Integrand size = 27, antiderivative size = 22 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=\log \left (e^{\frac {16 (7+x) \left (x+x^2\right )}{x^2}} \left (1+x^2\right )\right ) \]
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Time = 0.03 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.68, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {1607, 1816, 266} \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=\log \left (x^2+1\right )+16 x+\frac {112}{x} \]
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Rule 266
Rule 1607
Rule 1816
Rubi steps \begin{align*} \text {integral}& = \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2 \left (1+x^2\right )} \, dx \\ & = \int \left (16-\frac {112}{x^2}+\frac {2 x}{1+x^2}\right ) \, dx \\ & = \frac {112}{x}+16 x+2 \int \frac {x}{1+x^2} \, dx \\ & = \frac {112}{x}+16 x+\log \left (1+x^2\right ) \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.95 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=2 \left (\frac {56}{x}+8 x+\frac {1}{2} \log \left (1+x^2\right )\right ) \]
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Time = 0.48 (sec) , antiderivative size = 16, normalized size of antiderivative = 0.73
method | result | size |
default | \(16 x +\frac {112}{x}+\ln \left (x^{2}+1\right )\) | \(16\) |
meijerg | \(16 x +\frac {112}{x}+\ln \left (x^{2}+1\right )\) | \(16\) |
risch | \(16 x +\frac {112}{x}+\ln \left (x^{2}+1\right )\) | \(16\) |
norman | \(\frac {16 x^{2}+112}{x}+\ln \left (x^{2}+1\right )\) | \(19\) |
parallelrisch | \(\frac {\ln \left (x^{2}+1\right ) x +16 x^{2}+112}{x}\) | \(20\) |
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Time = 0.24 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.86 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=\frac {16 \, x^{2} + x \log \left (x^{2} + 1\right ) + 112}{x} \]
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Time = 0.04 (sec) , antiderivative size = 12, normalized size of antiderivative = 0.55 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=16 x + \log {\left (x^{2} + 1 \right )} + \frac {112}{x} \]
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Time = 0.29 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.68 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=16 \, x + \frac {112}{x} + \log \left (x^{2} + 1\right ) \]
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Time = 0.27 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.68 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=16 \, x + \frac {112}{x} + \log \left (x^{2} + 1\right ) \]
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Time = 12.68 (sec) , antiderivative size = 15, normalized size of antiderivative = 0.68 \[ \int \frac {-112-96 x^2+2 x^3+16 x^4}{x^2+x^4} \, dx=16\,x+\ln \left (x^2+1\right )+\frac {112}{x} \]
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