Integrand size = 68, antiderivative size = 17 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\frac {4}{x^4}}}{\log (\log (6+2 x))} \]
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\[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{x^5 (3+x) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx \\ & = \int \left (\frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{3 x^5 \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{27 x^3 \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{243 x \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{9 x^4 \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{81 x^2 \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{243 (3+x) \log (6+2 x) \log ^2(\log (6+2 x))}\right ) \, dx \\ & = \frac {1}{243} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{243} \int \frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{(3+x) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{81} \int \frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^2 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{27} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^3 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{9} \int \frac {e^{\frac {4}{x^4}} \left (x^5+48 \log (2 (3+x)) \log (\log (2 (3+x)))+16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^4 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{3} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-48 \log (2 (3+x)) \log (\log (2 (3+x)))-16 x \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^5 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx \\ & = \frac {1}{243} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{243} \int \frac {e^{\frac {4}{x^4}} \left (x^5+16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{(3+x) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{81} \int \frac {e^{\frac {4}{x^4}} \left (x^5+16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^2 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{27} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^3 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{9} \int \frac {e^{\frac {4}{x^4}} \left (x^5+16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^4 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{3} \int \frac {e^{\frac {4}{x^4}} \left (-x^5-16 (3+x) \log (2 (3+x)) \log (\log (2 (3+x)))\right )}{x^5 \log (6+2 x) \log ^2(\log (6+2 x))} \, dx \\ & = \frac {1}{243} \int \left (-\frac {e^{\frac {4}{x^4}} x^4}{\log (6+2 x) \log ^2(\log (6+2 x))}-\frac {16 e^{\frac {4}{x^4}}}{\log (\log (6+2 x))}-\frac {48 e^{\frac {4}{x^4}}}{x \log (\log (6+2 x))}\right ) \, dx+\frac {1}{243} \int \left (\frac {e^{\frac {4}{x^4}} x^5}{(3+x) \log (6+2 x) \log ^2(\log (6+2 x))}+\frac {48 e^{\frac {4}{x^4}}}{(3+x) \log (\log (6+2 x))}+\frac {16 e^{\frac {4}{x^4}} x}{(3+x) \log (\log (6+2 x))}\right ) \, dx+\frac {1}{81} \int \left (\frac {e^{\frac {4}{x^4}} x^3}{\log (6+2 x) \log ^2(\log (6+2 x))}+\frac {48 e^{\frac {4}{x^4}}}{x^2 \log (\log (6+2 x))}+\frac {16 e^{\frac {4}{x^4}}}{x \log (\log (6+2 x))}\right ) \, dx+\frac {1}{27} \int \left (-\frac {e^{\frac {4}{x^4}} x^2}{\log (6+2 x) \log ^2(\log (6+2 x))}-\frac {48 e^{\frac {4}{x^4}}}{x^3 \log (\log (6+2 x))}-\frac {16 e^{\frac {4}{x^4}}}{x^2 \log (\log (6+2 x))}\right ) \, dx+\frac {1}{9} \int \left (\frac {e^{\frac {4}{x^4}} x}{\log (6+2 x) \log ^2(\log (6+2 x))}+\frac {48 e^{\frac {4}{x^4}}}{x^4 \log (\log (6+2 x))}+\frac {16 e^{\frac {4}{x^4}}}{x^3 \log (\log (6+2 x))}\right ) \, dx+\frac {1}{3} \int \left (-\frac {e^{\frac {4}{x^4}}}{\log (6+2 x) \log ^2(\log (6+2 x))}-\frac {48 e^{\frac {4}{x^4}}}{x^5 \log (\log (6+2 x))}-\frac {16 e^{\frac {4}{x^4}}}{x^4 \log (\log (6+2 x))}\right ) \, dx \\ & = -\left (\frac {1}{243} \int \frac {e^{\frac {4}{x^4}} x^4}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx\right )+\frac {1}{243} \int \frac {e^{\frac {4}{x^4}} x^5}{(3+x) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{81} \int \frac {e^{\frac {4}{x^4}} x^3}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx-\frac {1}{27} \int \frac {e^{\frac {4}{x^4}} x^2}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx-\frac {16}{243} \int \frac {e^{\frac {4}{x^4}}}{\log (\log (6+2 x))} \, dx+\frac {16}{243} \int \frac {e^{\frac {4}{x^4}} x}{(3+x) \log (\log (6+2 x))} \, dx+\frac {1}{9} \int \frac {e^{\frac {4}{x^4}} x}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {16}{81} \int \frac {e^{\frac {4}{x^4}}}{(3+x) \log (\log (6+2 x))} \, dx-\frac {1}{3} \int \frac {e^{\frac {4}{x^4}}}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx-16 \int \frac {e^{\frac {4}{x^4}}}{x^5 \log (\log (6+2 x))} \, dx \\ & = \frac {1}{243} \int \left (\frac {81 e^{\frac {4}{x^4}}}{\log (6+2 x) \log ^2(\log (6+2 x))}+\frac {243 e^{\frac {4}{x^4}}}{(-3-x) \log (6+2 x) \log ^2(\log (6+2 x))}-\frac {27 e^{\frac {4}{x^4}} x}{\log (6+2 x) \log ^2(\log (6+2 x))}+\frac {9 e^{\frac {4}{x^4}} x^2}{\log (6+2 x) \log ^2(\log (6+2 x))}-\frac {3 e^{\frac {4}{x^4}} x^3}{\log (6+2 x) \log ^2(\log (6+2 x))}+\frac {e^{\frac {4}{x^4}} x^4}{\log (6+2 x) \log ^2(\log (6+2 x))}\right ) \, dx-\frac {1}{243} \int \frac {e^{\frac {4}{x^4}} x^4}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {1}{81} \int \frac {e^{\frac {4}{x^4}} x^3}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx-\frac {1}{27} \int \frac {e^{\frac {4}{x^4}} x^2}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {16}{243} \int \left (\frac {e^{\frac {4}{x^4}}}{\log (\log (6+2 x))}+\frac {3 e^{\frac {4}{x^4}}}{(-3-x) \log (\log (6+2 x))}\right ) \, dx-\frac {16}{243} \int \frac {e^{\frac {4}{x^4}}}{\log (\log (6+2 x))} \, dx+\frac {1}{9} \int \frac {e^{\frac {4}{x^4}} x}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx+\frac {16}{81} \int \frac {e^{\frac {4}{x^4}}}{(3+x) \log (\log (6+2 x))} \, dx-\frac {1}{3} \int \frac {e^{\frac {4}{x^4}}}{\log (6+2 x) \log ^2(\log (6+2 x))} \, dx-16 \int \frac {e^{\frac {4}{x^4}}}{x^5 \log (\log (6+2 x))} \, dx \\ & = \frac {16}{81} \int \frac {e^{\frac {4}{x^4}}}{(-3-x) \log (\log (6+2 x))} \, dx+\frac {16}{81} \int \frac {e^{\frac {4}{x^4}}}{(3+x) \log (\log (6+2 x))} \, dx-16 \int \frac {e^{\frac {4}{x^4}}}{x^5 \log (\log (6+2 x))} \, dx+\int \frac {e^{\frac {4}{x^4}}}{(-3-x) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\frac {4}{x^4}}}{\log (\log (2 (3+x)))} \]
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Time = 49.26 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00
method | result | size |
risch | \(\frac {{\mathrm e}^{\frac {4}{x^{4}}}}{\ln \left (\ln \left (2 x +6\right )\right )}\) | \(17\) |
parallelrisch | \(\frac {{\mathrm e}^{\frac {4}{x^{4}}}}{\ln \left (\ln \left (2 x +6\right )\right )}\) | \(19\) |
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Time = 0.24 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.94 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\left (\frac {4}{x^{4}}\right )}}{\log \left (\log \left (2 \, x + 6\right )\right )} \]
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Time = 0.16 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.82 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\frac {4}{x^{4}}}}{\log {\left (\log {\left (2 x + 6 \right )} \right )}} \]
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Time = 0.31 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.00 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\left (\frac {4}{x^{4}}\right )}}{\log \left (\log \left (2\right ) + \log \left (x + 3\right )\right )} \]
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Time = 0.28 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.94 \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\frac {e^{\left (\frac {4}{x^{4}}\right )}}{\log \left (\log \left (2 \, x + 6\right )\right )} \]
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Timed out. \[ \int \frac {-e^{\frac {4}{x^4}} x^5+e^{\frac {4}{x^4}} (-48-16 x) \log (6+2 x) \log (\log (6+2 x))}{\left (3 x^5+x^6\right ) \log (6+2 x) \log ^2(\log (6+2 x))} \, dx=\int -\frac {x^5\,{\mathrm {e}}^{\frac {4}{x^4}}+\ln \left (\ln \left (2\,x+6\right )\right )\,{\mathrm {e}}^{\frac {4}{x^4}}\,\ln \left (2\,x+6\right )\,\left (16\,x+48\right )}{{\ln \left (\ln \left (2\,x+6\right )\right )}^2\,\ln \left (2\,x+6\right )\,\left (x^6+3\,x^5\right )} \,d x \]
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