Integrand size = 166, antiderivative size = 28 \[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=1-e^{\frac {1}{\left (2-e^{2-16 \left (x^2-\log (4)\right )^2}\right )^2}} \]
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\[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=\int \frac {\exp \left (2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)\right ) \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \frac {\exp \left (2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)\right ) x^2 \left (-128 x^2+128 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx \\ & = \int \frac {2^{7+64 x^2} \exp \left (\frac {e^{32 \left (x^4+\log ^2(4)\right )}}{\left (2^{64 x^2} e^2-2 e^{16 \left (x^4+\log ^2(4)\right )}\right )^2}+32 x^4+2 \left (1+16 \log ^2(4)\right )\right ) x \left (-x^2+\log (4)\right )}{\left (2^{64 x^2} e^2-2 e^{16 \left (x^4+\log ^2(4)\right )}\right )^3} \, dx \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {2^{7+64 x} \exp \left (\frac {e^{32 \left (x^2+\log ^2(4)\right )}}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^2}+32 x^2+2 \left (1+16 \log ^2(4)\right )\right ) (-x+\log (4))}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^3} \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \left (\frac {2^{7+64 x} \exp \left (\frac {e^{32 \left (x^2+\log ^2(4)\right )}}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^2}+32 x^2+2 \left (1+16 \log ^2(4)\right )\right ) x}{\left (-2^{64 x} e^2+2 e^{16 x^2+16 \log ^2(4)}\right )^3}-\frac {2^{7+64 x} \exp \left (\frac {e^{32 \left (x^2+\log ^2(4)\right )}}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^2}+32 x^2+2 \left (1+16 \log ^2(4)\right )\right ) \log (4)}{\left (-2^{64 x} e^2+2 e^{16 x^2+16 \log ^2(4)}\right )^3}\right ) \, dx,x,x^2\right ) \\ & = \frac {1}{2} \text {Subst}\left (\int \frac {2^{7+64 x} \exp \left (\frac {e^{32 \left (x^2+\log ^2(4)\right )}}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^2}+32 x^2+2 \left (1+16 \log ^2(4)\right )\right ) x}{\left (-2^{64 x} e^2+2 e^{16 x^2+16 \log ^2(4)}\right )^3} \, dx,x,x^2\right )-\frac {1}{2} \log (4) \text {Subst}\left (\int \frac {2^{7+64 x} \exp \left (\frac {e^{32 \left (x^2+\log ^2(4)\right )}}{\left (2^{64 x} e^2-2 e^{16 \left (x^2+\log ^2(4)\right )}\right )^2}+32 x^2+2 \left (1+16 \log ^2(4)\right )\right )}{\left (-2^{64 x} e^2+2 e^{16 x^2+16 \log ^2(4)}\right )^3} \, dx,x,x^2\right ) \\ \end{align*}
\[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=\int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx \]
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Time = 1.75 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.93
method | result | size |
parallelrisch | \(-{\mathrm e}^{\frac {1}{{\mathrm e}^{-32 x^{4}+128 x^{2} \ln \left (2\right )-128 \ln \left (2\right )^{2}+4}-4 \,{\mathrm e}^{-16 x^{4}+64 x^{2} \ln \left (2\right )-64 \ln \left (2\right )^{2}+2}+4}}\) | \(54\) |
risch | \(-{\mathrm e}^{-\frac {1}{-{\mathrm e}^{-32 x^{4}+128 x^{2} \ln \left (2\right )-128 \ln \left (2\right )^{2}+4}+4 \,{\mathrm e}^{-16 x^{4}+64 x^{2} \ln \left (2\right )-64 \ln \left (2\right )^{2}+2}-4}}\) | \(56\) |
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Leaf count of result is larger than twice the leaf count of optimal. 180 vs. \(2 (24) = 48\).
Time = 0.26 (sec) , antiderivative size = 180, normalized size of antiderivative = 6.43 \[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=-e^{\left (16 \, x^{4} - 64 \, x^{2} \log \left (2\right ) + 64 \, \log \left (2\right )^{2} + \frac {64 \, x^{4} - 256 \, x^{2} \log \left (2\right ) - 8 \, {\left (8 \, x^{4} - 32 \, x^{2} \log \left (2\right ) + 32 \, \log \left (2\right )^{2} - 1\right )} e^{\left (-16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) - 64 \, \log \left (2\right )^{2} + 2\right )} + 2 \, {\left (8 \, x^{4} - 32 \, x^{2} \log \left (2\right ) + 32 \, \log \left (2\right )^{2} - 1\right )} e^{\left (-32 \, x^{4} + 128 \, x^{2} \log \left (2\right ) - 128 \, \log \left (2\right )^{2} + 4\right )} + 256 \, \log \left (2\right )^{2} - 9}{4 \, e^{\left (-16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) - 64 \, \log \left (2\right )^{2} + 2\right )} - e^{\left (-32 \, x^{4} + 128 \, x^{2} \log \left (2\right ) - 128 \, \log \left (2\right )^{2} + 4\right )} - 4} - 2\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 54 vs. \(2 (22) = 44\).
Time = 0.20 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.93 \[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=- e^{\frac {1}{e^{- 32 x^{4} + 128 x^{2} \log {\left (2 \right )} - 128 \log {\left (2 \right )}^{2} + 4} - 4 e^{- 16 x^{4} + 64 x^{2} \log {\left (2 \right )} - 64 \log {\left (2 \right )}^{2} + 2} + 4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 68 vs. \(2 (24) = 48\).
Time = 1.26 (sec) , antiderivative size = 68, normalized size of antiderivative = 2.43 \[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=-e^{\left (\frac {e^{\left (32 \, x^{4} + 128 \, \log \left (2\right )^{2}\right )}}{4 \, e^{\left (32 \, x^{4} + 128 \, \log \left (2\right )^{2}\right )} - 4 \, e^{\left (16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) + 64 \, \log \left (2\right )^{2} + 2\right )} + e^{\left (128 \, x^{2} \log \left (2\right ) + 4\right )}}\right )} \]
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\[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=\int { -\frac {128 \, {\left (x^{4} - 2 \, x^{2} \log \left (2\right )\right )} e^{\left (-16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) - 64 \, \log \left (2\right )^{2} - \frac {1}{4 \, e^{\left (-16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) - 64 \, \log \left (2\right )^{2} + 2\right )} - e^{\left (-32 \, x^{4} + 128 \, x^{2} \log \left (2\right ) - 128 \, \log \left (2\right )^{2} + 4\right )} - 4} + 2\right )}}{12 \, x e^{\left (-16 \, x^{4} + 64 \, x^{2} \log \left (2\right ) - 64 \, \log \left (2\right )^{2} + 2\right )} - 6 \, x e^{\left (-32 \, x^{4} + 128 \, x^{2} \log \left (2\right ) - 128 \, \log \left (2\right )^{2} + 4\right )} + x e^{\left (-48 \, x^{4} + 192 \, x^{2} \log \left (2\right ) - 192 \, \log \left (2\right )^{2} + 6\right )} - 8 \, x} \,d x } \]
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Time = 15.45 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.93 \[ \int \frac {e^{2+\frac {1}{4+e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)}-4 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)}}-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} \left (-128 x^4+128 x^2 \log (4)\right )}{-8 x+e^{6-48 x^4+96 x^2 \log (4)-48 \log ^2(4)} x-6 e^{4-32 x^4+64 x^2 \log (4)-32 \log ^2(4)} x+12 e^{2-16 x^4+32 x^2 \log (4)-16 \log ^2(4)} x} \, dx=-{\mathrm {e}}^{\frac {1}{2^{128\,x^2}\,{\mathrm {e}}^4\,{\mathrm {e}}^{-128\,{\ln \left (2\right )}^2}\,{\mathrm {e}}^{-32\,x^4}-4\,2^{64\,x^2}\,{\mathrm {e}}^2\,{\mathrm {e}}^{-64\,{\ln \left (2\right )}^2}\,{\mathrm {e}}^{-16\,x^4}+4}} \]
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