Integrand size = 19, antiderivative size = 47 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=2 \sqrt {1+\sqrt {1+x^2}}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {1+\sqrt {1+x^2}}}{\sqrt {2}}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.316, Rules used = {378, 1412, 797, 81, 65, 213} \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=2 \sqrt {\sqrt {x^2+1}+1}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {\sqrt {x^2+1}+1}}{\sqrt {2}}\right ) \]
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Rule 65
Rule 81
Rule 213
Rule 378
Rule 797
Rule 1412
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {\sqrt {1+\sqrt {1+x}}}{x} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {\sqrt {1+\sqrt {x}}}{-1+x} \, dx,x,1+x^2\right ) \\ & = \text {Subst}\left (\int \frac {x \sqrt {1+x}}{-1+x^2} \, dx,x,\sqrt {1+x^2}\right ) \\ & = \text {Subst}\left (\int \frac {x}{(-1+x) \sqrt {1+x}} \, dx,x,\sqrt {1+x^2}\right ) \\ & = 2 \sqrt {1+\sqrt {1+x^2}}+\text {Subst}\left (\int \frac {1}{(-1+x) \sqrt {1+x}} \, dx,x,\sqrt {1+x^2}\right ) \\ & = 2 \sqrt {1+\sqrt {1+x^2}}+2 \text {Subst}\left (\int \frac {1}{-2+x^2} \, dx,x,\sqrt {1+\sqrt {1+x^2}}\right ) \\ & = 2 \sqrt {1+\sqrt {1+x^2}}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {1+\sqrt {1+x^2}}}{\sqrt {2}}\right ) \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 47, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=2 \sqrt {1+\sqrt {1+x^2}}-\sqrt {2} \text {arctanh}\left (\frac {\sqrt {1+\sqrt {1+x^2}}}{\sqrt {2}}\right ) \]
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Result contains higher order function than in optimal. Order 5 vs. order 3.
Time = 0.13 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.09
method | result | size |
meijerg | \(-\frac {-\frac {\sqrt {\pi }\, \sqrt {2}\, x^{2} \operatorname {hypergeom}\left (\left [\frac {3}{4}, 1, 1, \frac {5}{4}\right ], \left [\frac {3}{2}, 2, 2\right ], -x^{2}\right )}{2}-4 \left (-4 \ln \left (2\right )+4+2 \ln \left (x \right )\right ) \sqrt {\pi }\, \sqrt {2}}{8 \sqrt {\pi }}\) | \(51\) |
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none
Time = 0.53 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.43 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=\frac {1}{2} \, \sqrt {2} \log \left (-\frac {x^{2} - 2 \, {\left (\sqrt {2} \sqrt {x^{2} + 1} + \sqrt {2}\right )} \sqrt {\sqrt {x^{2} + 1} + 1} + 4 \, \sqrt {x^{2} + 1} + 4}{x^{2}}\right ) + 2 \, \sqrt {\sqrt {x^{2} + 1} + 1} \]
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Result contains complex when optimal does not.
Time = 1.85 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.04 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=\frac {x^{2} \Gamma \left (\frac {3}{4}\right ) \Gamma \left (\frac {5}{4}\right ) {{}_{4}F_{3}\left (\begin {matrix} \frac {3}{4}, 1, 1, \frac {5}{4} \\ \frac {3}{2}, 2, 2 \end {matrix}\middle | {x^{2} e^{i \pi }} \right )}}{4 \pi } + \frac {\log {\left (x^{2} \right )} \Gamma \left (\frac {1}{4}\right ) \Gamma \left (\frac {3}{4}\right )}{2 \pi } \]
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none
Time = 0.28 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.19 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=\frac {1}{2} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - \sqrt {\sqrt {x^{2} + 1} + 1}}{\sqrt {2} + \sqrt {\sqrt {x^{2} + 1} + 1}}\right ) + 2 \, \sqrt {\sqrt {x^{2} + 1} + 1} \]
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none
Time = 0.29 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.19 \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=\frac {1}{2} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - \sqrt {\sqrt {x^{2} + 1} + 1}}{\sqrt {2} + \sqrt {\sqrt {x^{2} + 1} + 1}}\right ) + 2 \, \sqrt {\sqrt {x^{2} + 1} + 1} \]
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Timed out. \[ \int \frac {\sqrt {1+\sqrt {1+x^2}}}{x} \, dx=\int \frac {\sqrt {\sqrt {x^2+1}+1}}{x} \,d x \]
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