Integrand size = 121, antiderivative size = 24 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=e^{4 (2-2 x) \left (-1+\frac {1}{x^2 \left (e^{2 x}+x\right )}\right )} \]
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\[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=\int \frac {\exp \left (\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}\right ) \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {8 \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (e^{4 x} x^3+x \left (-3+2 x+x^4\right )+e^{2 x} \left (-2-x+2 x^2+2 x^4\right )\right )}{x^3 \left (e^{2 x}+x\right )^2} \, dx \\ & = 8 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (e^{4 x} x^3+x \left (-3+2 x+x^4\right )+e^{2 x} \left (-2-x+2 x^2+2 x^4\right )\right )}{x^3 \left (e^{2 x}+x\right )^2} \, dx \\ & = 8 \int \left (\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )-\frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (1-3 x+2 x^2\right )}{x^2 \left (e^{2 x}+x\right )^2}+\frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (-2-x+2 x^2\right )}{x^3 \left (e^{2 x}+x\right )}\right ) \, dx \\ & = 8 \int \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \, dx-8 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (1-3 x+2 x^2\right )}{x^2 \left (e^{2 x}+x\right )^2} \, dx+8 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \left (-2-x+2 x^2\right )}{x^3 \left (e^{2 x}+x\right )} \, dx \\ & = 8 \int \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \, dx-8 \int \left (\frac {2 \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{\left (e^{2 x}+x\right )^2}+\frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^2 \left (e^{2 x}+x\right )^2}-\frac {3 \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x \left (e^{2 x}+x\right )^2}\right ) \, dx+8 \int \left (-\frac {2 \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^3 \left (e^{2 x}+x\right )}-\frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^2 \left (e^{2 x}+x\right )}+\frac {2 \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x \left (e^{2 x}+x\right )}\right ) \, dx \\ & = 8 \int \exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right ) \, dx-8 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^2 \left (e^{2 x}+x\right )^2} \, dx-8 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^2 \left (e^{2 x}+x\right )} \, dx-16 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{\left (e^{2 x}+x\right )^2} \, dx-16 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x^3 \left (e^{2 x}+x\right )} \, dx+16 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x \left (e^{2 x}+x\right )} \, dx+24 \int \frac {\exp \left (\frac {8 (-1+x) \left (-1+e^{2 x} x^2+x^3\right )}{x^2 \left (e^{2 x}+x\right )}\right )}{x \left (e^{2 x}+x\right )^2} \, dx \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=e^{-8+8 x-\frac {8 (-1+x)}{x^2 \left (e^{2 x}+x\right )}} \]
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Time = 3.09 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.29
method | result | size |
risch | \({\mathrm e}^{\frac {8 \left (-1+x \right ) \left ({\mathrm e}^{2 x} x^{2}+x^{3}-1\right )}{x^{2} \left ({\mathrm e}^{2 x}+x \right )}}\) | \(31\) |
parallelrisch | \({\mathrm e}^{\frac {\left (8 x^{3}-8 x^{2}\right ) {\mathrm e}^{2 x}+8 x^{4}-8 x^{3}-8 x +8}{x^{2} \left ({\mathrm e}^{2 x}+x \right )}}\) | \(45\) |
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Leaf count of result is larger than twice the leaf count of optimal. 44 vs. \(2 (20) = 40\).
Time = 0.25 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.83 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=e^{\left (\frac {8 \, {\left (x^{4} - x^{3} + {\left (x^{3} - x^{2}\right )} e^{\left (2 \, x\right )} - x + 1\right )}}{x^{3} + x^{2} e^{\left (2 \, x\right )}}\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 42 vs. \(2 (19) = 38\).
Time = 0.27 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.75 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=e^{\frac {8 x^{4} - 8 x^{3} - 8 x + \left (8 x^{3} - 8 x^{2}\right ) e^{2 x} + 8}{x^{3} + x^{2} e^{2 x}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (20) = 40\).
Time = 0.44 (sec) , antiderivative size = 63, normalized size of antiderivative = 2.62 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=e^{\left (8 \, x - \frac {8 \, e^{\left (-2 \, x\right )}}{x} - \frac {8 \, e^{\left (-4 \, x\right )}}{x} + \frac {8}{x e^{\left (4 \, x\right )} + e^{\left (6 \, x\right )}} + \frac {8}{x e^{\left (2 \, x\right )} + e^{\left (4 \, x\right )}} + \frac {8 \, e^{\left (-2 \, x\right )}}{x^{2}} - 8\right )} \]
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Exception generated. \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx=\text {Exception raised: TypeError} \]
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Time = 11.29 (sec) , antiderivative size = 90, normalized size of antiderivative = 3.75 \[ \int \frac {e^{\frac {8-8 x-8 x^3+8 x^4+e^{2 x} \left (-8 x^2+8 x^3\right )}{e^{2 x} x^2+x^3}} \left (-24 x+16 x^2+8 e^{4 x} x^3+8 x^5+e^{2 x} \left (-16-8 x+16 x^2+16 x^4\right )\right )}{e^{4 x} x^3+2 e^{2 x} x^4+x^5} \, dx={\mathrm {e}}^{\frac {8\,x^2}{x+{\mathrm {e}}^{2\,x}}}\,{\mathrm {e}}^{-\frac {8}{x\,{\mathrm {e}}^{2\,x}+x^2}}\,{\mathrm {e}}^{-\frac {8\,{\mathrm {e}}^{2\,x}}{x+{\mathrm {e}}^{2\,x}}}\,{\mathrm {e}}^{-\frac {8\,x}{x+{\mathrm {e}}^{2\,x}}}\,{\mathrm {e}}^{\frac {8}{x^2\,{\mathrm {e}}^{2\,x}+x^3}}\,{\mathrm {e}}^{\frac {8\,x\,{\mathrm {e}}^{2\,x}}{x+{\mathrm {e}}^{2\,x}}} \]
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