Integrand size = 23, antiderivative size = 15 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=4-2 x-2 e^{(1+x)^2} x \]
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Time = 0.04 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.67, number of steps used = 8, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {2259, 2258, 2235, 2240, 2243} \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=-2 x+2 e^{(x+1)^2}-2 e^{(x+1)^2} (x+1) \]
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Rule 2235
Rule 2240
Rule 2243
Rule 2258
Rule 2259
Rubi steps \begin{align*} \text {integral}& = -2 x+\int e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right ) \, dx \\ & = -2 x+\int e^{(1+x)^2} \left (-2-4 x-4 x^2\right ) \, dx \\ & = -2 x+\int \left (-2 e^{(1+x)^2}+4 e^{(1+x)^2} (1+x)-4 e^{(1+x)^2} (1+x)^2\right ) \, dx \\ & = -2 x-2 \int e^{(1+x)^2} \, dx+4 \int e^{(1+x)^2} (1+x) \, dx-4 \int e^{(1+x)^2} (1+x)^2 \, dx \\ & = 2 e^{(1+x)^2}-2 x-2 e^{(1+x)^2} (1+x)-\sqrt {\pi } \text {erfi}(1+x)+2 \int e^{(1+x)^2} \, dx \\ & = 2 e^{(1+x)^2}-2 x-2 e^{(1+x)^2} (1+x) \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.93 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=-2 x-2 e^{(1+x)^2} x \]
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Time = 0.03 (sec) , antiderivative size = 14, normalized size of antiderivative = 0.93
method | result | size |
risch | \(-2 x -2 \,{\mathrm e}^{\left (1+x \right )^{2}} x\) | \(14\) |
norman | \(-2 x -2 \,{\mathrm e}^{x^{2}+2 x +1} x\) | \(17\) |
parallelrisch | \(-2 x -2 \,{\mathrm e}^{x^{2}+2 x +1} x\) | \(17\) |
default | \(-2 x +i {\mathrm e} \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )-4 \,{\mathrm e} \left (\frac {{\mathrm e}^{x^{2}+2 x}}{2}+\frac {i \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )}{2}\right )-4 \,{\mathrm e} \left (\frac {x \,{\mathrm e}^{x^{2}+2 x}}{2}-\frac {{\mathrm e}^{x^{2}+2 x}}{2}-\frac {i \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )}{4}\right )\) | \(96\) |
parts | \(-2 x +i {\mathrm e} \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )-4 \,{\mathrm e} \left (\frac {{\mathrm e}^{x^{2}+2 x}}{2}+\frac {i \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )}{2}\right )-4 \,{\mathrm e} \left (\frac {x \,{\mathrm e}^{x^{2}+2 x}}{2}-\frac {{\mathrm e}^{x^{2}+2 x}}{2}-\frac {i \sqrt {\pi }\, {\mathrm e}^{-1} \operatorname {erf}\left (i x +i\right )}{4}\right )\) | \(96\) |
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Time = 0.30 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.07 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=-2 \, x e^{\left (x^{2} + 2 \, x + 1\right )} - 2 \, x \]
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Time = 0.05 (sec) , antiderivative size = 17, normalized size of antiderivative = 1.13 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=- 2 x e^{x^{2} + 2 x + 1} - 2 x \]
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Result contains higher order function than in optimal. Order 4 vs. order 3.
Time = 0.25 (sec) , antiderivative size = 48, normalized size of antiderivative = 3.20 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=\frac {2 \, {\left (x + 1\right )}^{3} \Gamma \left (\frac {3}{2}, -{\left (x + 1\right )}^{2}\right )}{\left (-{\left (x + 1\right )}^{2}\right )^{\frac {3}{2}}} + i \, \sqrt {\pi } \operatorname {erf}\left (i \, x + i\right ) - 2 \, x + 2 \, e^{\left ({\left (x + 1\right )}^{2}\right )} \]
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Time = 0.27 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.07 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=-2 \, x e^{\left (x^{2} + 2 \, x + 1\right )} - 2 \, x \]
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Time = 17.57 (sec) , antiderivative size = 16, normalized size of antiderivative = 1.07 \[ \int \left (-2+e^{1+2 x+x^2} \left (-2-4 x-4 x^2\right )\right ) \, dx=-2\,x\,\left ({\mathrm {e}}^{2\,x}\,{\mathrm {e}}^{x^2}\,\mathrm {e}+1\right ) \]
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