Integrand size = 84, antiderivative size = 34 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=-2-x-5 (1+x)+\frac {2 x}{-3+2 x}+\frac {-2+2 x}{\log \left (\frac {x}{5}\right )} \]
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Time = 0.28 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.119, Rules used = {1608, 27, 6820, 12, 697, 2367, 2334, 2335, 2339, 30} \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=-6 x-\frac {3}{3-2 x}+\frac {2 x}{\log \left (\frac {x}{5}\right )}-\frac {2}{\log \left (\frac {x}{5}\right )} \]
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Rule 12
Rule 27
Rule 30
Rule 697
Rule 1608
Rule 2334
Rule 2335
Rule 2339
Rule 2367
Rule 6820
Rubi steps \begin{align*} \text {integral}& = \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{x \left (9-12 x+4 x^2\right ) \log ^2\left (\frac {x}{5}\right )} \, dx \\ & = \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{x (-3+2 x)^2 \log ^2\left (\frac {x}{5}\right )} \, dx \\ & = \int 2 \left (-\frac {6 \left (5-6 x+2 x^2\right )}{(3-2 x)^2}+\frac {-1+\frac {1}{x}}{\log ^2\left (\frac {x}{5}\right )}+\frac {1}{\log \left (\frac {x}{5}\right )}\right ) \, dx \\ & = 2 \int \left (-\frac {6 \left (5-6 x+2 x^2\right )}{(3-2 x)^2}+\frac {-1+\frac {1}{x}}{\log ^2\left (\frac {x}{5}\right )}+\frac {1}{\log \left (\frac {x}{5}\right )}\right ) \, dx \\ & = 2 \int \frac {-1+\frac {1}{x}}{\log ^2\left (\frac {x}{5}\right )} \, dx+2 \int \frac {1}{\log \left (\frac {x}{5}\right )} \, dx-12 \int \frac {5-6 x+2 x^2}{(3-2 x)^2} \, dx \\ & = 10 \operatorname {LogIntegral}\left (\frac {x}{5}\right )+2 \int \left (-\frac {1}{\log ^2\left (\frac {x}{5}\right )}+\frac {1}{x \log ^2\left (\frac {x}{5}\right )}\right ) \, dx-12 \int \left (\frac {1}{2}+\frac {1}{2 (-3+2 x)^2}\right ) \, dx \\ & = -\frac {3}{3-2 x}-6 x+10 \operatorname {LogIntegral}\left (\frac {x}{5}\right )-2 \int \frac {1}{\log ^2\left (\frac {x}{5}\right )} \, dx+2 \int \frac {1}{x \log ^2\left (\frac {x}{5}\right )} \, dx \\ & = -\frac {3}{3-2 x}-6 x+\frac {2 x}{\log \left (\frac {x}{5}\right )}+10 \operatorname {LogIntegral}\left (\frac {x}{5}\right )-2 \int \frac {1}{\log \left (\frac {x}{5}\right )} \, dx+2 \text {Subst}\left (\int \frac {1}{x^2} \, dx,x,\log \left (\frac {x}{5}\right )\right ) \\ & = -\frac {3}{3-2 x}-6 x-\frac {2}{\log \left (\frac {x}{5}\right )}+\frac {2 x}{\log \left (\frac {x}{5}\right )} \\ \end{align*}
Time = 0.16 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.03 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=2 \left (-\frac {3}{2 (3-2 x)}-\frac {3}{2} (-3+2 x)+\frac {-1+x}{\log \left (\frac {x}{5}\right )}\right ) \]
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Time = 0.13 (sec) , antiderivative size = 31, normalized size of antiderivative = 0.91
method | result | size |
derivativedivides | \(-6 x +\frac {3}{-3+2 x}+\frac {2 x}{\ln \left (\frac {x}{5}\right )}-\frac {2}{\ln \left (\frac {x}{5}\right )}\) | \(31\) |
default | \(-6 x +\frac {3}{-3+2 x}+\frac {2 x}{\ln \left (\frac {x}{5}\right )}-\frac {2}{\ln \left (\frac {x}{5}\right )}\) | \(31\) |
parts | \(-6 x +\frac {3}{-3+2 x}+\frac {2 x}{\ln \left (\frac {x}{5}\right )}-\frac {2}{\ln \left (\frac {x}{5}\right )}\) | \(31\) |
risch | \(-\frac {3 \left (4 x^{2}-6 x -1\right )}{-3+2 x}+\frac {-2+2 x}{\ln \left (\frac {x}{5}\right )}\) | \(32\) |
norman | \(\frac {6+30 \ln \left (\frac {x}{5}\right )-10 x +4 x^{2}-12 \ln \left (\frac {x}{5}\right ) x^{2}}{\left (-3+2 x \right ) \ln \left (\frac {x}{5}\right )}\) | \(40\) |
parallelrisch | \(\frac {12-24 \ln \left (\frac {x}{5}\right ) x^{2}+8 x^{2}-20 x +60 \ln \left (\frac {x}{5}\right )}{2 \ln \left (\frac {x}{5}\right ) \left (-3+2 x \right )}\) | \(41\) |
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Time = 0.25 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.18 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=\frac {4 \, x^{2} - 3 \, {\left (4 \, x^{2} - 6 \, x - 1\right )} \log \left (\frac {1}{5} \, x\right ) - 10 \, x + 6}{{\left (2 \, x - 3\right )} \log \left (\frac {1}{5} \, x\right )} \]
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Time = 0.07 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.56 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=- 6 x + \frac {2 x - 2}{\log {\left (\frac {x}{5} \right )}} + \frac {3}{2 x - 3} \]
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Leaf count of result is larger than twice the leaf count of optimal. 63 vs. \(2 (26) = 52\).
Time = 0.32 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.85 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=-\frac {4 \, x^{2} {\left (3 \, \log \left (5\right ) + 1\right )} - 2 \, x {\left (9 \, \log \left (5\right ) + 5\right )} - 3 \, {\left (4 \, x^{2} - 6 \, x - 1\right )} \log \left (x\right ) - 3 \, \log \left (5\right ) + 6}{2 \, x \log \left (5\right ) - {\left (2 \, x - 3\right )} \log \left (x\right ) - 3 \, \log \left (5\right )} \]
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Time = 0.27 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.71 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=-6 \, x + \frac {2 \, {\left (x - 1\right )}}{\log \left (\frac {1}{5} \, x\right )} + \frac {3}{2 \, x - 3} \]
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Time = 14.36 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.24 \[ \int \frac {18-42 x+32 x^2-8 x^3+\left (18 x-24 x^2+8 x^3\right ) \log \left (\frac {x}{5}\right )+\left (-60 x+72 x^2-24 x^3\right ) \log ^2\left (\frac {x}{5}\right )}{\left (9 x-12 x^2+4 x^3\right ) \log ^2\left (\frac {x}{5}\right )} \, dx=\frac {20\,x-12\,x^2}{2\,x-3}+\frac {4\,x^2-10\,x+6}{\ln \left (\frac {x}{5}\right )\,\left (2\,x-3\right )} \]
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