrt {3}}}+\sqrt [3]{26-15 \sqrt {3}}\right )+x^2\right )^{5/2} \left (-1+\frac {1}{\left (26-15 \sqrt {3}\right )^{2/3}}+\left (26-15 \sqrt {3}\right )^{2/3}-\frac {\left (1+\left (26-15 \sqrt {3}\right )^{2/3}\right ) \left (-1+3 x^2\right )}{\sqrt [3]{26-15 \sqrt {3}}}+\left (-1+3 x^2\right )^2\right )^{5/2}}-\int \frac {\left (2-x^4+x^6\right )^{5/2}}{x^7} \, dx \\ & = \frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{\sqrt [6]{-2}-x} \, dx+\frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{-\sqrt [6]{-2} \sqrt [3]{-1}-x} \, dx+\frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{\sqrt [6]{-2} (-1)^{2/3}-x} \, dx-\frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{\sqrt [6]{-2}+x} \, dx-\frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{-\sqrt [6]{-2} \sqrt [3]{-1}+x} \, dx-\frac {5}{24} \int \frac {\left (2-x^4+x^6\right )^{5/2}}{\sqrt [6]{-2} (-1)^{2/3}+x} \, dx-\frac {3}{4} \text {Subst}\left (\int \frac {x^2 \left (2-x^2+x^3\right )^{5/2}}{\left (2+x^3\right )^2} \, dx,x,x^2\right )+\frac {\left (1215 \left (2-x^4+x^6\right )^{5/2}\right ) \text {Subst}\left (\int \frac {\left (\frac {1+\left (26-15 \sqrt {3}\right )^{2/3}}{3 \sqrt [3]{26-15 \sqrt {3}}}+x\right )^{5/2} \left (\frac {1}{9} \left (-1+\frac {1}{\left (26-15 \sqrt {3}\right )^{2/3}}+\left (26-15 \sqrt {3}\right )^{2/3}\right )-\frac {\left (1+\left (26-15 \sqrt {3}\right )^{2/3}\right ) x}{3 \sqrt [3]{26-15 \sqrt {3}}}+x^2\right )^{5/2}}{\frac {1}{3}+x} \, dx,x,\frac {1}{3} \left (-1+3 x^2\right )\right )}{8 \left (\frac {1}{3} \left (-1+\frac {1}{\sqrt [3]{26-15 \sqrt {3}}}+\sqrt [3]{26-15 \sqrt {3}}\right )+x^2\right )^{5/2} \left (-1+\frac {1}{\left (26-15 \sqrt {3}\right )^{2/3}}+\left (26-15 \sqrt {3}\right )^{2/3}-\frac {\left (1+\left (26-15 \sqrt {3}\right )^{2/3}\right ) \left (-1+3 x^2\right )}{\sqrt [3]{26-15 \sqrt {3}}}+\left (-1+3 x^2\right )^2\right )^{5/2}}-\int \frac {\left (2-x^4+x^6\right )^{5/2}}{x^7} \, dx \\ \end{align*}
Time = 1.69 (sec) , antiderivative size = 79, normalized size of antiderivative = 1.00 \[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\frac {\sqrt {2-x^4+x^6} \left (8-28 x^4+8 x^6-3 x^8-14 x^{10}+2 x^{12}\right )}{6 x^6 \left (2+x^6\right )}-\frac {5}{2} \arctan \left (\frac {x^2}{\sqrt {2-x^4+x^6}}\right ) \]
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Time = 6.24 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.03
method | result | size |
pseudoelliptic | \(\frac {15 \left (x^{12}+2 x^{6}\right ) \arctan \left (\frac {\sqrt {x^{6}-x^{4}+2}}{x^{2}}\right )+2 \left (x^{12}-7 x^{10}-\frac {3}{2} x^{8}+4 x^{6}-14 x^{4}+4\right ) \sqrt {x^{6}-x^{4}+2}}{6 \left (x^{6}+2\right ) x^{6}}\) | \(81\) |
trager | \(\frac {\sqrt {x^{6}-x^{4}+2}\, \left (2 x^{12}-14 x^{10}-3 x^{8}+8 x^{6}-28 x^{4}+8\right )}{6 x^{6} \left (x^{6}+2\right )}+\frac {5 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{6}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{4}+2 \sqrt {x^{6}-x^{4}+2}\, x^{2}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )}{x^{6}+2}\right )}{4}\) | \(119\) |
risch | \(\frac {2 x^{18}-16 x^{16}+11 x^{14}+15 x^{12}-64 x^{10}+22 x^{8}+24 x^{6}-64 x^{4}+16}{6 \left (x^{6}+2\right ) \sqrt {x^{6}-x^{4}+2}\, x^{6}}-\frac {5 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{6}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{4}+2 \sqrt {x^{6}-x^{4}+2}\, x^{2}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )}{x^{6}+2}\right )}{4}\) | \(133\) |
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Time = 0.32 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.22 \[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=-\frac {15 \, {\left (x^{12} + 2 \, x^{6}\right )} \arctan \left (\frac {2 \, \sqrt {x^{6} - x^{4} + 2} x^{2}}{x^{6} - 2 \, x^{4} + 2}\right ) - 2 \, {\left (2 \, x^{12} - 14 \, x^{10} - 3 \, x^{8} + 8 \, x^{6} - 28 \, x^{4} + 8\right )} \sqrt {x^{6} - x^{4} + 2}}{12 \, {\left (x^{12} + 2 \, x^{6}\right )}} \]
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\[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\int \frac {\left (\left (x^{2} + 1\right ) \left (x^{4} - 2 x^{2} + 2\right )\right )^{\frac {5}{2}} \left (x^{3} - 2\right ) \left (x^{3} + 2\right )}{x^{7} \left (x^{6} + 2\right )^{2}}\, dx \]
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\[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\int { \frac {{\left (x^{6} - x^{4} + 2\right )}^{\frac {5}{2}} {\left (x^{6} - 4\right )}}{{\left (x^{6} + 2\right )}^{2} x^{7}} \,d x } \]
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\[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\int { \frac {{\left (x^{6} - x^{4} + 2\right )}^{\frac {5}{2}} {\left (x^{6} - 4\right )}}{{\left (x^{6} + 2\right )}^{2} x^{7}} \,d x } \]
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Timed out. \[ \int \frac {\left (-4+x^6\right ) \left (2-x^4+x^6\right )^{5/2}}{x^7 \left (2+x^6\right )^2} \, dx=\int \frac {\left (x^6-4\right )\,{\left (x^6-x^4+2\right )}^{5/2}}{x^7\,{\left (x^6+2\right )}^2} \,d x \]
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