Integrand size = 8, antiderivative size = 55 \[ \int \text {sech}^5(a+b x) \, dx=\frac {3 \arctan (\sinh (a+b x))}{8 b}+\frac {3 \text {sech}(a+b x) \tanh (a+b x)}{8 b}+\frac {\text {sech}^3(a+b x) \tanh (a+b x)}{4 b} \]
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Time = 0.02 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {3853, 3855} \[ \int \text {sech}^5(a+b x) \, dx=\frac {3 \arctan (\sinh (a+b x))}{8 b}+\frac {\tanh (a+b x) \text {sech}^3(a+b x)}{4 b}+\frac {3 \tanh (a+b x) \text {sech}(a+b x)}{8 b} \]
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Rule 3853
Rule 3855
Rubi steps \begin{align*} \text {integral}& = \frac {\text {sech}^3(a+b x) \tanh (a+b x)}{4 b}+\frac {3}{4} \int \text {sech}^3(a+b x) \, dx \\ & = \frac {3 \text {sech}(a+b x) \tanh (a+b x)}{8 b}+\frac {\text {sech}^3(a+b x) \tanh (a+b x)}{4 b}+\frac {3}{8} \int \text {sech}(a+b x) \, dx \\ & = \frac {3 \arctan (\sinh (a+b x))}{8 b}+\frac {3 \text {sech}(a+b x) \tanh (a+b x)}{8 b}+\frac {\text {sech}^3(a+b x) \tanh (a+b x)}{4 b} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.00 \[ \int \text {sech}^5(a+b x) \, dx=\frac {3 \arctan (\sinh (a+b x))}{8 b}+\frac {3 \text {sech}(a+b x) \tanh (a+b x)}{8 b}+\frac {\text {sech}^3(a+b x) \tanh (a+b x)}{4 b} \]
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Time = 0.84 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.75
method | result | size |
derivativedivides | \(\frac {\left (\frac {\operatorname {sech}\left (b x +a \right )^{3}}{4}+\frac {3 \,\operatorname {sech}\left (b x +a \right )}{8}\right ) \tanh \left (b x +a \right )+\frac {3 \arctan \left ({\mathrm e}^{b x +a}\right )}{4}}{b}\) | \(41\) |
default | \(\frac {\left (\frac {\operatorname {sech}\left (b x +a \right )^{3}}{4}+\frac {3 \,\operatorname {sech}\left (b x +a \right )}{8}\right ) \tanh \left (b x +a \right )+\frac {3 \arctan \left ({\mathrm e}^{b x +a}\right )}{4}}{b}\) | \(41\) |
risch | \(\frac {{\mathrm e}^{b x +a} \left (3 \,{\mathrm e}^{6 b x +6 a}+11 \,{\mathrm e}^{4 b x +4 a}-11 \,{\mathrm e}^{2 b x +2 a}-3\right )}{4 b \left (1+{\mathrm e}^{2 b x +2 a}\right )^{4}}+\frac {3 i \ln \left ({\mathrm e}^{b x +a}+i\right )}{8 b}-\frac {3 i \ln \left ({\mathrm e}^{b x +a}-i\right )}{8 b}\) | \(93\) |
parallelrisch | \(\frac {3 i \left (-3-\cosh \left (4 b x +4 a \right )-4 \cosh \left (2 b x +2 a \right )\right ) \ln \left (\tanh \left (\frac {b x}{2}+\frac {a}{2}\right )-i\right )+3 i \left (3+\cosh \left (4 b x +4 a \right )+4 \cosh \left (2 b x +2 a \right )\right ) \ln \left (\tanh \left (\frac {b x}{2}+\frac {a}{2}\right )+i\right )+22 \sinh \left (b x +a \right )+6 \sinh \left (3 b x +3 a \right )}{8 b \left (3+\cosh \left (4 b x +4 a \right )+4 \cosh \left (2 b x +2 a \right )\right )}\) | \(128\) |
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Leaf count of result is larger than twice the leaf count of optimal. 812 vs. \(2 (49) = 98\).
Time = 0.24 (sec) , antiderivative size = 812, normalized size of antiderivative = 14.76 \[ \int \text {sech}^5(a+b x) \, dx=\text {Too large to display} \]
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\[ \int \text {sech}^5(a+b x) \, dx=\int \operatorname {sech}^{5}{\left (a + b x \right )}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 112 vs. \(2 (49) = 98\).
Time = 0.29 (sec) , antiderivative size = 112, normalized size of antiderivative = 2.04 \[ \int \text {sech}^5(a+b x) \, dx=-\frac {3 \, \arctan \left (e^{\left (-b x - a\right )}\right )}{4 \, b} + \frac {3 \, e^{\left (-b x - a\right )} + 11 \, e^{\left (-3 \, b x - 3 \, a\right )} - 11 \, e^{\left (-5 \, b x - 5 \, a\right )} - 3 \, e^{\left (-7 \, b x - 7 \, a\right )}}{4 \, b {\left (4 \, e^{\left (-2 \, b x - 2 \, a\right )} + 6 \, e^{\left (-4 \, b x - 4 \, a\right )} + 4 \, e^{\left (-6 \, b x - 6 \, a\right )} + e^{\left (-8 \, b x - 8 \, a\right )} + 1\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 102 vs. \(2 (49) = 98\).
Time = 0.27 (sec) , antiderivative size = 102, normalized size of antiderivative = 1.85 \[ \int \text {sech}^5(a+b x) \, dx=\frac {3 \, \pi + \frac {4 \, {\left (3 \, {\left (e^{\left (b x + a\right )} - e^{\left (-b x - a\right )}\right )}^{3} + 20 \, e^{\left (b x + a\right )} - 20 \, e^{\left (-b x - a\right )}\right )}}{{\left ({\left (e^{\left (b x + a\right )} - e^{\left (-b x - a\right )}\right )}^{2} + 4\right )}^{2}} + 6 \, \arctan \left (\frac {1}{2} \, {\left (e^{\left (2 \, b x + 2 \, a\right )} - 1\right )} e^{\left (-b x - a\right )}\right )}{16 \, b} \]
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Time = 2.02 (sec) , antiderivative size = 189, normalized size of antiderivative = 3.44 \[ \int \text {sech}^5(a+b x) \, dx=\frac {3\,\mathrm {atan}\left (\frac {{\mathrm {e}}^{b\,x}\,{\mathrm {e}}^a\,\sqrt {b^2}}{b}\right )}{4\,\sqrt {b^2}}+\frac {{\mathrm {e}}^{a+b\,x}}{2\,b\,\left (2\,{\mathrm {e}}^{2\,a+2\,b\,x}+{\mathrm {e}}^{4\,a+4\,b\,x}+1\right )}-\frac {2\,{\mathrm {e}}^{a+b\,x}}{b\,\left (3\,{\mathrm {e}}^{2\,a+2\,b\,x}+3\,{\mathrm {e}}^{4\,a+4\,b\,x}+{\mathrm {e}}^{6\,a+6\,b\,x}+1\right )}-\frac {4\,{\mathrm {e}}^{3\,a+3\,b\,x}}{b\,\left (4\,{\mathrm {e}}^{2\,a+2\,b\,x}+6\,{\mathrm {e}}^{4\,a+4\,b\,x}+4\,{\mathrm {e}}^{6\,a+6\,b\,x}+{\mathrm {e}}^{8\,a+8\,b\,x}+1\right )}+\frac {3\,{\mathrm {e}}^{a+b\,x}}{4\,b\,\left ({\mathrm {e}}^{2\,a+2\,b\,x}+1\right )} \]
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