Integrand size = 46, antiderivative size = 33 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {3-e^2+x+(4+x)^2}{2-\frac {9}{3+\frac {1}{4} \left (-9+x^2\right )}} \]
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Time = 0.03 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.03, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {6, 28, 1828, 1600} \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {x^2}{2}-\frac {9 \left (9 x-e^2+34\right )}{15-x^2}+\frac {9 x}{2} \]
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Rule 6
Rule 28
Rule 1600
Rule 1828
Rubi steps \begin{align*} \text {integral}& = \int \frac {-405+\left (-774+36 e^2\right ) x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx \\ & = 2 \int \frac {-405+\left (-774+36 e^2\right ) x-432 x^2-60 x^3+9 x^4+2 x^5}{\left (-30+2 x^2\right )^2} \, dx \\ & = -\frac {9 \left (34-e^2+9 x\right )}{15-x^2}+\frac {1}{30} \int \frac {-4050-900 x+270 x^2+60 x^3}{-30+2 x^2} \, dx \\ & = -\frac {9 \left (34-e^2+9 x\right )}{15-x^2}+\frac {1}{30} \int (135+30 x) \, dx \\ & = \frac {9 x}{2}+\frac {x^2}{2}-\frac {9 \left (34-e^2+9 x\right )}{15-x^2} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 28, normalized size of antiderivative = 0.85 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {1}{2} \left (9 x+x^2-\frac {18 \left (-34+e^2-9 x\right )}{-15+x^2}\right ) \]
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Time = 0.38 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82
method | result | size |
risch | \(\frac {x^{2}}{2}+\frac {9 x}{2}+\frac {81 x +306-9 \,{\mathrm e}^{2}}{x^{2}-15}\) | \(27\) |
default | \(\frac {x^{2}}{2}+\frac {9 x}{2}+\frac {81 x +306-9 \,{\mathrm e}^{2}}{x^{2}-15}\) | \(28\) |
norman | \(\frac {\frac {27 x}{2}+\frac {9 x^{3}}{2}+\frac {x^{4}}{2}+\frac {387}{2}-9 \,{\mathrm e}^{2}}{x^{2}-15}\) | \(28\) |
gosper | \(-\frac {-x^{4}-9 x^{3}+18 \,{\mathrm e}^{2}-27 x -387}{2 \left (x^{2}-15\right )}\) | \(29\) |
parallelrisch | \(-\frac {-x^{4}-9 x^{3}+18 \,{\mathrm e}^{2}-27 x -387}{2 \left (x^{2}-15\right )}\) | \(29\) |
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Time = 0.23 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.94 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {x^{4} + 9 \, x^{3} - 15 \, x^{2} + 27 \, x - 18 \, e^{2} + 612}{2 \, {\left (x^{2} - 15\right )}} \]
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Time = 0.19 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.73 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {x^{2}}{2} + \frac {9 x}{2} + \frac {81 x - 9 e^{2} + 306}{x^{2} - 15} \]
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Time = 0.19 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {1}{2} \, x^{2} + \frac {9}{2} \, x + \frac {9 \, {\left (9 \, x - e^{2} + 34\right )}}{x^{2} - 15} \]
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Time = 0.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.82 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {1}{2} \, x^{2} + \frac {9}{2} \, x + \frac {9 \, {\left (9 \, x - e^{2} + 34\right )}}{x^{2} - 15} \]
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Time = 0.09 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.79 \[ \int \frac {-405-774 x+36 e^2 x-432 x^2-60 x^3+9 x^4+2 x^5}{450-60 x^2+2 x^4} \, dx=\frac {9\,x}{2}+\frac {x^2}{2}+\frac {81\,x-9\,{\mathrm {e}}^2+306}{x^2-15} \]
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