Integrand size = 31, antiderivative size = 49 \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\left (-a-b x-c x^2\right )^{-m} \left (a+b x+c x^2\right )^m \Gamma \left (1+m,-a-b x-c x^2\right ) \]
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Time = 0.14 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.065, Rules used = {6839, 2212} \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\left (-a-b x-c x^2\right )^{-m} \left (a+b x+c x^2\right )^m \Gamma \left (m+1,-c x^2-b x-a\right ) \]
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Rule 2212
Rule 6839
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int e^x x^m \, dx,x,a+b x+c x^2\right ) \\ & = \left (-a-b x-c x^2\right )^{-m} \left (a+b x+c x^2\right )^m \Gamma \left (1+m,-a-b x-c x^2\right ) \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 44, normalized size of antiderivative = 0.90 \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=(-a-x (b+c x))^{-m} (a+x (b+c x))^m \Gamma (1+m,-a-x (b+c x)) \]
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\[\int {\mathrm e}^{c \,x^{2}+b x +a} \left (2 x c +b \right ) \left (c \,x^{2}+b x +a \right )^{m}d x\]
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Result contains complex when optimal does not.
Time = 0.09 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.49 \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=e^{\left (-i \, \pi m\right )} \Gamma \left (m + 1, -c x^{2} - b x - a\right ) \]
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Timed out. \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\text {Timed out} \]
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\[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\int { {\left (2 \, c x + b\right )} {\left (c x^{2} + b x + a\right )}^{m} e^{\left (c x^{2} + b x + a\right )} \,d x } \]
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\[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\int { {\left (2 \, c x + b\right )} {\left (c x^{2} + b x + a\right )}^{m} e^{\left (c x^{2} + b x + a\right )} \,d x } \]
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Time = 0.40 (sec) , antiderivative size = 49, normalized size of antiderivative = 1.00 \[ \int e^{a+b x+c x^2} (b+2 c x) \left (a+b x+c x^2\right )^m \, dx=\frac {\Gamma \left (m+1,-c\,x^2-b\,x-a\right )\,{\left (c\,x^2+b\,x+a\right )}^m}{{\left (-c\,x^2-b\,x-a\right )}^m} \]
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