Integrand size = 30, antiderivative size = 30 \[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\frac {\sqrt {-1+x^6}}{x^2}-\text {arctanh}\left (\frac {x^2}{\sqrt {-1+x^6}}\right ) \]
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\[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (-\frac {2 \sqrt {-1+x^6}}{x^3}+\frac {x \left (2-3 x^2\right ) \sqrt {-1+x^6}}{1+x^4-x^6}\right ) \, dx \\ & = -\left (2 \int \frac {\sqrt {-1+x^6}}{x^3} \, dx\right )+\int \frac {x \left (2-3 x^2\right ) \sqrt {-1+x^6}}{1+x^4-x^6} \, dx \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {(2-3 x) \sqrt {-1+x^3}}{1+x^2-x^3} \, dx,x,x^2\right )-\text {Subst}\left (\int \frac {\sqrt {-1+x^3}}{x^2} \, dx,x,x^2\right ) \\ & = \frac {\sqrt {-1+x^6}}{x^2}+\frac {1}{2} \text {Subst}\left (\int \left (-\frac {2 \sqrt {-1+x^3}}{-1-x^2+x^3}+\frac {3 x \sqrt {-1+x^3}}{-1-x^2+x^3}\right ) \, dx,x,x^2\right )-\frac {3}{2} \text {Subst}\left (\int \frac {x}{\sqrt {-1+x^3}} \, dx,x,x^2\right ) \\ & = \frac {\sqrt {-1+x^6}}{x^2}+\frac {3}{2} \text {Subst}\left (\int \frac {1+\sqrt {3}-x}{\sqrt {-1+x^3}} \, dx,x,x^2\right )+\frac {3}{2} \text {Subst}\left (\int \frac {x \sqrt {-1+x^3}}{-1-x^2+x^3} \, dx,x,x^2\right )-\frac {1}{2} \left (3 \left (1+\sqrt {3}\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {-1+x^3}} \, dx,x,x^2\right )-\text {Subst}\left (\int \frac {\sqrt {-1+x^3}}{-1-x^2+x^3} \, dx,x,x^2\right ) \\ & = \frac {\sqrt {-1+x^6}}{x^2}+\frac {3 \sqrt {-1+x^6}}{1-\sqrt {3}-x^2}-\frac {3 \sqrt [4]{3} \sqrt {2+\sqrt {3}} \left (1-x^2\right ) \sqrt {\frac {1+x^2+x^4}{\left (1-\sqrt {3}-x^2\right )^2}} E\left (\arcsin \left (\frac {1+\sqrt {3}-x^2}{1-\sqrt {3}-x^2}\right )|-7+4 \sqrt {3}\right )}{2 \sqrt {-\frac {1-x^2}{\left (1-\sqrt {3}-x^2\right )^2}} \sqrt {-1+x^6}}+\frac {\sqrt {2} 3^{3/4} \left (1-x^2\right ) \sqrt {\frac {1+x^2+x^4}{\left (1-\sqrt {3}-x^2\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {1+\sqrt {3}-x^2}{1-\sqrt {3}-x^2}\right ),-7+4 \sqrt {3}\right )}{\sqrt {-\frac {1-x^2}{\left (1-\sqrt {3}-x^2\right )^2}} \sqrt {-1+x^6}}+\frac {3}{2} \text {Subst}\left (\int \frac {x \sqrt {-1+x^3}}{-1-x^2+x^3} \, dx,x,x^2\right )-\text {Subst}\left (\int \frac {\sqrt {-1+x^3}}{-1-x^2+x^3} \, dx,x,x^2\right ) \\ \end{align*}
Time = 5.32 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\frac {\sqrt {-1+x^6}}{x^2}-\text {arctanh}\left (\frac {x^2}{\sqrt {-1+x^6}}\right ) \]
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Time = 1.97 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.63
method | result | size |
trager | \(\frac {\sqrt {x^{6}-1}}{x^{2}}-\frac {\ln \left (\frac {x^{6}+x^{4}+2 x^{2} \sqrt {x^{6}-1}-1}{x^{6}-x^{4}-1}\right )}{2}\) | \(49\) |
risch | \(\frac {\sqrt {x^{6}-1}}{x^{2}}+\frac {\ln \left (-\frac {-x^{6}-x^{4}+2 x^{2} \sqrt {x^{6}-1}+1}{x^{6}-x^{4}-1}\right )}{2}\) | \(54\) |
pseudoelliptic | \(\frac {\ln \left (\frac {-x^{2}+\sqrt {x^{6}-1}}{x^{2}}\right ) x^{2}-\ln \left (\frac {x^{2}+\sqrt {x^{6}-1}}{x^{2}}\right ) x^{2}+2 \sqrt {x^{6}-1}}{2 x^{2}}\) | \(59\) |
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Leaf count of result is larger than twice the leaf count of optimal. 53 vs. \(2 (26) = 52\).
Time = 0.27 (sec) , antiderivative size = 53, normalized size of antiderivative = 1.77 \[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\frac {x^{2} \log \left (\frac {x^{6} + x^{4} - 2 \, \sqrt {x^{6} - 1} x^{2} - 1}{x^{6} - x^{4} - 1}\right ) + 2 \, \sqrt {x^{6} - 1}}{2 \, x^{2}} \]
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Timed out. \[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\text {Timed out} \]
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\[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\int { \frac {{\left (x^{6} + 2\right )} \sqrt {x^{6} - 1}}{{\left (x^{6} - x^{4} - 1\right )} x^{3}} \,d x } \]
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\[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\int { \frac {{\left (x^{6} + 2\right )} \sqrt {x^{6} - 1}}{{\left (x^{6} - x^{4} - 1\right )} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {-1+x^6} \left (2+x^6\right )}{x^3 \left (-1-x^4+x^6\right )} \, dx=\int -\frac {\sqrt {x^6-1}\,\left (x^6+2\right )}{x^3\,\left (-x^6+x^4+1\right )} \,d x \]
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