Integrand size = 14, antiderivative size = 63 \[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=-\frac {\sqrt {1+a^2 x^2}}{2 x^2}+\frac {i a \sqrt {1+a^2 x^2}}{x}+\frac {1}{2} a^2 \text {arctanh}\left (\sqrt {1+a^2 x^2}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {5168, 849, 821, 272, 65, 214} \[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\frac {1}{2} a^2 \text {arctanh}\left (\sqrt {a^2 x^2+1}\right )+\frac {i a \sqrt {a^2 x^2+1}}{x}-\frac {\sqrt {a^2 x^2+1}}{2 x^2} \]
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Rule 65
Rule 214
Rule 272
Rule 821
Rule 849
Rule 5168
Rubi steps \begin{align*} \text {integral}& = \int \frac {1-i a x}{x^3 \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{2 x^2}-\frac {1}{2} \int \frac {2 i a+a^2 x}{x^2 \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{2 x^2}+\frac {i a \sqrt {1+a^2 x^2}}{x}-\frac {1}{2} a^2 \int \frac {1}{x \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{2 x^2}+\frac {i a \sqrt {1+a^2 x^2}}{x}-\frac {1}{4} a^2 \text {Subst}\left (\int \frac {1}{x \sqrt {1+a^2 x}} \, dx,x,x^2\right ) \\ & = -\frac {\sqrt {1+a^2 x^2}}{2 x^2}+\frac {i a \sqrt {1+a^2 x^2}}{x}-\frac {1}{2} \text {Subst}\left (\int \frac {1}{-\frac {1}{a^2}+\frac {x^2}{a^2}} \, dx,x,\sqrt {1+a^2 x^2}\right ) \\ & = -\frac {\sqrt {1+a^2 x^2}}{2 x^2}+\frac {i a \sqrt {1+a^2 x^2}}{x}+\frac {1}{2} a^2 \text {arctanh}\left (\sqrt {1+a^2 x^2}\right ) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.90 \[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\frac {1}{2} \left (\frac {(-1+2 i a x) \sqrt {1+a^2 x^2}}{x^2}-a^2 \log (x)+a^2 \log \left (1+\sqrt {1+a^2 x^2}\right )\right ) \]
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Time = 0.25 (sec) , antiderivative size = 60, normalized size of antiderivative = 0.95
method | result | size |
risch | \(\frac {i \left (2 a^{3} x^{3}+i a^{2} x^{2}+2 a x +i\right )}{2 x^{2} \sqrt {a^{2} x^{2}+1}}+\frac {a^{2} \operatorname {arctanh}\left (\frac {1}{\sqrt {a^{2} x^{2}+1}}\right )}{2}\) | \(60\) |
default | \(-\frac {\left (a^{2} x^{2}+1\right )^{\frac {3}{2}}}{2 x^{2}}-\frac {a^{2} \left (\sqrt {a^{2} x^{2}+1}-\operatorname {arctanh}\left (\frac {1}{\sqrt {a^{2} x^{2}+1}}\right )\right )}{2}-i a \left (-\frac {\left (a^{2} x^{2}+1\right )^{\frac {3}{2}}}{x}+2 a^{2} \left (\frac {\sqrt {a^{2} x^{2}+1}\, x}{2}+\frac {\ln \left (\frac {a^{2} x}{\sqrt {a^{2}}}+\sqrt {a^{2} x^{2}+1}\right )}{2 \sqrt {a^{2}}}\right )\right )+a^{2} \left (\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}+\frac {i a \ln \left (\frac {i a +\left (x -\frac {i}{a}\right ) a^{2}}{\sqrt {a^{2}}}+\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}\right )}{\sqrt {a^{2}}}\right )\) | \(217\) |
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Time = 0.27 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.32 \[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\frac {a^{2} x^{2} \log \left (-a x + \sqrt {a^{2} x^{2} + 1} + 1\right ) - a^{2} x^{2} \log \left (-a x + \sqrt {a^{2} x^{2} + 1} - 1\right ) + 2 i \, a^{2} x^{2} + \sqrt {a^{2} x^{2} + 1} {\left (2 i \, a x - 1\right )}}{2 \, x^{2}} \]
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\[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=- i \int \frac {\sqrt {a^{2} x^{2} + 1}}{a x^{4} - i x^{3}}\, dx \]
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\[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\int { \frac {\sqrt {a^{2} x^{2} + 1}}{{\left (i \, a x + 1\right )} x^{3}} \,d x } \]
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\[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\int { \frac {\sqrt {a^{2} x^{2} + 1}}{{\left (i \, a x + 1\right )} x^{3}} \,d x } \]
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Time = 0.04 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.83 \[ \int \frac {e^{-i \arctan (a x)}}{x^3} \, dx=\frac {a^2\,\mathrm {atanh}\left (\sqrt {a^2\,x^2+1}\right )}{2}-\frac {\sqrt {a^2\,x^2+1}}{2\,x^2}+\frac {a\,\sqrt {a^2\,x^2+1}\,1{}\mathrm {i}}{x} \]
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