Integrand size = 22, antiderivative size = 139 \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=-\frac {320 (3 \cos (d+e x)-4 \sin (d+e x))}{3 e \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)}}-\frac {16 (3 \cos (d+e x)-4 \sin (d+e x)) \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)}}{3 e}-\frac {2 (3 \cos (d+e x)-4 \sin (d+e x)) (5+4 \cos (d+e x)+3 \sin (d+e x))^{3/2}}{5 e} \]
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Time = 0.08 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {3192, 3191} \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=-\frac {2 (3 \cos (d+e x)-4 \sin (d+e x)) (3 \sin (d+e x)+4 \cos (d+e x)+5)^{3/2}}{5 e}-\frac {16 (3 \cos (d+e x)-4 \sin (d+e x)) \sqrt {3 \sin (d+e x)+4 \cos (d+e x)+5}}{3 e}-\frac {320 (3 \cos (d+e x)-4 \sin (d+e x))}{3 e \sqrt {3 \sin (d+e x)+4 \cos (d+e x)+5}} \]
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Rule 3191
Rule 3192
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (3 \cos (d+e x)-4 \sin (d+e x)) (5+4 \cos (d+e x)+3 \sin (d+e x))^{3/2}}{5 e}+8 \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{3/2} \, dx \\ & = -\frac {16 (3 \cos (d+e x)-4 \sin (d+e x)) \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)}}{3 e}-\frac {2 (3 \cos (d+e x)-4 \sin (d+e x)) (5+4 \cos (d+e x)+3 \sin (d+e x))^{3/2}}{5 e}+\frac {160}{3} \int \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)} \, dx \\ & = -\frac {320 (3 \cos (d+e x)-4 \sin (d+e x))}{3 e \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)}}-\frac {16 (3 \cos (d+e x)-4 \sin (d+e x)) \sqrt {5+4 \cos (d+e x)+3 \sin (d+e x)}}{3 e}-\frac {2 (3 \cos (d+e x)-4 \sin (d+e x)) (5+4 \cos (d+e x)+3 \sin (d+e x))^{3/2}}{5 e} \\ \end{align*}
Time = 6.25 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.94 \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=-\frac {(5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \left (3750 \cos \left (\frac {1}{2} (d+e x)\right )+1625 \cos \left (\frac {3}{2} (d+e x)\right )+3 \left (79 \cos \left (\frac {5}{2} (d+e x)\right )-3750 \sin \left (\frac {1}{2} (d+e x)\right )-375 \sin \left (\frac {3}{2} (d+e x)\right )+3 \sin \left (\frac {5}{2} (d+e x)\right )\right )\right )}{30 e \left (3 \cos \left (\frac {1}{2} (d+e x)\right )+\sin \left (\frac {1}{2} (d+e x)\right )\right )^5} \]
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Time = 1.06 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.53
method | result | size |
default | \(\frac {50 \left (1+\sin \left (e x +d +\arctan \left (\frac {4}{3}\right )\right )\right ) \left (\sin \left (e x +d +\arctan \left (\frac {4}{3}\right )\right )-1\right ) \left (3 \sin \left (e x +d +\arctan \left (\frac {4}{3}\right )\right )^{2}+14 \sin \left (e x +d +\arctan \left (\frac {4}{3}\right )\right )+43\right )}{3 \cos \left (e x +d +\arctan \left (\frac {4}{3}\right )\right ) \sqrt {5+5 \sin \left (e x +d +\arctan \left (\frac {4}{3}\right )\right )}\, e}\) | \(74\) |
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Time = 0.24 (sec) , antiderivative size = 101, normalized size of antiderivative = 0.73 \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=-\frac {2 \, {\left (237 \, \cos \left (e x + d\right )^{3} + 931 \, \cos \left (e x + d\right )^{2} + 9 \, {\left (\cos \left (e x + d\right )^{2} - 62 \, \cos \left (e x + d\right ) - 344\right )} \sin \left (e x + d\right ) + 1166 \, \cos \left (e x + d\right ) + 472\right )} \sqrt {4 \, \cos \left (e x + d\right ) + 3 \, \sin \left (e x + d\right ) + 5}}{15 \, {\left (3 \, e \cos \left (e x + d\right ) + e \sin \left (e x + d\right ) + 3 \, e\right )}} \]
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Timed out. \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=\text {Timed out} \]
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\[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=\int { {\left (4 \, \cos \left (e x + d\right ) + 3 \, \sin \left (e x + d\right ) + 5\right )}^{\frac {5}{2}} \,d x } \]
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\[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=\int { {\left (4 \, \cos \left (e x + d\right ) + 3 \, \sin \left (e x + d\right ) + 5\right )}^{\frac {5}{2}} \,d x } \]
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Timed out. \[ \int (5+4 \cos (d+e x)+3 \sin (d+e x))^{5/2} \, dx=\int {\left (4\,\cos \left (d+e\,x\right )+3\,\sin \left (d+e\,x\right )+5\right )}^{5/2} \,d x \]
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