Integrand size = 31, antiderivative size = 123 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\frac {e^{-\frac {9}{4 b f n^2 \log (F)}} F^{a f} g^2 \sqrt {\pi } (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \text {erfi}\left (\frac {3+2 b f n \log (F) \log \left (c (d+e x)^n\right )}{2 \sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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Time = 0.08 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.097, Rules used = {2308, 2266, 2235} \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\frac {\sqrt {\pi } g^2 F^{a f} (d+e x)^3 e^{-\frac {9}{4 b f n^2 \log (F)}} \left (c (d+e x)^n\right )^{-3/n} \text {erfi}\left (\frac {2 b f n \log (F) \log \left (c (d+e x)^n\right )+3}{2 \sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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Rule 2235
Rule 2266
Rule 2308
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\left (c (d+e x)^n\right )^{-3/n} (d g+e g x)^3\right ) \text {Subst}\left (\int e^{\frac {3 x}{n}+a f \log (F)+b f x^2 \log (F)} \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e g n} \\ & = \frac {\left (e^{-\frac {9}{4 b f n^2 \log (F)}} F^{a f} \left (c (d+e x)^n\right )^{-3/n} (d g+e g x)^3\right ) \text {Subst}\left (\int e^{\frac {\left (\frac {3}{n}+2 b f x \log (F)\right )^2}{4 b f \log (F)}} \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e g n} \\ & = \frac {e^{-\frac {9}{4 b f n^2 \log (F)}} F^{a f} g^2 \sqrt {\pi } (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \text {erfi}\left (\frac {3+2 b f n \log (F) \log \left (c (d+e x)^n\right )}{2 \sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.00 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\frac {e^{-\frac {9}{4 b f n^2 \log (F)}} F^{a f} g^2 \sqrt {\pi } (d+e x)^3 \left (c (d+e x)^n\right )^{-3/n} \text {erfi}\left (\frac {3+2 b f n \log (F) \log \left (c (d+e x)^n\right )}{2 \sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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\[\int F^{f \left (a +b \ln \left (c \left (e x +d \right )^{n}\right )^{2}\right )} \left (e g x +d g \right )^{2}d x\]
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none
Time = 0.30 (sec) , antiderivative size = 119, normalized size of antiderivative = 0.97 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=-\frac {\sqrt {\pi } \sqrt {-b f n^{2} \log \left (F\right )} g^{2} \operatorname {erf}\left (\frac {{\left (2 \, b f n^{2} \log \left (e x + d\right ) \log \left (F\right ) + 2 \, b f n \log \left (F\right ) \log \left (c\right ) + 3\right )} \sqrt {-b f n^{2} \log \left (F\right )}}{2 \, b f n^{2} \log \left (F\right )}\right ) e^{\left (\frac {4 \, a b f^{2} n^{2} \log \left (F\right )^{2} - 12 \, b f n \log \left (F\right ) \log \left (c\right ) - 9}{4 \, b f n^{2} \log \left (F\right )}\right )}}{2 \, e n} \]
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Leaf count of result is larger than twice the leaf count of optimal. 525 vs. \(2 (110) = 220\).
Time = 89.19 (sec) , antiderivative size = 525, normalized size of antiderivative = 4.27 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\begin {cases} - \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{3} f g^{2} n^{2} \log {\left (F \right )}}{9 e} - \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{3} f g^{2} n \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{9 e} + \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{2} f g^{2} n^{2} x \log {\left (F \right )}}{9} - \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{2} f g^{2} n x \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{3} + \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d e f g^{2} n^{2} x^{2} \log {\left (F \right )}}{9} - \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d e f g^{2} n x^{2} \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{3} + \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b e^{2} f g^{2} n^{2} x^{3} \log {\left (F \right )}}{27} - \frac {2 F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b e^{2} f g^{2} n x^{3} \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{9} + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} d^{3} g^{2}}{3 e} + F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} d^{2} g^{2} x + F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} d e g^{2} x^{2} + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} e^{2} g^{2} x^{3}}{3} & \text {for}\: e \neq 0 \\F^{f \left (a + b \log {\left (c d^{n} \right )}^{2}\right )} d^{2} g^{2} x & \text {otherwise} \end {cases} \]
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\[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\int { {\left (e g x + d g\right )}^{2} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + a\right )} f} \,d x } \]
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\[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\int { {\left (e g x + d g\right )}^{2} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + a\right )} f} \,d x } \]
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Timed out. \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x)^2 \, dx=\int {\mathrm {e}}^{f\,\ln \left (F\right )\,\left (b\,{\ln \left (c\,{\left (d+e\,x\right )}^n\right )}^2+a\right )}\,{\left (d\,g+e\,g\,x\right )}^2 \,d x \]
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