Integrand size = 225, antiderivative size = 26 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx=x \left (-5+x+\frac {\left (-4+e^{9+e^{x^2}}\right ) (x+\log (4))}{e^3}\right )^2 \]
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Leaf count is larger than twice the leaf count of optimal. \(179\) vs. \(2(26)=52\).
Time = 0.16 (sec) , antiderivative size = 179, normalized size of antiderivative = 6.88, number of steps used = 6, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.009, Rules used = {12, 2326} \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx=-\frac {8 x^3}{e^3}+\frac {16 x^3}{e^6}+x^3+\frac {40 x^2}{e^3}-10 x^2+\frac {e^{2 e^{x^2}+12} \left (x^4+2 x^3 \log (4)+x^2 \log ^2(4)\right )}{x}-\frac {2 e^{e^{x^2}+3} \left (4 x^4+4 x^2 \log ^2(4)+e^3 \left (5 x^3-x^4\right )+\left (8 x^3+e^3 \left (5 x^2-x^3\right )\right ) \log (4)\right )}{x}+25 x+\frac {16 x \log ^2(4)}{e^6}+\frac {2 \left (e^3 (5-2 x)+8 x\right )^2 \log (4)}{e^6 \left (4-e^3\right )} \]
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Rule 12
Rule 2326
Rubi steps \begin{align*} \text {integral}& = \frac {\int \left (48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )\right ) \, dx}{e^6} \\ & = \frac {16 x^3}{e^6}+\frac {2 \left (e^3 (5-2 x)+8 x\right )^2 \log (4)}{e^6 \left (4-e^3\right )}+\frac {16 x \log ^2(4)}{e^6}+\frac {\int e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right ) \, dx}{e^6}+\frac {\int e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right ) \, dx}{e^6}+\frac {\int \left (80 x-24 x^2\right ) \, dx}{e^3}+\int \left (25-20 x+3 x^2\right ) \, dx \\ & = 25 x-10 x^2+\frac {40 x^2}{e^3}+x^3+\frac {16 x^3}{e^6}-\frac {8 x^3}{e^3}+\frac {2 \left (e^3 (5-2 x)+8 x\right )^2 \log (4)}{e^6 \left (4-e^3\right )}+\frac {16 x \log ^2(4)}{e^6}+\frac {e^{12+2 e^{x^2}} \left (x^4+2 x^3 \log (4)+x^2 \log ^2(4)\right )}{x}-\frac {2 e^{3+e^{x^2}} \left (4 x^4+e^3 \left (5 x^3-x^4\right )+\left (8 x^3+e^3 \left (5 x^2-x^3\right )\right ) \log (4)+4 x^2 \log ^2(4)\right )}{x} \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.35 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx=\frac {x \left (e^3 (-5+x)-4 (x+\log (4))+e^{9+e^{x^2}} (x+\log (4))\right )^2}{e^6} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(169\) vs. \(2(27)=54\).
Time = 0.76 (sec) , antiderivative size = 170, normalized size of antiderivative = 6.54
method | result | size |
risch | \({\mathrm e}^{6} {\mathrm e}^{-6} x^{3}-8 \,{\mathrm e}^{-6} {\mathrm e}^{3} x^{3}+16 \,{\mathrm e}^{-6} x^{3}-16 \,{\mathrm e}^{3} \ln \left (2\right ) {\mathrm e}^{-6} x^{2}+40 \,{\mathrm e}^{3} {\mathrm e}^{-6} x^{2}+64 \ln \left (2\right ) {\mathrm e}^{-6} x^{2}-10 \,{\mathrm e}^{-6} {\mathrm e}^{6} x^{2}+25 \,{\mathrm e}^{6} {\mathrm e}^{-6} x +80 \,{\mathrm e}^{3} \ln \left (2\right ) {\mathrm e}^{-6} x +64 \ln \left (2\right )^{2} {\mathrm e}^{-6} x +\left (4 \ln \left (2\right )^{2}+4 x \ln \left (2\right )+x^{2}\right ) x \,{\mathrm e}^{12+2 \,{\mathrm e}^{x^{2}}}+2 \left (2 \,{\mathrm e}^{3} \ln \left (2\right ) x +x^{2} {\mathrm e}^{3}-10 \,{\mathrm e}^{3} \ln \left (2\right )-5 x \,{\mathrm e}^{3}-16 \ln \left (2\right )^{2}-16 x \ln \left (2\right )-4 x^{2}\right ) x \,{\mathrm e}^{{\mathrm e}^{x^{2}}+3}\) | \(170\) |
default | \({\mathrm e}^{-6} \left (x^{3} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+4 x \ln \left (2\right )^{2} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+4 x^{2} \ln \left (2\right ) {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+\left (-20 \,{\mathrm e}^{3} \ln \left (2\right )-32 \ln \left (2\right )^{2}\right ) x \,{\mathrm e}^{{\mathrm e}^{x^{2}}+9}+\left (2 \,{\mathrm e}^{3}-8\right ) x^{3} {\mathrm e}^{{\mathrm e}^{x^{2}}+9}+\left (4 \,{\mathrm e}^{3} \ln \left (2\right )-10 \,{\mathrm e}^{3}-32 \ln \left (2\right )\right ) x^{2} {\mathrm e}^{{\mathrm e}^{x^{2}}+9}+8 \,{\mathrm e}^{3} \left (-x^{3}+5 x^{2}\right )+{\mathrm e}^{6} \left (x^{3}-10 x^{2}+25 x \right )+16 x^{3}+64 x \ln \left (2\right )^{2}+2 \ln \left (2\right ) \left (-8 x^{2} {\mathrm e}^{3}+40 x \,{\mathrm e}^{3}+32 x^{2}\right )\right )\) | \(183\) |
norman | \(\left (\left (16+{\mathrm e}^{6}-8 \,{\mathrm e}^{3}\right ) {\mathrm e}^{-3} x^{3}+\left (80 \,{\mathrm e}^{3} \ln \left (2\right )+25 \,{\mathrm e}^{6}+64 \ln \left (2\right )^{2}\right ) {\mathrm e}^{-3} x +{\mathrm e}^{-3} x^{3} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}-2 \left (5 \,{\mathrm e}^{6}+8 \,{\mathrm e}^{3} \ln \left (2\right )-20 \,{\mathrm e}^{3}-32 \ln \left (2\right )\right ) {\mathrm e}^{-3} x^{2}+2 \left ({\mathrm e}^{3}-4\right ) {\mathrm e}^{-3} x^{3} {\mathrm e}^{{\mathrm e}^{x^{2}}+9}+2 \left (2 \,{\mathrm e}^{3} \ln \left (2\right )-5 \,{\mathrm e}^{3}-16 \ln \left (2\right )\right ) {\mathrm e}^{-3} x^{2} {\mathrm e}^{{\mathrm e}^{x^{2}}+9}+4 \,{\mathrm e}^{-3} \ln \left (2\right )^{2} x \,{\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+4 \ln \left (2\right ) {\mathrm e}^{-3} x^{2} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}-4 \ln \left (2\right ) \left (5 \,{\mathrm e}^{3}+8 \ln \left (2\right )\right ) {\mathrm e}^{-3} x \,{\mathrm e}^{{\mathrm e}^{x^{2}}+9}\right ) {\mathrm e}^{-3}\) | \(213\) |
parallelrisch | \({\mathrm e}^{-6} \left (x^{3} {\mathrm e}^{6}+4 \,{\mathrm e}^{3} \ln \left (2\right ) x^{2} {\mathrm e}^{{\mathrm e}^{x^{2}}+9}+2 \,{\mathrm e}^{{\mathrm e}^{x^{2}}+9} x^{3} {\mathrm e}^{3}+4 x \ln \left (2\right )^{2} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+4 x^{2} \ln \left (2\right ) {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}+x^{3} {\mathrm e}^{2 \,{\mathrm e}^{x^{2}}+18}-10 x^{2} {\mathrm e}^{6}-16 \,{\mathrm e}^{3} \ln \left (2\right ) x^{2}-20 \,{\mathrm e}^{3} \ln \left (2\right ) {\mathrm e}^{{\mathrm e}^{x^{2}}+9} x -8 x^{3} {\mathrm e}^{3}-10 \,{\mathrm e}^{3} {\mathrm e}^{{\mathrm e}^{x^{2}}+9} x^{2}-32 \ln \left (2\right )^{2} x \,{\mathrm e}^{{\mathrm e}^{x^{2}}+9}-32 \ln \left (2\right ) {\mathrm e}^{{\mathrm e}^{x^{2}}+9} x^{2}-8 \,{\mathrm e}^{{\mathrm e}^{x^{2}}+9} x^{3}+25 x \,{\mathrm e}^{6}+80 \,{\mathrm e}^{3} \ln \left (2\right ) x +40 x^{2} {\mathrm e}^{3}+64 x^{2} \ln \left (2\right )+16 x^{3}+64 x \ln \left (2\right )^{2}\right )\) | \(223\) |
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Leaf count of result is larger than twice the leaf count of optimal. 149 vs. \(2 (25) = 50\).
Time = 0.33 (sec) , antiderivative size = 149, normalized size of antiderivative = 5.73 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx={\left (16 \, x^{3} + 64 \, x \log \left (2\right )^{2} + {\left (x^{3} - 10 \, x^{2} + 25 \, x\right )} e^{6} - 8 \, {\left (x^{3} - 5 \, x^{2}\right )} e^{3} + {\left (x^{3} + 4 \, x^{2} \log \left (2\right ) + 4 \, x \log \left (2\right )^{2}\right )} e^{\left (2 \, e^{\left (x^{2}\right )} + 18\right )} - 2 \, {\left (4 \, x^{3} + 16 \, x \log \left (2\right )^{2} - {\left (x^{3} - 5 \, x^{2}\right )} e^{3} + 2 \, {\left (8 \, x^{2} - {\left (x^{2} - 5 \, x\right )} e^{3}\right )} \log \left (2\right )\right )} e^{\left (e^{\left (x^{2}\right )} + 9\right )} + 16 \, {\left (4 \, x^{2} - {\left (x^{2} - 5 \, x\right )} e^{3}\right )} \log \left (2\right )\right )} e^{\left (-6\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 196 vs. \(2 (26) = 52\).
Time = 0.99 (sec) , antiderivative size = 196, normalized size of antiderivative = 7.54 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx=\frac {x^{3} \left (- 8 e^{3} + 16 + e^{6}\right )}{e^{6}} + \frac {x^{2} \left (- 10 e^{6} - 16 e^{3} \log {\left (2 \right )} + 64 \log {\left (2 \right )} + 40 e^{3}\right )}{e^{6}} + \frac {x \left (64 \log {\left (2 \right )}^{2} + 80 e^{3} \log {\left (2 \right )} + 25 e^{6}\right )}{e^{6}} + \frac {\left (x^{3} e^{6} + 4 x^{2} e^{6} \log {\left (2 \right )} + 4 x e^{6} \log {\left (2 \right )}^{2}\right ) e^{2 e^{x^{2}} + 18} + \left (- 8 x^{3} e^{6} + 2 x^{3} e^{9} - 10 x^{2} e^{9} - 32 x^{2} e^{6} \log {\left (2 \right )} + 4 x^{2} e^{9} \log {\left (2 \right )} - 20 x e^{9} \log {\left (2 \right )} - 32 x e^{6} \log {\left (2 \right )}^{2}\right ) e^{e^{x^{2}} + 9}}{e^{12}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 155 vs. \(2 (25) = 50\).
Time = 0.29 (sec) , antiderivative size = 155, normalized size of antiderivative = 5.96 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx={\left (16 \, x^{3} + 64 \, x \log \left (2\right )^{2} + {\left (x^{3} - 10 \, x^{2} + 25 \, x\right )} e^{6} - 8 \, {\left (x^{3} - 5 \, x^{2}\right )} e^{3} + {\left (x^{3} e^{18} + 4 \, x^{2} e^{18} \log \left (2\right ) + 4 \, x e^{18} \log \left (2\right )^{2}\right )} e^{\left (2 \, e^{\left (x^{2}\right )}\right )} + 2 \, {\left (x^{3} {\left (e^{12} - 4 \, e^{9}\right )} + {\left ({\left (2 \, \log \left (2\right ) - 5\right )} e^{12} - 16 \, e^{9} \log \left (2\right )\right )} x^{2} - 2 \, {\left (8 \, e^{9} \log \left (2\right )^{2} + 5 \, e^{12} \log \left (2\right )\right )} x\right )} e^{\left (e^{\left (x^{2}\right )}\right )} + 16 \, {\left (4 \, x^{2} - {\left (x^{2} - 5 \, x\right )} e^{3}\right )} \log \left (2\right )\right )} e^{\left (-6\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 229 vs. \(2 (25) = 50\).
Time = 0.31 (sec) , antiderivative size = 229, normalized size of antiderivative = 8.81 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx={\left (x^{3} e^{\left (2 \, e^{\left (x^{2}\right )} + 18\right )} + 4 \, x^{2} e^{\left (2 \, e^{\left (x^{2}\right )} + 18\right )} \log \left (2\right ) + 4 \, x e^{\left (2 \, e^{\left (x^{2}\right )} + 18\right )} \log \left (2\right )^{2} + 16 \, x^{3} + 64 \, x \log \left (2\right )^{2} + {\left (x^{3} - 10 \, x^{2} + 25 \, x\right )} e^{6} - 8 \, {\left (x^{3} - 5 \, x^{2}\right )} e^{3} + 2 \, {\left (x^{3} e^{\left (x^{2} + e^{\left (x^{2}\right )} + 12\right )} - 4 \, x^{3} e^{\left (x^{2} + e^{\left (x^{2}\right )} + 9\right )} + 2 \, x^{2} e^{\left (x^{2} + e^{\left (x^{2}\right )} + 12\right )} \log \left (2\right ) - 16 \, x^{2} e^{\left (x^{2} + e^{\left (x^{2}\right )} + 9\right )} \log \left (2\right ) - 16 \, x e^{\left (x^{2} + e^{\left (x^{2}\right )} + 9\right )} \log \left (2\right )^{2} - 5 \, x^{2} e^{\left (x^{2} + e^{\left (x^{2}\right )} + 12\right )} - 10 \, x e^{\left (x^{2} + e^{\left (x^{2}\right )} + 12\right )} \log \left (2\right )\right )} e^{\left (-x^{2}\right )} + 16 \, {\left (4 \, x^{2} - {\left (x^{2} - 5 \, x\right )} e^{3}\right )} \log \left (2\right )\right )} e^{\left (-6\right )} \]
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Time = 18.73 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.69 \[ \int \frac {48 x^2+e^3 \left (80 x-24 x^2\right )+e^6 \left (25-20 x+3 x^2\right )+\left (e^3 (40-16 x)+64 x\right ) \log (4)+16 \log ^2(4)+e^{9+e^{x^2}} \left (-24 x^2+e^3 \left (-20 x+6 x^2\right )+\left (-32 x+e^3 (-10+4 x)\right ) \log (4)-8 \log ^2(4)+e^{x^2} \left (-16 x^4+e^3 \left (-20 x^3+4 x^4\right )+\left (-32 x^3+e^3 \left (-20 x^2+4 x^3\right )\right ) \log (4)-16 x^2 \log ^2(4)\right )\right )+e^{18+2 e^{x^2}} \left (3 x^2+4 x \log (4)+\log ^2(4)+e^{x^2} \left (4 x^4+8 x^3 \log (4)+4 x^2 \log ^2(4)\right )\right )}{e^6} \, dx=x\,{\mathrm {e}}^{-6}\,{\left (4\,x+5\,{\mathrm {e}}^3+8\,\ln \left (2\right )-x\,{\mathrm {e}}^3-2\,{\mathrm {e}}^9\,{\mathrm {e}}^{{\mathrm {e}}^{x^2}}\,\ln \left (2\right )-x\,{\mathrm {e}}^9\,{\mathrm {e}}^{{\mathrm {e}}^{x^2}}\right )}^2 \]
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