Integrand size = 65, antiderivative size = 24 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\log \left (\frac {1}{5} x^3 \left (-\frac {1}{e^8}+\log \left (\frac {4}{x}\right )\right )\right )} \]
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Time = 0.13 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.25, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.031, Rules used = {2641, 6818} \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\log \left (-\frac {x^3-e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \]
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Rule 2641
Rule 6818
Rubi steps \begin{align*} \text {integral}& = \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{x \left (-1+e^8 \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx \\ & = \frac {2}{\log \left (-\frac {x^3-e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\log \left (\frac {x^3 \left (-1+e^8 \log \left (\frac {4}{x}\right )\right )}{5 e^8}\right )} \]
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Time = 0.45 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08
method | result | size |
parallelrisch | \(\frac {2}{\ln \left (\frac {x^{3} \left ({\mathrm e}^{8} \ln \left (\frac {4}{x}\right )-1\right ) {\mathrm e}^{-8}}{5}\right )}\) | \(26\) |
norman | \(\frac {2}{\ln \left (\frac {\left (x^{3} {\mathrm e}^{8} \ln \left (\frac {4}{x}\right )-x^{3}\right ) {\mathrm e}^{-8}}{5}\right )}\) | \(30\) |
default | \(-\frac {2}{\ln \left (5\right )+8-\ln \left (x^{3} \left (2 \ln \left (2\right ) {\mathrm e}^{8}+{\mathrm e}^{8} \ln \left (\frac {1}{x}\right )-1\right )\right )}\) | \(31\) |
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Time = 0.23 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\log \left (\frac {1}{5} \, {\left (x^{3} e^{8} \log \left (\frac {4}{x}\right ) - x^{3}\right )} e^{\left (-8\right )}\right )} \]
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Time = 0.11 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\log {\left (\frac {\frac {x^{3} e^{8} \log {\left (\frac {4}{x} \right )}}{5} - \frac {x^{3}}{5}}{e^{8}} \right )}} \]
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Time = 0.32 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.21 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=-\frac {2}{\log \left (5\right ) - \log \left (2 \, e^{8} \log \left (2\right ) - e^{8} \log \left (x\right ) - 1\right ) - 3 \, \log \left (x\right ) + 8} \]
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Leaf count of result is larger than twice the leaf count of optimal. 456 vs. \(2 (21) = 42\).
Time = 0.35 (sec) , antiderivative size = 456, normalized size of antiderivative = 19.00 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=-\frac {2 \, {\left (6 \, e^{16} \log \left (2\right ) \log \left (\frac {4}{x}\right ) - 3 \, e^{16} \log \left (x\right ) \log \left (\frac {4}{x}\right ) - 6 \, e^{8} \log \left (2\right ) + 3 \, e^{8} \log \left (x\right ) - e^{16} \log \left (\frac {4}{x}\right ) - 3 \, e^{8} \log \left (\frac {4}{x}\right ) + e^{8} + 3\right )}}{6 \, e^{16} \log \left (5\right ) \log \left (2\right ) \log \left (\frac {4}{x}\right ) - 6 \, e^{16} \log \left (2\right ) \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) \log \left (\frac {4}{x}\right ) - 3 \, e^{16} \log \left (5\right ) \log \left (x\right ) \log \left (\frac {4}{x}\right ) - 18 \, e^{16} \log \left (2\right ) \log \left (x\right ) \log \left (\frac {4}{x}\right ) + 3 \, e^{16} \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) \log \left (x\right ) \log \left (\frac {4}{x}\right ) + 9 \, e^{16} \log \left (x\right )^{2} \log \left (\frac {4}{x}\right ) - 2 \, e^{16} \log \left (5\right ) \log \left (2\right ) - 6 \, e^{8} \log \left (5\right ) \log \left (2\right ) + 2 \, e^{16} \log \left (2\right ) \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) + 6 \, e^{8} \log \left (2\right ) \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) + e^{16} \log \left (5\right ) \log \left (x\right ) + 3 \, e^{8} \log \left (5\right ) \log \left (x\right ) + 6 \, e^{16} \log \left (2\right ) \log \left (x\right ) + 18 \, e^{8} \log \left (2\right ) \log \left (x\right ) - e^{16} \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) \log \left (x\right ) - 3 \, e^{8} \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) \log \left (x\right ) - 3 \, e^{16} \log \left (x\right )^{2} - 9 \, e^{8} \log \left (x\right )^{2} - 3 \, e^{8} \log \left (5\right ) \log \left (\frac {4}{x}\right ) + 48 \, e^{16} \log \left (2\right ) \log \left (\frac {4}{x}\right ) + 3 \, e^{8} \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) \log \left (\frac {4}{x}\right ) - 24 \, e^{16} \log \left (x\right ) \log \left (\frac {4}{x}\right ) + 9 \, e^{8} \log \left (x\right ) \log \left (\frac {4}{x}\right ) + e^{8} \log \left (5\right ) - 16 \, e^{16} \log \left (2\right ) - 48 \, e^{8} \log \left (2\right ) - e^{8} \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) + 8 \, e^{16} \log \left (x\right ) + 21 \, e^{8} \log \left (x\right ) - 24 \, e^{8} \log \left (\frac {4}{x}\right ) + 8 \, e^{8} + 3 \, \log \left (5\right ) - 3 \, \log \left (e^{8} \log \left (\frac {4}{x}\right ) - 1\right ) - 9 \, \log \left (x\right ) + 24} \]
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Time = 13.17 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {6+2 e^8-6 e^8 \log \left (\frac {4}{x}\right )}{\left (-x+e^8 x \log \left (\frac {4}{x}\right )\right ) \log ^2\left (\frac {-x^3+e^8 x^3 \log \left (\frac {4}{x}\right )}{5 e^8}\right )} \, dx=\frac {2}{\ln \left (\frac {x^3\,\ln \left (\frac {4}{x}\right )}{5}-\frac {x^3\,{\mathrm {e}}^{-8}}{5}\right )} \]
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