Integrand size = 8, antiderivative size = 78 \[ \int \text {arcsinh}(a+b x)^3 \, dx=-\frac {6 \sqrt {1+(a+b x)^2}}{b}+\frac {6 (a+b x) \text {arcsinh}(a+b x)}{b}-\frac {3 \sqrt {1+(a+b x)^2} \text {arcsinh}(a+b x)^2}{b}+\frac {(a+b x) \text {arcsinh}(a+b x)^3}{b} \]
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Time = 0.05 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {5858, 5772, 5798, 267} \[ \int \text {arcsinh}(a+b x)^3 \, dx=\frac {(a+b x) \text {arcsinh}(a+b x)^3}{b}-\frac {3 \sqrt {(a+b x)^2+1} \text {arcsinh}(a+b x)^2}{b}+\frac {6 (a+b x) \text {arcsinh}(a+b x)}{b}-\frac {6 \sqrt {(a+b x)^2+1}}{b} \]
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Rule 267
Rule 5772
Rule 5798
Rule 5858
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \text {arcsinh}(x)^3 \, dx,x,a+b x\right )}{b} \\ & = \frac {(a+b x) \text {arcsinh}(a+b x)^3}{b}-\frac {3 \text {Subst}\left (\int \frac {x \text {arcsinh}(x)^2}{\sqrt {1+x^2}} \, dx,x,a+b x\right )}{b} \\ & = -\frac {3 \sqrt {1+(a+b x)^2} \text {arcsinh}(a+b x)^2}{b}+\frac {(a+b x) \text {arcsinh}(a+b x)^3}{b}+\frac {6 \text {Subst}(\int \text {arcsinh}(x) \, dx,x,a+b x)}{b} \\ & = \frac {6 (a+b x) \text {arcsinh}(a+b x)}{b}-\frac {3 \sqrt {1+(a+b x)^2} \text {arcsinh}(a+b x)^2}{b}+\frac {(a+b x) \text {arcsinh}(a+b x)^3}{b}-\frac {6 \text {Subst}\left (\int \frac {x}{\sqrt {1+x^2}} \, dx,x,a+b x\right )}{b} \\ & = -\frac {6 \sqrt {1+(a+b x)^2}}{b}+\frac {6 (a+b x) \text {arcsinh}(a+b x)}{b}-\frac {3 \sqrt {1+(a+b x)^2} \text {arcsinh}(a+b x)^2}{b}+\frac {(a+b x) \text {arcsinh}(a+b x)^3}{b} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.90 \[ \int \text {arcsinh}(a+b x)^3 \, dx=\frac {-6 \sqrt {1+(a+b x)^2}+6 (a+b x) \text {arcsinh}(a+b x)-3 \sqrt {1+(a+b x)^2} \text {arcsinh}(a+b x)^2+(a+b x) \text {arcsinh}(a+b x)^3}{b} \]
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Time = 0.09 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.86
method | result | size |
derivativedivides | \(\frac {\operatorname {arcsinh}\left (b x +a \right )^{3} \left (b x +a \right )-3 \operatorname {arcsinh}\left (b x +a \right )^{2} \sqrt {1+\left (b x +a \right )^{2}}+6 \left (b x +a \right ) \operatorname {arcsinh}\left (b x +a \right )-6 \sqrt {1+\left (b x +a \right )^{2}}}{b}\) | \(67\) |
default | \(\frac {\operatorname {arcsinh}\left (b x +a \right )^{3} \left (b x +a \right )-3 \operatorname {arcsinh}\left (b x +a \right )^{2} \sqrt {1+\left (b x +a \right )^{2}}+6 \left (b x +a \right ) \operatorname {arcsinh}\left (b x +a \right )-6 \sqrt {1+\left (b x +a \right )^{2}}}{b}\) | \(67\) |
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Time = 0.29 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.78 \[ \int \text {arcsinh}(a+b x)^3 \, dx=\frac {{\left (b x + a\right )} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{3} - 3 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right )^{2} + 6 \, {\left (b x + a\right )} \log \left (b x + a + \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}\right ) - 6 \, \sqrt {b^{2} x^{2} + 2 \, a b x + a^{2} + 1}}{b} \]
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Time = 0.14 (sec) , antiderivative size = 109, normalized size of antiderivative = 1.40 \[ \int \text {arcsinh}(a+b x)^3 \, dx=\begin {cases} \frac {a \operatorname {asinh}^{3}{\left (a + b x \right )}}{b} + \frac {6 a \operatorname {asinh}{\left (a + b x \right )}}{b} + x \operatorname {asinh}^{3}{\left (a + b x \right )} + 6 x \operatorname {asinh}{\left (a + b x \right )} - \frac {3 \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1} \operatorname {asinh}^{2}{\left (a + b x \right )}}{b} - \frac {6 \sqrt {a^{2} + 2 a b x + b^{2} x^{2} + 1}}{b} & \text {for}\: b \neq 0 \\x \operatorname {asinh}^{3}{\left (a \right )} & \text {otherwise} \end {cases} \]
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\[ \int \text {arcsinh}(a+b x)^3 \, dx=\int { \operatorname {arsinh}\left (b x + a\right )^{3} \,d x } \]
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\[ \int \text {arcsinh}(a+b x)^3 \, dx=\int { \operatorname {arsinh}\left (b x + a\right )^{3} \,d x } \]
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Timed out. \[ \int \text {arcsinh}(a+b x)^3 \, dx=\int {\mathrm {asinh}\left (a+b\,x\right )}^3 \,d x \]
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