Integrand size = 56, antiderivative size = 95 \[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}+\frac {\arctan \left (\frac {\sqrt [4]{2} x \left (-b+a x^6\right )^{3/4}}{b-a x^6}\right )}{\sqrt [4]{2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} x \left (-b+a x^6\right )^{3/4}}{b-a x^6}\right )}{\sqrt [4]{2}} \]
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\[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{\sqrt [4]{-b+a x^6}}+\frac {2 b}{x^4 \sqrt [4]{-b+a x^6}}+\frac {a x^2}{\sqrt [4]{-b+a x^6}}+\frac {-3 b-2 x^4}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}}\right ) \, dx \\ & = a \int \frac {x^2}{\sqrt [4]{-b+a x^6}} \, dx+(2 b) \int \frac {1}{x^4 \sqrt [4]{-b+a x^6}} \, dx+\int \frac {1}{\sqrt [4]{-b+a x^6}} \, dx+\int \frac {-3 b-2 x^4}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}} \, dx \\ & = \frac {1}{3} a \text {Subst}\left (\int \frac {1}{\sqrt [4]{-b+a x^2}} \, dx,x,x^3\right )+\frac {1}{3} (2 b) \text {Subst}\left (\int \frac {1}{x^2 \sqrt [4]{-b+a x^2}} \, dx,x,x^3\right )+\frac {\sqrt [4]{1-\frac {a x^6}{b}} \int \frac {1}{\sqrt [4]{1-\frac {a x^6}{b}}} \, dx}{\sqrt [4]{-b+a x^6}}+\int \left (-\frac {3 b}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}}+\frac {2 x^4}{\sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )}\right ) \, dx \\ & = \frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}+\frac {x \sqrt [4]{1-\frac {a x^6}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{4},\frac {7}{6},\frac {a x^6}{b}\right )}{\sqrt [4]{-b+a x^6}}+2 \int \frac {x^4}{\sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx-\frac {1}{3} a \text {Subst}\left (\int \frac {1}{\sqrt [4]{-b+a x^2}} \, dx,x,x^3\right )-(3 b) \int \frac {1}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}} \, dx+\frac {\left (2 \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3} \\ & = \frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}+\frac {x \sqrt [4]{1-\frac {a x^6}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{4},\frac {7}{6},\frac {a x^6}{b}\right )}{\sqrt [4]{-b+a x^6}}+2 \int \frac {x^4}{\sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx-(3 b) \int \frac {1}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}} \, dx-\frac {\left (2 \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3}+\frac {\left (2 \sqrt {b} \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3}-\frac {\left (2 \sqrt {b} \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {1-\frac {x^2}{\sqrt {b}}}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3} \\ & = \frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}+\frac {2 a x^3 \sqrt [4]{-b+a x^6}}{3 \left (\sqrt {b}+\sqrt {-b+a x^6}\right )}-\frac {2 \sqrt [4]{b} \sqrt {\frac {a x^6}{\left (\sqrt {b}+\sqrt {-b+a x^6}\right )^2}} \left (\sqrt {b}+\sqrt {-b+a x^6}\right ) E\left (2 \arctan \left (\frac {\sqrt [4]{-b+a x^6}}{\sqrt [4]{b}}\right )|\frac {1}{2}\right )}{3 x^3}+\frac {\sqrt [4]{b} \sqrt {\frac {a x^6}{\left (\sqrt {b}+\sqrt {-b+a x^6}\right )^2}} \left (\sqrt {b}+\sqrt {-b+a x^6}\right ) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{-b+a x^6}}{\sqrt [4]{b}}\right ),\frac {1}{2}\right )}{3 x^3}+\frac {x \sqrt [4]{1-\frac {a x^6}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{4},\frac {7}{6},\frac {a x^6}{b}\right )}{\sqrt [4]{-b+a x^6}}+2 \int \frac {x^4}{\sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx-(3 b) \int \frac {1}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}} \, dx-\frac {\left (2 \sqrt {b} \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3}+\frac {\left (2 \sqrt {b} \sqrt {\frac {a x^6}{b}}\right ) \text {Subst}\left (\int \frac {1-\frac {x^2}{\sqrt {b}}}{\sqrt {1+\frac {x^4}{b}}} \, dx,x,\sqrt [4]{-b+a x^6}\right )}{3 x^3} \\ & = \frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}+\frac {x \sqrt [4]{1-\frac {a x^6}{b}} \operatorname {Hypergeometric2F1}\left (\frac {1}{6},\frac {1}{4},\frac {7}{6},\frac {a x^6}{b}\right )}{\sqrt [4]{-b+a x^6}}+2 \int \frac {x^4}{\sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx-(3 b) \int \frac {1}{\left (b+2 x^4-a x^6\right ) \sqrt [4]{-b+a x^6}} \, dx \\ \end{align*}
Time = 8.07 (sec) , antiderivative size = 77, normalized size of antiderivative = 0.81 \[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\frac {2 \left (-b+a x^6\right )^{3/4}}{3 x^3}-\frac {\arctan \left (\frac {\sqrt [4]{2} x}{\sqrt [4]{-b+a x^6}}\right )}{\sqrt [4]{2}}-\frac {\text {arctanh}\left (\frac {\sqrt [4]{2} x}{\sqrt [4]{-b+a x^6}}\right )}{\sqrt [4]{2}} \]
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Time = 1.41 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.04
method | result | size |
pseudoelliptic | \(\frac {6 \arctan \left (\frac {\left (a \,x^{6}-b \right )^{\frac {1}{4}} 2^{\frac {3}{4}}}{2 x}\right ) 2^{\frac {3}{4}} x^{3}-3 \ln \left (\frac {-2^{\frac {1}{4}} x -\left (a \,x^{6}-b \right )^{\frac {1}{4}}}{2^{\frac {1}{4}} x -\left (a \,x^{6}-b \right )^{\frac {1}{4}}}\right ) 2^{\frac {3}{4}} x^{3}+8 \left (a \,x^{6}-b \right )^{\frac {3}{4}}}{12 x^{3}}\) | \(99\) |
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Timed out. \[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\int { \frac {{\left (a x^{6} - x^{4} - b\right )} {\left (a x^{6} + 2 \, b\right )}}{{\left (a x^{6} - 2 \, x^{4} - b\right )} {\left (a x^{6} - b\right )}^{\frac {1}{4}} x^{4}} \,d x } \]
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\[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\int { \frac {{\left (a x^{6} - x^{4} - b\right )} {\left (a x^{6} + 2 \, b\right )}}{{\left (a x^{6} - 2 \, x^{4} - b\right )} {\left (a x^{6} - b\right )}^{\frac {1}{4}} x^{4}} \,d x } \]
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Timed out. \[ \int \frac {\left (2 b+a x^6\right ) \left (-b-x^4+a x^6\right )}{x^4 \sqrt [4]{-b+a x^6} \left (-b-2 x^4+a x^6\right )} \, dx=\int \frac {\left (a\,x^6+2\,b\right )\,\left (-a\,x^6+x^4+b\right )}{x^4\,{\left (a\,x^6-b\right )}^{1/4}\,\left (-a\,x^6+2\,x^4+b\right )} \,d x \]
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