Integrand size = 64, antiderivative size = 30 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=\frac {-x+25 e^{-\frac {2}{3} e^{2 (4+x+\log (3))}} \log ^2(x)}{\log (x)} \]
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Time = 0.92 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.77, number of steps used = 10, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {12, 6874, 2320, 2225, 2634, 6820, 2334, 2335} \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=25 e^{-6 e^{2 x+8}} \log (x)-\frac {x}{\log (x)} \]
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Rule 12
Rule 2225
Rule 2320
Rule 2334
Rule 2335
Rule 2634
Rule 6820
Rule 6874
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{x \log ^2(x)} \, dx \\ & = \frac {1}{3} \int \left (-900 e^{8-6 e^{8+2 x}+2 x} \log (x)-\frac {3 e^{-6 e^{8+2 x}} \left (-e^{6 e^{8+2 x}} x+e^{6 e^{8+2 x}} x \log (x)-25 \log ^2(x)\right )}{x \log ^2(x)}\right ) \, dx \\ & = -\left (300 \int e^{8-6 e^{8+2 x}+2 x} \log (x) \, dx\right )-\int \frac {e^{-6 e^{8+2 x}} \left (-e^{6 e^{8+2 x}} x+e^{6 e^{8+2 x}} x \log (x)-25 \log ^2(x)\right )}{x \log ^2(x)} \, dx \\ & = 25 e^{-6 e^{8+2 x}} \log (x)+300 \int -\frac {e^{-6 e^{8+2 x}}}{12 x} \, dx-\int \left (-\frac {25 e^{-6 e^{8+2 x}}}{x}-\frac {1}{\log ^2(x)}+\frac {1}{\log (x)}\right ) \, dx \\ & = 25 e^{-6 e^{8+2 x}} \log (x)+\int \frac {1}{\log ^2(x)} \, dx-\int \frac {1}{\log (x)} \, dx \\ & = -\frac {x}{\log (x)}+25 e^{-6 e^{8+2 x}} \log (x)-\operatorname {LogIntegral}(x)+\int \frac {1}{\log (x)} \, dx \\ & = -\frac {x}{\log (x)}+25 e^{-6 e^{8+2 x}} \log (x) \\ \end{align*}
Time = 0.85 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.77 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=-\frac {x}{\log (x)}+25 e^{-6 e^{8+2 x}} \log (x) \]
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Time = 0.17 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.73
method | result | size |
risch | \(-\frac {x}{\ln \left (x \right )}+25 \ln \left (x \right ) {\mathrm e}^{-6 \,{\mathrm e}^{2 x +8}}\) | \(22\) |
parallelrisch | \(\frac {\left (-9 \,{\mathrm e}^{6 \,{\mathrm e}^{2 x +8}} x +225 \ln \left (x \right )^{2}\right ) {\mathrm e}^{-6 \,{\mathrm e}^{2 x +8}}}{9 \ln \left (x \right )}\) | \(47\) |
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Time = 0.27 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.37 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=-\frac {{\left (x e^{\left (\frac {2}{3} \, e^{\left (2 \, x + 2 \, \log \left (3\right ) + 8\right )}\right )} - 25 \, \log \left (x\right )^{2}\right )} e^{\left (-\frac {2}{3} \, e^{\left (2 \, x + 2 \, \log \left (3\right ) + 8\right )}\right )}}{\log \left (x\right )} \]
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Time = 12.76 (sec) , antiderivative size = 19, normalized size of antiderivative = 0.63 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=- \frac {x}{\log {\left (x \right )}} + 25 e^{- 6 e^{2 x + 8}} \log {\left (x \right )} \]
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Time = 0.24 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=\frac {25 \, e^{\left (-6 \, e^{\left (2 \, x + 8\right )}\right )} \log \left (x\right )^{2} - x}{\log \left (x\right )} \]
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Time = 0.27 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.37 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=\frac {{\left (25 \, e^{\left (2 \, x - 6 \, e^{\left (2 \, x + 8\right )} + 8\right )} \log \left (x\right )^{2} - x e^{\left (2 \, x + 8\right )}\right )} e^{\left (-2 \, x - 8\right )}}{\log \left (x\right )} \]
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Time = 13.48 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.70 \[ \int \frac {e^{-6 e^{8+2 x}} \left (75 \log ^2(x)-900 e^{8+2 x} x \log ^3(x)+e^{6 e^{8+2 x}} (3 x-3 x \log (x))\right )}{3 x \log ^2(x)} \, dx=25\,{\mathrm {e}}^{-6\,{\mathrm {e}}^{2\,x}\,{\mathrm {e}}^8}\,\ln \left (x\right )-\frac {x}{\ln \left (x\right )} \]
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