Integrand size = 59, antiderivative size = 95 \[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\arctan \left (\frac {x \sqrt {-1-2 x^2-2 x^3-x^8}}{1+2 x^2+2 x^3+x^8}\right )-\sqrt {2} \arctan \left (\frac {\sqrt {2} x \sqrt {-1-2 x^2-2 x^3-x^8}}{1+2 x^2+2 x^3+x^8}\right ) \]
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\[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{2 (1+x)}+\frac {\left (1+4 x-3 x^2+4 x^3-5 x^4+6 x^5+x^6\right ) \sqrt {-1-2 x^2-2 x^3-x^8}}{2 \left (1-x+x^2+x^3-x^4+x^5-x^6+x^7\right )}+\frac {\left (-1-3 x-4 x^6\right ) \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8}\right ) \, dx \\ & = -\left (\frac {1}{2} \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{1+x} \, dx\right )+\frac {1}{2} \int \frac {\left (1+4 x-3 x^2+4 x^3-5 x^4+6 x^5+x^6\right ) \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx+\int \frac {\left (-1-3 x-4 x^6\right ) \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8} \, dx \\ & = -\left (\frac {1}{2} \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{1+x} \, dx\right )+\frac {1}{2} \int \left (\frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}+\frac {4 x \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}-\frac {3 x^2 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}+\frac {4 x^3 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}-\frac {5 x^4 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}+\frac {6 x^5 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}+\frac {x^6 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7}\right ) \, dx+\int \left (\frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{-1-x^2-2 x^3-x^8}-\frac {3 x \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8}-\frac {4 x^6 \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8}\right ) \, dx \\ & = -\left (\frac {1}{2} \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{1+x} \, dx\right )+\frac {1}{2} \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx+\frac {1}{2} \int \frac {x^6 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx-\frac {3}{2} \int \frac {x^2 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx+2 \int \frac {x \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx+2 \int \frac {x^3 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx-\frac {5}{2} \int \frac {x^4 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx+3 \int \frac {x^5 \sqrt {-1-2 x^2-2 x^3-x^8}}{1-x+x^2+x^3-x^4+x^5-x^6+x^7} \, dx-3 \int \frac {x \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8} \, dx-4 \int \frac {x^6 \sqrt {-1-2 x^2-2 x^3-x^8}}{1+x^2+2 x^3+x^8} \, dx+\int \frac {\sqrt {-1-2 x^2-2 x^3-x^8}}{-1-x^2-2 x^3-x^8} \, dx \\ \end{align*}
Time = 0.33 (sec) , antiderivative size = 62, normalized size of antiderivative = 0.65 \[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=-\arctan \left (\frac {x}{\sqrt {-1-2 x^2-2 x^3-x^8}}\right )+\sqrt {2} \arctan \left (\frac {\sqrt {2} x}{\sqrt {-1-2 x^2-2 x^3-x^8}}\right ) \]
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Time = 6.34 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.62
method | result | size |
pseudoelliptic | \(\arctan \left (\frac {\sqrt {-x^{8}-2 x^{3}-2 x^{2}-1}}{x}\right )-\sqrt {2}\, \arctan \left (\frac {\sqrt {-x^{8}-2 x^{3}-2 x^{2}-1}\, \sqrt {2}}{2 x}\right )\) | \(59\) |
trager | \(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) \ln \left (\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) x^{8}+2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) x^{3}+4 \operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right ) x^{2}-4 \sqrt {-x^{8}-2 x^{3}-2 x^{2}-1}\, x +\operatorname {RootOf}\left (\textit {\_Z}^{2}+2\right )}{\left (1+x \right ) \left (x^{7}-x^{6}+x^{5}-x^{4}+x^{3}+x^{2}-x +1\right )}\right )}{2}-\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\frac {-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{8}-2 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{3}-3 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) x^{2}+2 \sqrt {-x^{8}-2 x^{3}-2 x^{2}-1}\, x -\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right )}{x^{8}+2 x^{3}+x^{2}+1}\right )}{2}\) | \(197\) |
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Result contains complex when optimal does not.
Time = 0.58 (sec) , antiderivative size = 241, normalized size of antiderivative = 2.54 \[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=-\frac {1}{4} \, \sqrt {-2} \log \left (-\frac {2 \, {\left (\sqrt {-2} {\left (x^{8} + 2 \, x^{3} + 4 \, x^{2} + 1\right )} + 4 \, \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1} x\right )}}{x^{8} + 2 \, x^{3} + 1}\right ) + \frac {1}{4} \, \sqrt {-2} \log \left (\frac {2 \, {\left (\sqrt {-2} {\left (x^{8} + 2 \, x^{3} + 4 \, x^{2} + 1\right )} - 4 \, \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1} x\right )}}{x^{8} + 2 \, x^{3} + 1}\right ) - \frac {1}{4} i \, \log \left (\frac {i \, x^{8} + 2 i \, x^{3} + 3 i \, x^{2} - 2 \, \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1} x + i}{x^{8} + 2 \, x^{3} + x^{2} + 1}\right ) + \frac {1}{4} i \, \log \left (\frac {-i \, x^{8} - 2 i \, x^{3} - 3 i \, x^{2} - 2 \, \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1} x - i}{x^{8} + 2 \, x^{3} + x^{2} + 1}\right ) \]
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\[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\int \frac {\left (3 x^{8} + x^{3} - 1\right ) \sqrt {- x^{8} - 2 x^{3} - 2 x^{2} - 1}}{\left (x + 1\right ) \left (x^{8} + 2 x^{3} + x^{2} + 1\right ) \left (x^{7} - x^{6} + x^{5} - x^{4} + x^{3} + x^{2} - x + 1\right )}\, dx \]
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\[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\int { \frac {{\left (3 \, x^{8} + x^{3} - 1\right )} \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1}}{{\left (x^{8} + 2 \, x^{3} + x^{2} + 1\right )} {\left (x^{8} + 2 \, x^{3} + 1\right )}} \,d x } \]
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\[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\int { \frac {{\left (3 \, x^{8} + x^{3} - 1\right )} \sqrt {-x^{8} - 2 \, x^{3} - 2 \, x^{2} - 1}}{{\left (x^{8} + 2 \, x^{3} + x^{2} + 1\right )} {\left (x^{8} + 2 \, x^{3} + 1\right )}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {-1-2 x^2-2 x^3-x^8} \left (-1+x^3+3 x^8\right )}{\left (1+2 x^3+x^8\right ) \left (1+x^2+2 x^3+x^8\right )} \, dx=\int \frac {\left (3\,x^8+x^3-1\right )\,\sqrt {-x^8-2\,x^3-2\,x^2-1}}{\left (x^8+2\,x^3+1\right )\,\left (x^8+2\,x^3+x^2+1\right )} \,d x \]
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