Integrand size = 14, antiderivative size = 90 \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=-\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {2 a^2 \sqrt {1+a^2 x^2}}{3 x}-\frac {1}{2} i a^3 \text {arctanh}\left (\sqrt {1+a^2 x^2}\right ) \]
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Time = 0.05 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {5168, 849, 821, 272, 65, 214} \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\frac {2 a^2 \sqrt {a^2 x^2+1}}{3 x}+\frac {i a \sqrt {a^2 x^2+1}}{2 x^2}-\frac {\sqrt {a^2 x^2+1}}{3 x^3}-\frac {1}{2} i a^3 \text {arctanh}\left (\sqrt {a^2 x^2+1}\right ) \]
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Rule 65
Rule 214
Rule 272
Rule 821
Rule 849
Rule 5168
Rubi steps \begin{align*} \text {integral}& = \int \frac {1-i a x}{x^4 \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}-\frac {1}{3} \int \frac {3 i a+2 a^2 x}{x^3 \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {1}{6} \int \frac {-4 a^2+3 i a^3 x}{x^2 \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {2 a^2 \sqrt {1+a^2 x^2}}{3 x}+\frac {1}{2} \left (i a^3\right ) \int \frac {1}{x \sqrt {1+a^2 x^2}} \, dx \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {2 a^2 \sqrt {1+a^2 x^2}}{3 x}+\frac {1}{4} \left (i a^3\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {1+a^2 x}} \, dx,x,x^2\right ) \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {2 a^2 \sqrt {1+a^2 x^2}}{3 x}+\frac {1}{2} (i a) \text {Subst}\left (\int \frac {1}{-\frac {1}{a^2}+\frac {x^2}{a^2}} \, dx,x,\sqrt {1+a^2 x^2}\right ) \\ & = -\frac {\sqrt {1+a^2 x^2}}{3 x^3}+\frac {i a \sqrt {1+a^2 x^2}}{2 x^2}+\frac {2 a^2 \sqrt {1+a^2 x^2}}{3 x}-\frac {1}{2} i a^3 \text {arctanh}\left (\sqrt {1+a^2 x^2}\right ) \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.78 \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\frac {1}{6} \left (\frac {\sqrt {1+a^2 x^2} \left (-2+3 i a x+4 a^2 x^2\right )}{x^3}+3 i a^3 \log (x)-3 i a^3 \log \left (1+\sqrt {1+a^2 x^2}\right )\right ) \]
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Time = 0.25 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.76
method | result | size |
risch | \(\frac {4 a^{4} x^{4}+3 i a^{3} x^{3}+2 a^{2} x^{2}+3 i a x -2}{6 x^{3} \sqrt {a^{2} x^{2}+1}}-\frac {i a^{3} \operatorname {arctanh}\left (\frac {1}{\sqrt {a^{2} x^{2}+1}}\right )}{2}\) | \(68\) |
default | \(-\frac {\left (a^{2} x^{2}+1\right )^{\frac {3}{2}}}{3 x^{3}}-a^{2} \left (-\frac {\left (a^{2} x^{2}+1\right )^{\frac {3}{2}}}{x}+2 a^{2} \left (\frac {\sqrt {a^{2} x^{2}+1}\, x}{2}+\frac {\ln \left (\frac {a^{2} x}{\sqrt {a^{2}}}+\sqrt {a^{2} x^{2}+1}\right )}{2 \sqrt {a^{2}}}\right )\right )+i a^{3} \left (\sqrt {a^{2} x^{2}+1}-\operatorname {arctanh}\left (\frac {1}{\sqrt {a^{2} x^{2}+1}}\right )\right )-i a \left (-\frac {\left (a^{2} x^{2}+1\right )^{\frac {3}{2}}}{2 x^{2}}+\frac {a^{2} \left (\sqrt {a^{2} x^{2}+1}-\operatorname {arctanh}\left (\frac {1}{\sqrt {a^{2} x^{2}+1}}\right )\right )}{2}\right )-i a^{3} \left (\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}+\frac {i a \ln \left (\frac {i a +\left (x -\frac {i}{a}\right ) a^{2}}{\sqrt {a^{2}}}+\sqrt {\left (x -\frac {i}{a}\right )^{2} a^{2}+2 i a \left (x -\frac {i}{a}\right )}\right )}{\sqrt {a^{2}}}\right )\) | \(273\) |
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Time = 0.26 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.02 \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\frac {-3 i \, a^{3} x^{3} \log \left (-a x + \sqrt {a^{2} x^{2} + 1} + 1\right ) + 3 i \, a^{3} x^{3} \log \left (-a x + \sqrt {a^{2} x^{2} + 1} - 1\right ) + 4 \, a^{3} x^{3} + {\left (4 \, a^{2} x^{2} + 3 i \, a x - 2\right )} \sqrt {a^{2} x^{2} + 1}}{6 \, x^{3}} \]
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\[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=- i \int \frac {\sqrt {a^{2} x^{2} + 1}}{a x^{5} - i x^{4}}\, dx \]
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\[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\int { \frac {\sqrt {a^{2} x^{2} + 1}}{{\left (i \, a x + 1\right )} x^{4}} \,d x } \]
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Exception generated. \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\text {Exception raised: TypeError} \]
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Time = 0.04 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.82 \[ \int \frac {e^{-i \arctan (a x)}}{x^4} \, dx=\frac {2\,a^2\,\sqrt {a^2\,x^2+1}}{3\,x}-\frac {\sqrt {a^2\,x^2+1}}{3\,x^3}-\frac {a^3\,\mathrm {atan}\left (\sqrt {a^2\,x^2+1}\,1{}\mathrm {i}\right )}{2}+\frac {a\,\sqrt {a^2\,x^2+1}\,1{}\mathrm {i}}{2\,x^2} \]
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