Integrand size = 26, antiderivative size = 29 \[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\frac {\sqrt {b x^2} \log \left (\text {arcsinh}\left (\sqrt {-1+b x^2}\right )\right )}{b x} \]
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Time = 0.04 (sec) , antiderivative size = 29, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {5871, 5782} \[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\frac {\sqrt {b x^2} \log \left (\text {arcsinh}\left (\sqrt {b x^2-1}\right )\right )}{b x} \]
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Rule 5782
Rule 5871
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {b x^2} \text {Subst}\left (\int \frac {1}{\sqrt {1+x^2} \text {arcsinh}(x)} \, dx,x,\sqrt {-1+b x^2}\right )}{b x} \\ & = \frac {\sqrt {b x^2} \log \left (\text {arcsinh}\left (\sqrt {-1+b x^2}\right )\right )}{b x} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.83 \[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\frac {x \log \left (\text {arcsinh}\left (\sqrt {-1+b x^2}\right )\right )}{\sqrt {b x^2}} \]
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\[\int \frac {1}{\operatorname {arcsinh}\left (\sqrt {b \,x^{2}-1}\right ) \sqrt {b \,x^{2}-1}}d x\]
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none
Time = 0.24 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.14 \[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\frac {\sqrt {b x^{2}} \log \left (\log \left (\sqrt {b x^{2} - 1} + \sqrt {b x^{2}}\right )\right )}{b x} \]
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\[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\int \frac {1}{\sqrt {b x^{2} - 1} \operatorname {asinh}{\left (\sqrt {b x^{2} - 1} \right )}}\, dx \]
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\[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\int { \frac {1}{\sqrt {b x^{2} - 1} \operatorname {arsinh}\left (\sqrt {b x^{2} - 1}\right )} \,d x } \]
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\[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\int { \frac {1}{\sqrt {b x^{2} - 1} \operatorname {arsinh}\left (\sqrt {b x^{2} - 1}\right )} \,d x } \]
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Time = 2.64 (sec) , antiderivative size = 23, normalized size of antiderivative = 0.79 \[ \int \frac {1}{\sqrt {-1+b x^2} \text {arcsinh}\left (\sqrt {-1+b x^2}\right )} \, dx=\frac {\ln \left (\mathrm {asinh}\left (\sqrt {b\,x^2-1}\right )\right )\,\sqrt {x^2}}{\sqrt {b}\,x} \]
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