Integrand size = 26, antiderivative size = 37 \[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\frac {\sqrt {b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )^{1+n}}{b (1+n) x} \]
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Time = 0.05 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {5871, 5783} \[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\frac {\sqrt {b x^2} \text {arcsinh}\left (\sqrt {b x^2-1}\right )^{n+1}}{b (n+1) x} \]
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Rule 5783
Rule 5871
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {b x^2} \text {Subst}\left (\int \frac {\text {arcsinh}(x)^n}{\sqrt {1+x^2}} \, dx,x,\sqrt {-1+b x^2}\right )}{b x} \\ & = \frac {\sqrt {b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )^{1+n}}{b (1+n) x} \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 37, normalized size of antiderivative = 1.00 \[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\frac {\sqrt {b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )^{1+n}}{b (1+n) x} \]
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\[\int \frac {\operatorname {arcsinh}\left (\sqrt {b \,x^{2}-1}\right )^{n}}{\sqrt {b \,x^{2}-1}}d x\]
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Leaf count of result is larger than twice the leaf count of optimal. 108 vs. \(2 (33) = 66\).
Time = 0.26 (sec) , antiderivative size = 108, normalized size of antiderivative = 2.92 \[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\frac {\sqrt {b x^{2}} \cosh \left (n \log \left (\log \left (\sqrt {b x^{2} - 1} + \sqrt {b x^{2}}\right )\right )\right ) \log \left (\sqrt {b x^{2} - 1} + \sqrt {b x^{2}}\right ) + \sqrt {b x^{2}} \log \left (\sqrt {b x^{2} - 1} + \sqrt {b x^{2}}\right ) \sinh \left (n \log \left (\log \left (\sqrt {b x^{2} - 1} + \sqrt {b x^{2}}\right )\right )\right )}{{\left (b n + b\right )} x} \]
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\[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\begin {cases} - \frac {2 x}{\pi } & \text {for}\: b = 0 \wedge n = -1 \\- i x \left (\frac {i \pi }{2}\right )^{n} & \text {for}\: b = 0 \\\int \frac {1}{\sqrt {b x^{2} - 1} \operatorname {asinh}{\left (\sqrt {b x^{2} - 1} \right )}}\, dx & \text {for}\: n = -1 \\\frac {\sqrt {b x^{2}} \operatorname {asinh}{\left (\sqrt {b x^{2} - 1} \right )} \operatorname {asinh}^{n}{\left (\sqrt {b x^{2} - 1} \right )}}{b n x + b x} & \text {otherwise} \end {cases} \]
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\[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\int { \frac {\operatorname {arsinh}\left (\sqrt {b x^{2} - 1}\right )^{n}}{\sqrt {b x^{2} - 1}} \,d x } \]
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\[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\int { \frac {\operatorname {arsinh}\left (\sqrt {b x^{2} - 1}\right )^{n}}{\sqrt {b x^{2} - 1}} \,d x } \]
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Timed out. \[ \int \frac {\text {arcsinh}\left (\sqrt {-1+b x^2}\right )^n}{\sqrt {-1+b x^2}} \, dx=\int \frac {{\mathrm {asinh}\left (\sqrt {b\,x^2-1}\right )}^n}{\sqrt {b\,x^2-1}} \,d x \]
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