Integrand size = 29, antiderivative size = 115 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\frac {e^{-\frac {1}{b f n^2 \log (F)}} F^{a f} g \sqrt {\pi } (d+e x)^2 \left (c (d+e x)^n\right )^{-2/n} \text {erfi}\left (\frac {1+b f n \log (F) \log \left (c (d+e x)^n\right )}{\sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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Time = 0.07 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {2308, 2266, 2235} \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\frac {\sqrt {\pi } g F^{a f} (d+e x)^2 e^{-\frac {1}{b f n^2 \log (F)}} \left (c (d+e x)^n\right )^{-2/n} \text {erfi}\left (\frac {b f n \log (F) \log \left (c (d+e x)^n\right )+1}{\sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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Rule 2235
Rule 2266
Rule 2308
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\left (c (d+e x)^n\right )^{-2/n} (d g+e g x)^2\right ) \text {Subst}\left (\int e^{\frac {2 x}{n}+a f \log (F)+b f x^2 \log (F)} \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e g n} \\ & = \frac {\left (e^{-\frac {1}{b f n^2 \log (F)}} F^{a f} \left (c (d+e x)^n\right )^{-2/n} (d g+e g x)^2\right ) \text {Subst}\left (\int e^{\frac {\left (\frac {2}{n}+2 b f x \log (F)\right )^2}{4 b f \log (F)}} \, dx,x,\log \left (c (d+e x)^n\right )\right )}{e g n} \\ & = \frac {e^{-\frac {1}{b f n^2 \log (F)}} F^{a f} g \sqrt {\pi } (d+e x)^2 \left (c (d+e x)^n\right )^{-2/n} \text {erfi}\left (\frac {1+b f n \log (F) \log \left (c (d+e x)^n\right )}{\sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \\ \end{align*}
Time = 0.48 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.00 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\frac {e^{-\frac {1}{b f n^2 \log (F)}} F^{a f} g \sqrt {\pi } (d+e x)^2 \left (c (d+e x)^n\right )^{-2/n} \text {erfi}\left (\frac {1+b f n \log (F) \log \left (c (d+e x)^n\right )}{\sqrt {b} \sqrt {f} n \sqrt {\log (F)}}\right )}{2 \sqrt {b} e \sqrt {f} n \sqrt {\log (F)}} \]
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\[\int F^{f \left (a +b \ln \left (c \left (e x +d \right )^{n}\right )^{2}\right )} \left (e g x +d g \right )d x\]
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none
Time = 0.33 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.97 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=-\frac {\sqrt {\pi } \sqrt {-b f n^{2} \log \left (F\right )} g \operatorname {erf}\left (\frac {{\left (b f n^{2} \log \left (e x + d\right ) \log \left (F\right ) + b f n \log \left (F\right ) \log \left (c\right ) + 1\right )} \sqrt {-b f n^{2} \log \left (F\right )}}{b f n^{2} \log \left (F\right )}\right ) e^{\left (\frac {a b f^{2} n^{2} \log \left (F\right )^{2} - 2 \, b f n \log \left (F\right ) \log \left (c\right ) - 1}{b f n^{2} \log \left (F\right )}\right )}}{2 \, e n} \]
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Leaf count of result is larger than twice the leaf count of optimal. 357 vs. \(2 (105) = 210\).
Time = 19.43 (sec) , antiderivative size = 357, normalized size of antiderivative = 3.10 \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\begin {cases} - \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{2} f g n^{2} \log {\left (F \right )}}{2 e} - \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d^{2} f g n \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{2 e} + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d f g n^{2} x \log {\left (F \right )}}{2} - F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b d f g n x \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )} + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b e f g n^{2} x^{2} \log {\left (F \right )}}{4} - \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} b e f g n x^{2} \log {\left (F \right )} \log {\left (c \left (d + e x\right )^{n} \right )}}{2} + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} d^{2} g}{2 e} + F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} d g x + \frac {F^{a f + b f \log {\left (c \left (d + e x\right )^{n} \right )}^{2}} e g x^{2}}{2} & \text {for}\: e \neq 0 \\F^{f \left (a + b \log {\left (c d^{n} \right )}^{2}\right )} d g x & \text {otherwise} \end {cases} \]
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\[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\int { {\left (e g x + d g\right )} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + a\right )} f} \,d x } \]
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\[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\int { {\left (e g x + d g\right )} F^{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right )^{2} + a\right )} f} \,d x } \]
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Timed out. \[ \int F^{f \left (a+b \log ^2\left (c (d+e x)^n\right )\right )} (d g+e g x) \, dx=\int {\mathrm {e}}^{f\,\ln \left (F\right )\,\left (b\,{\ln \left (c\,{\left (d+e\,x\right )}^n\right )}^2+a\right )}\,\left (d\,g+e\,g\,x\right ) \,d x \]
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