Integrand size = 13, antiderivative size = 47 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{15} \sqrt {1+x} \sqrt {1+\sqrt {1+x}}+\frac {4}{15} (1+3 x) \sqrt {1+\sqrt {1+x}} \]
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Time = 0.01 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.74, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {253, 196, 45} \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{5} \left (\sqrt {x+1}+1\right )^{5/2}-\frac {4}{3} \left (\sqrt {x+1}+1\right )^{3/2} \]
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Rule 45
Rule 196
Rule 253
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int \sqrt {1+\sqrt {x}} \, dx,x,1+x\right ) \\ & = 2 \text {Subst}\left (\int x \sqrt {1+x} \, dx,x,\sqrt {1+x}\right ) \\ & = 2 \text {Subst}\left (\int \left (-\sqrt {1+x}+(1+x)^{3/2}\right ) \, dx,x,\sqrt {1+x}\right ) \\ & = -\frac {4}{3} \left (1+\sqrt {1+x}\right )^{3/2}+\frac {4}{5} \left (1+\sqrt {1+x}\right )^{5/2} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.60 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{15} \left (1+\sqrt {1+x}\right )^{3/2} \left (-2+3 \sqrt {1+x}\right ) \]
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Result contains higher order function than in optimal. Order 5 vs. order 2.
Time = 0.38 (sec) , antiderivative size = 17, normalized size of antiderivative = 0.36
method | result | size |
meijerg | \(\sqrt {2}\, x \operatorname {hypergeom}\left (\left [-\frac {1}{4}, \frac {1}{4}, 1\right ], \left [\frac {1}{2}, 2\right ], -x \right )\) | \(17\) |
derivativedivides | \(\frac {4 \left (\sqrt {1+x}+1\right )^{\frac {5}{2}}}{5}-\frac {4 \left (\sqrt {1+x}+1\right )^{\frac {3}{2}}}{3}\) | \(24\) |
default | \(\frac {4 \left (\sqrt {1+x}+1\right )^{\frac {5}{2}}}{5}-\frac {4 \left (\sqrt {1+x}+1\right )^{\frac {3}{2}}}{3}\) | \(24\) |
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none
Time = 0.25 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.45 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{15} \, {\left (3 \, x + \sqrt {x + 1} + 1\right )} \sqrt {\sqrt {x + 1} + 1} \]
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Leaf count of result is larger than twice the leaf count of optimal. 184 vs. \(2 (41) = 82\).
Time = 0.55 (sec) , antiderivative size = 184, normalized size of antiderivative = 3.91 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {12 \left (x + 1\right )^{\frac {7}{2}} \sqrt {\sqrt {x + 1} + 1}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} - \frac {4 \left (x + 1\right )^{\frac {5}{2}} \sqrt {\sqrt {x + 1} + 1}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} + \frac {8 \left (x + 1\right )^{\frac {5}{2}}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} + \frac {16 \left (x + 1\right )^{3} \sqrt {\sqrt {x + 1} + 1}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} - \frac {8 \left (x + 1\right )^{2} \sqrt {\sqrt {x + 1} + 1}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} + \frac {8 \left (x + 1\right )^{2}}{15 \left (x + 1\right )^{\frac {5}{2}} + 15 \left (x + 1\right )^{2}} \]
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Result contains higher order function than in optimal. Order 3 vs. order 2.
Time = 0.18 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.49 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{5} \, {\left (\sqrt {x + 1} + 1\right )}^{\frac {5}{2}} - \frac {4}{3} \, {\left (\sqrt {x + 1} + 1\right )}^{\frac {3}{2}} \]
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Result contains higher order function than in optimal. Order 3 vs. order 2.
Time = 0.28 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.49 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\frac {4}{5} \, {\left (\sqrt {x + 1} + 1\right )}^{\frac {5}{2}} - \frac {4}{3} \, {\left (\sqrt {x + 1} + 1\right )}^{\frac {3}{2}} \]
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Time = 5.21 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.34 \[ \int \sqrt {1+\sqrt {1+x}} \, dx=\left (x+1\right )\,{{}}_2{\mathrm {F}}_1\left (-\frac {1}{2},2;\ 3;\ -\sqrt {x+1}\right ) \]
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