Integrand size = 8, antiderivative size = 41 \[ \int \text {sech}^6(a+b x) \, dx=\frac {\tanh (a+b x)}{b}-\frac {2 \tanh ^3(a+b x)}{3 b}+\frac {\tanh ^5(a+b x)}{5 b} \]
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Time = 0.01 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {3852} \[ \int \text {sech}^6(a+b x) \, dx=\frac {\tanh ^5(a+b x)}{5 b}-\frac {2 \tanh ^3(a+b x)}{3 b}+\frac {\tanh (a+b x)}{b} \]
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Rule 3852
Rubi steps \begin{align*} \text {integral}& = \frac {i \text {Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,-i \tanh (a+b x)\right )}{b} \\ & = \frac {\tanh (a+b x)}{b}-\frac {2 \tanh ^3(a+b x)}{3 b}+\frac {\tanh ^5(a+b x)}{5 b} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.00 \[ \int \text {sech}^6(a+b x) \, dx=\frac {\tanh (a+b x)}{b}-\frac {2 \tanh ^3(a+b x)}{3 b}+\frac {\tanh ^5(a+b x)}{5 b} \]
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Time = 0.70 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.80
method | result | size |
derivativedivides | \(\frac {\left (\frac {8}{15}+\frac {\operatorname {sech}\left (b x +a \right )^{4}}{5}+\frac {4 \operatorname {sech}\left (b x +a \right )^{2}}{15}\right ) \tanh \left (b x +a \right )}{b}\) | \(33\) |
default | \(\frac {\left (\frac {8}{15}+\frac {\operatorname {sech}\left (b x +a \right )^{4}}{5}+\frac {4 \operatorname {sech}\left (b x +a \right )^{2}}{15}\right ) \tanh \left (b x +a \right )}{b}\) | \(33\) |
risch | \(-\frac {16 \left (10 \,{\mathrm e}^{4 b x +4 a}+5 \,{\mathrm e}^{2 b x +2 a}+1\right )}{15 b \left (1+{\mathrm e}^{2 b x +2 a}\right )^{5}}\) | \(43\) |
parallelrisch | \(\frac {\frac {8 \tanh \left (\frac {b x}{2}+\frac {a}{2}\right )^{3}}{3}+\frac {8 \tanh \left (\frac {b x}{2}+\frac {a}{2}\right )^{7}}{3}+2 \tanh \left (\frac {b x}{2}+\frac {a}{2}\right )^{9}+\frac {116 \tanh \left (\frac {b x}{2}+\frac {a}{2}\right )^{5}}{15}+2 \tanh \left (\frac {b x}{2}+\frac {a}{2}\right )}{b \left (1+\tanh \left (\frac {b x}{2}+\frac {a}{2}\right )^{2}\right )^{5}}\) | \(85\) |
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Leaf count of result is larger than twice the leaf count of optimal. 344 vs. \(2 (37) = 74\).
Time = 0.26 (sec) , antiderivative size = 344, normalized size of antiderivative = 8.39 \[ \int \text {sech}^6(a+b x) \, dx=-\frac {16 \, {\left (11 \, \cosh \left (b x + a\right )^{2} + 18 \, \cosh \left (b x + a\right ) \sinh \left (b x + a\right ) + 11 \, \sinh \left (b x + a\right )^{2} + 5\right )}}{15 \, {\left (b \cosh \left (b x + a\right )^{8} + 8 \, b \cosh \left (b x + a\right ) \sinh \left (b x + a\right )^{7} + b \sinh \left (b x + a\right )^{8} + 5 \, b \cosh \left (b x + a\right )^{6} + {\left (28 \, b \cosh \left (b x + a\right )^{2} + 5 \, b\right )} \sinh \left (b x + a\right )^{6} + 2 \, {\left (28 \, b \cosh \left (b x + a\right )^{3} + 15 \, b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{5} + 10 \, b \cosh \left (b x + a\right )^{4} + 5 \, {\left (14 \, b \cosh \left (b x + a\right )^{4} + 15 \, b \cosh \left (b x + a\right )^{2} + 2 \, b\right )} \sinh \left (b x + a\right )^{4} + 4 \, {\left (14 \, b \cosh \left (b x + a\right )^{5} + 25 \, b \cosh \left (b x + a\right )^{3} + 10 \, b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right )^{3} + 11 \, b \cosh \left (b x + a\right )^{2} + {\left (28 \, b \cosh \left (b x + a\right )^{6} + 75 \, b \cosh \left (b x + a\right )^{4} + 60 \, b \cosh \left (b x + a\right )^{2} + 11 \, b\right )} \sinh \left (b x + a\right )^{2} + 2 \, {\left (4 \, b \cosh \left (b x + a\right )^{7} + 15 \, b \cosh \left (b x + a\right )^{5} + 20 \, b \cosh \left (b x + a\right )^{3} + 9 \, b \cosh \left (b x + a\right )\right )} \sinh \left (b x + a\right ) + 5 \, b\right )}} \]
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\[ \int \text {sech}^6(a+b x) \, dx=\int \operatorname {sech}^{6}{\left (a + b x \right )}\, dx \]
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Leaf count of result is larger than twice the leaf count of optimal. 205 vs. \(2 (37) = 74\).
Time = 0.19 (sec) , antiderivative size = 205, normalized size of antiderivative = 5.00 \[ \int \text {sech}^6(a+b x) \, dx=\frac {16 \, e^{\left (-2 \, b x - 2 \, a\right )}}{3 \, b {\left (5 \, e^{\left (-2 \, b x - 2 \, a\right )} + 10 \, e^{\left (-4 \, b x - 4 \, a\right )} + 10 \, e^{\left (-6 \, b x - 6 \, a\right )} + 5 \, e^{\left (-8 \, b x - 8 \, a\right )} + e^{\left (-10 \, b x - 10 \, a\right )} + 1\right )}} + \frac {32 \, e^{\left (-4 \, b x - 4 \, a\right )}}{3 \, b {\left (5 \, e^{\left (-2 \, b x - 2 \, a\right )} + 10 \, e^{\left (-4 \, b x - 4 \, a\right )} + 10 \, e^{\left (-6 \, b x - 6 \, a\right )} + 5 \, e^{\left (-8 \, b x - 8 \, a\right )} + e^{\left (-10 \, b x - 10 \, a\right )} + 1\right )}} + \frac {16}{15 \, b {\left (5 \, e^{\left (-2 \, b x - 2 \, a\right )} + 10 \, e^{\left (-4 \, b x - 4 \, a\right )} + 10 \, e^{\left (-6 \, b x - 6 \, a\right )} + 5 \, e^{\left (-8 \, b x - 8 \, a\right )} + e^{\left (-10 \, b x - 10 \, a\right )} + 1\right )}} \]
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Time = 0.28 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.02 \[ \int \text {sech}^6(a+b x) \, dx=-\frac {16 \, {\left (10 \, e^{\left (4 \, b x + 4 \, a\right )} + 5 \, e^{\left (2 \, b x + 2 \, a\right )} + 1\right )}}{15 \, b {\left (e^{\left (2 \, b x + 2 \, a\right )} + 1\right )}^{5}} \]
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Time = 2.02 (sec) , antiderivative size = 42, normalized size of antiderivative = 1.02 \[ \int \text {sech}^6(a+b x) \, dx=-\frac {16\,\left (5\,{\mathrm {e}}^{2\,a+2\,b\,x}+10\,{\mathrm {e}}^{4\,a+4\,b\,x}+1\right )}{15\,b\,{\left ({\mathrm {e}}^{2\,a+2\,b\,x}+1\right )}^5} \]
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