Integrand size = 109, antiderivative size = 25 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=e^{e^{2 x}+\left (-1+\log \left (4+e^x-\frac {x^2}{6}\right )\right )^2} \]
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Time = 0.13 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.76, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.018, Rules used = {12, 2326} \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\frac {36 e^{\log ^2\left (\frac {1}{6} \left (-x^2+6 e^x+24\right )\right )+e^{2 x}+1}}{\left (-x^2+6 e^x+24\right )^2} \]
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Rule 12
Rule 2326
Rubi steps \begin{align*} \text {integral}& = 36 \int \frac {e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx \\ & = \frac {36 e^{1+e^{2 x}+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )}}{\left (24+6 e^x-x^2\right )^2} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.60 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\frac {36 e^{1+e^{2 x}+\log ^2\left (4+e^x-\frac {x^2}{6}\right )}}{\left (24+6 e^x-x^2\right )^2} \]
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Time = 18.60 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.28
method | result | size |
risch | \(\frac {{\mathrm e}^{{\mathrm e}^{2 x}+\ln \left ({\mathrm e}^{x}-\frac {x^{2}}{6}+4\right )^{2}+1}}{\left ({\mathrm e}^{x}-\frac {x^{2}}{6}+4\right )^{2}}\) | \(32\) |
parallelrisch | \({\mathrm e}^{{\mathrm e}^{2 x}} {\mathrm e}^{\ln \left ({\mathrm e}^{x}-\frac {x^{2}}{6}+4\right )^{2}-2 \ln \left ({\mathrm e}^{x}-\frac {x^{2}}{6}+4\right )+1}\) | \(34\) |
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Time = 0.25 (sec) , antiderivative size = 31, normalized size of antiderivative = 1.24 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=e^{\left (\log \left (-\frac {1}{6} \, x^{2} + e^{x} + 4\right )^{2} + e^{\left (2 \, x\right )} - 2 \, \log \left (-\frac {1}{6} \, x^{2} + e^{x} + 4\right ) + 1\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 54 vs. \(2 (22) = 44\).
Time = 1.09 (sec) , antiderivative size = 54, normalized size of antiderivative = 2.16 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\frac {36 e^{\log {\left (- \frac {x^{2}}{6} + e^{x} + 4 \right )}^{2} + 1} e^{e^{2 x}}}{x^{4} - 12 x^{2} e^{x} - 48 x^{2} + 36 e^{2 x} + 288 e^{x} + 576} \]
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Leaf count of result is larger than twice the leaf count of optimal. 98 vs. \(2 (20) = 40\).
Time = 0.43 (sec) , antiderivative size = 98, normalized size of antiderivative = 3.92 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\frac {9 \cdot 2^{2 \, \log \left (3\right ) + 2} e^{\left (\log \left (3\right )^{2} + \log \left (2\right )^{2} - 2 \, \log \left (3\right ) \log \left (-x^{2} + 6 \, e^{x} + 24\right ) - 2 \, \log \left (2\right ) \log \left (-x^{2} + 6 \, e^{x} + 24\right ) + \log \left (-x^{2} + 6 \, e^{x} + 24\right )^{2} + e^{\left (2 \, x\right )} + 1\right )}}{x^{4} - 48 \, x^{2} - 12 \, {\left (x^{2} - 24\right )} e^{x} + 36 \, e^{\left (2 \, x\right )} + 576} \]
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\[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\int { \frac {2 \, {\left (2 \, {\left (x - 3 \, e^{x}\right )} e^{\left (e^{\left (2 \, x\right )}\right )} \log \left (-\frac {1}{6} \, x^{2} + e^{x} + 4\right ) + {\left ({\left (x^{2} - 6 \, e^{x} - 24\right )} e^{\left (2 \, x\right )} - 2 \, x + 6 \, e^{x}\right )} e^{\left (e^{\left (2 \, x\right )}\right )}\right )} e^{\left (\log \left (-\frac {1}{6} \, x^{2} + e^{x} + 4\right )^{2} - 2 \, \log \left (-\frac {1}{6} \, x^{2} + e^{x} + 4\right ) + 1\right )}}{x^{2} - 6 \, e^{x} - 24} \,d x } \]
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Time = 14.14 (sec) , antiderivative size = 50, normalized size of antiderivative = 2.00 \[ \int \frac {36 e^{1+\log ^2\left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )} \left (e^{e^{2 x}} \left (-12 e^x+4 x+e^{2 x} \left (48+12 e^x-2 x^2\right )\right )+e^{e^{2 x}} \left (12 e^x-4 x\right ) \log \left (\frac {1}{6} \left (24+6 e^x-x^2\right )\right )\right )}{\left (24+6 e^x-x^2\right )^3} \, dx=\frac {\mathrm {e}\,{\mathrm {e}}^{{\mathrm {e}}^{2\,x}}\,{\mathrm {e}}^{{\ln \left ({\mathrm {e}}^x-\frac {x^2}{6}+4\right )}^2}}{{\mathrm {e}}^{2\,x}+8\,{\mathrm {e}}^x-\frac {x^2\,{\mathrm {e}}^x}{3}-\frac {4\,x^2}{3}+\frac {x^4}{36}+16} \]
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