Integrand size = 209, antiderivative size = 33 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\frac {2 x}{\log \left (\frac {x^2}{5}+\log \left (\frac {25 x^2}{\left (2-2 \left (-4 x+x^2\right )\right )^2}\right )\right )} \]
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\[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-20-24 x^2-16 x^3+4 x^4-2 \left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {x^2}{5}+\log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx \\ & = \int \left (\frac {4 x^4}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {20}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {24 x^2}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {16 x^3}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {2 x^2}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {8 x^3}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {2 x^4}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {10 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {40 x \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}+\frac {10 x^2 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )}\right ) \, dx \\ & = 2 \int \frac {x^2}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+2 \int \frac {x^4}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+4 \int \frac {x^4}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+8 \int \frac {x^3}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+10 \int \frac {\log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+10 \int \frac {x^2 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+16 \int \frac {x^3}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+20 \int \frac {1}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+24 \int \frac {x^2}{\left (-1-4 x+x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx+40 \int \frac {x \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )}{\left (1+4 x-x^2\right ) \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )\right )} \, dx \\ & = \text {Too large to display} \\ \end{align*}
Time = 0.17 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.97 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\frac {2 x}{\log \left (\frac {x^2}{5}+\log \left (\frac {25 x^2}{4 \left (-1-4 x+x^2\right )^2}\right )\right )} \]
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Time = 7.79 (sec) , antiderivative size = 39, normalized size of antiderivative = 1.18
method | result | size |
parallelrisch | \(\frac {2 x}{\ln \left (\ln \left (\frac {25 x^{2}}{4 \left (x^{4}-8 x^{3}+14 x^{2}+8 x +1\right )}\right )+\frac {x^{2}}{5}\right )}\) | \(39\) |
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Time = 0.25 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.15 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\frac {2 \, x}{\log \left (\frac {1}{5} \, x^{2} + \log \left (\frac {25 \, x^{2}}{4 \, {\left (x^{4} - 8 \, x^{3} + 14 \, x^{2} + 8 \, x + 1\right )}}\right )\right )} \]
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Time = 0.23 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.09 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\frac {2 x}{\log {\left (\frac {x^{2}}{5} + \log {\left (\frac {25 x^{2}}{4 x^{4} - 32 x^{3} + 56 x^{2} + 32 x + 4} \right )} \right )}} \]
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Time = 0.32 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.15 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=-\frac {2 \, x}{\log \left (5\right ) - \log \left (x^{2} + 10 \, \log \left (5\right ) - 10 \, \log \left (2\right ) - 10 \, \log \left (x^{2} - 4 \, x - 1\right ) + 10 \, \log \left (x\right )\right )} \]
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\[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=\int { -\frac {2 \, {\left (2 \, x^{4} - 8 \, x^{3} - 12 \, x^{2} - {\left (x^{4} - 4 \, x^{3} - x^{2} + 5 \, {\left (x^{2} - 4 \, x - 1\right )} \log \left (\frac {25 \, x^{2}}{4 \, {\left (x^{4} - 8 \, x^{3} + 14 \, x^{2} + 8 \, x + 1\right )}}\right )\right )} \log \left (\frac {1}{5} \, x^{2} + \log \left (\frac {25 \, x^{2}}{4 \, {\left (x^{4} - 8 \, x^{3} + 14 \, x^{2} + 8 \, x + 1\right )}}\right )\right ) - 10\right )}}{{\left (x^{4} - 4 \, x^{3} - x^{2} + 5 \, {\left (x^{2} - 4 \, x - 1\right )} \log \left (\frac {25 \, x^{2}}{4 \, {\left (x^{4} - 8 \, x^{3} + 14 \, x^{2} + 8 \, x + 1\right )}}\right )\right )} \log \left (\frac {1}{5} \, x^{2} + \log \left (\frac {25 \, x^{2}}{4 \, {\left (x^{4} - 8 \, x^{3} + 14 \, x^{2} + 8 \, x + 1\right )}}\right )\right )^{2}} \,d x } \]
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Time = 8.44 (sec) , antiderivative size = 138, normalized size of antiderivative = 4.18 \[ \int \frac {20+24 x^2+16 x^3-4 x^4+\left (-2 x^2-8 x^3+2 x^4+\left (-10-40 x+10 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log \left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )}{\left (-x^2-4 x^3+x^4+\left (-5-20 x+5 x^2\right ) \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right ) \log ^2\left (\frac {1}{5} \left (x^2+5 \log \left (\frac {25 x^2}{4+32 x+56 x^2-32 x^3+4 x^4}\right )\right )\right )} \, dx=x-\frac {5\,x}{-x^4+4\,x^3+6\,x^2+5}-\frac {6\,x^3}{-x^4+4\,x^3+6\,x^2+5}-\frac {4\,x^4}{-x^4+4\,x^3+6\,x^2+5}+\frac {x^5}{-x^4+4\,x^3+6\,x^2+5}+\frac {2\,x}{\ln \left (\ln \left (x^2\right )+2\,\ln \left (5\right )+\ln \left (\frac {1}{4\,x^4-32\,x^3+56\,x^2+32\,x+4}\right )+\frac {x^2}{5}\right )} \]
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