Integrand size = 141, antiderivative size = 31 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=\log \left (\left (3-e^{\frac {2 e^e x}{-1+x}}\right )^2\right ) \left (2+\log \left (\frac {2+x}{5}\right )\right ) \]
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\[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=\int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\log \left (\left (-3+e^{\frac {2 e^e x}{-1+x}}\right )^2\right )}{2+x}-\frac {4 e^{e+\frac {2 e^e x}{-1+x}} \left (2+\log \left (\frac {2+x}{5}\right )\right )}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (-1+x)^2}\right ) \, dx \\ & = -\left (4 \int \frac {e^{e+\frac {2 e^e x}{-1+x}} \left (2+\log \left (\frac {2+x}{5}\right )\right )}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (-1+x)^2} \, dx\right )+\int \frac {\log \left (\left (-3+e^{\frac {2 e^e x}{-1+x}}\right )^2\right )}{2+x} \, dx \\ & = -\left (4 \int \left (\frac {2 e^{e+\frac {2 e^e x}{-1+x}}}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (-1+x)^2}+\frac {e^{e+\frac {2 e^e x}{-1+x}} \log \left (\frac {2}{5}+\frac {x}{5}\right )}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (1-x)^2}\right ) \, dx\right )+\int \frac {\log \left (\left (-3+e^{\frac {2 e^e x}{-1+x}}\right )^2\right )}{2+x} \, dx \\ & = -\left (4 \int \frac {e^{e+\frac {2 e^e x}{-1+x}} \log \left (\frac {2}{5}+\frac {x}{5}\right )}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (1-x)^2} \, dx\right )-8 \int \frac {e^{e+\frac {2 e^e x}{-1+x}}}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (-1+x)^2} \, dx+\int \frac {\log \left (\left (-3+e^{\frac {2 e^e x}{-1+x}}\right )^2\right )}{2+x} \, dx \\ & = 4 \log \left (3-e^{-\frac {2 e^e x}{1-x}}\right )-4 \int \frac {e^{e+\frac {2 e^e x}{-1+x}} \log \left (\frac {2}{5}+\frac {x}{5}\right )}{\left (-3+e^{\frac {2 e^e x}{-1+x}}\right ) (1-x)^2} \, dx+\int \frac {\log \left (\left (-3+e^{\frac {2 e^e x}{-1+x}}\right )^2\right )}{2+x} \, dx \\ \end{align*}
Time = 0.95 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.87 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=4 \log \left (3-e^{2 e^e+\frac {2 e^e}{-1+x}}\right )+\log \left (\left (-3+e^{2 e^e+\frac {2 e^e}{-1+x}}\right )^2\right ) \log \left (\frac {2+x}{5}\right ) \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 26.06 (sec) , antiderivative size = 179, normalized size of antiderivative = 5.77
method | result | size |
risch | \(2 \ln \left (\frac {2}{5}+\frac {x}{5}\right ) \ln \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )-\frac {i \pi \ln \left (-2-x \right ) {\operatorname {csgn}\left (i \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )\right )}^{2} \operatorname {csgn}\left (i \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )^{2}\right )}{2}+i \pi \ln \left (-2-x \right ) \operatorname {csgn}\left (i \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )\right ) {\operatorname {csgn}\left (i \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )^{2}\right )}^{2}-\frac {i \pi \ln \left (-2-x \right ) {\operatorname {csgn}\left (i \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )^{2}\right )}^{3}}{2}-8 \,{\mathrm e}^{{\mathrm e}}+4 \ln \left ({\mathrm e}^{\frac {2 x \,{\mathrm e}^{{\mathrm e}}}{-1+x}}-3\right )\) | \(179\) |
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Time = 0.26 (sec) , antiderivative size = 38, normalized size of antiderivative = 1.23 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx={\left (\log \left (\frac {1}{5} \, x + \frac {2}{5}\right ) + 2\right )} \log \left (e^{\left (\frac {4 \, x e^{e}}{x - 1}\right )} - 6 \, e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} + 9\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 58 vs. \(2 (27) = 54\).
Time = 0.56 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.87 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=\log {\left (\frac {x}{5} + \frac {2}{5} \right )} \log {\left (e^{\frac {4 x e^{e}}{x - 1}} - 6 e^{\frac {2 x e^{e}}{x - 1}} + 9 \right )} + 4 \log {\left (e^{\frac {2 x e^{e}}{x - 1}} - 3 \right )} \]
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Time = 0.39 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.03 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=-2 \, {\left (\log \left (5\right ) - \log \left (x + 2\right ) - 2\right )} \log \left (e^{\left (\frac {2 \, e^{e}}{x - 1} + 2 \, e^{e}\right )} - 3\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 178 vs. \(2 (26) = 52\).
Time = 2.41 (sec) , antiderivative size = 178, normalized size of antiderivative = 5.74 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=\frac {x \log \left (x + 2\right ) \log \left (e^{\left (\frac {4 \, x e^{e}}{x - 1}\right )} - 6 \, e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} + 9\right ) - 2 \, x \log \left (5\right ) \log \left (e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} - 3\right ) + 4 \, e^{e} \log \left (5\right ) - 4 \, e^{e} \log \left (x + 2\right ) + 4 \, e^{e} \log \left (\frac {1}{5} \, x + \frac {2}{5}\right ) - \log \left (x + 2\right ) \log \left (e^{\left (\frac {4 \, x e^{e}}{x - 1}\right )} - 6 \, e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} + 9\right ) + 4 \, x \log \left (e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} - 3\right ) + 2 \, \log \left (5\right ) \log \left (e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} - 3\right ) - 4 \, \log \left (e^{\left (\frac {2 \, x e^{e}}{x - 1}\right )} - 3\right )}{x - 1} \]
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Time = 11.14 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.74 \[ \int \frac {\left (-3+6 x-3 x^2+e^{\frac {2 e^e x}{-1+x}} \left (1-2 x+x^2\right )\right ) \log \left (9-6 e^{\frac {2 e^e x}{-1+x}}+e^{\frac {4 e^e x}{-1+x}}\right )+e^{\frac {2 e^e x}{-1+x}} \left (e^e (-16-8 x)+e^e (-8-4 x) \log \left (\frac {2+x}{5}\right )\right )}{-6+9 x-3 x^3+e^{\frac {2 e^e x}{-1+x}} \left (2-3 x+x^3\right )} \, dx=4\,\ln \left ({\mathrm {e}}^{\frac {2\,x\,{\mathrm {e}}^{\mathrm {e}}}{x-1}}-3\right )+\ln \left (\frac {x}{5}+\frac {2}{5}\right )\,\ln \left ({\mathrm {e}}^{\frac {4\,x\,{\mathrm {e}}^{\mathrm {e}}}{x-1}}-6\,{\mathrm {e}}^{\frac {2\,x\,{\mathrm {e}}^{\mathrm {e}}}{x-1}}+9\right ) \]
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