Integrand size = 12, antiderivative size = 275 \[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=-\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right ) \]
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Time = 0.28 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.667, Rules used = {5859, 5827, 5680, 2221, 2611, 6744, 2320, 6724} \[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{\sqrt {a^2+1}+a}\right )-\frac {1}{4} \text {arcsinh}(a+b x)^4 \]
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Rule 2221
Rule 2320
Rule 2611
Rule 5680
Rule 5827
Rule 5859
Rule 6724
Rule 6744
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\text {arcsinh}(x)^3}{-\frac {a}{b}+\frac {x}{b}} \, dx,x,a+b x\right )}{b} \\ & = \frac {\text {Subst}\left (\int \frac {x^3 \cosh (x)}{-\frac {a}{b}+\frac {\sinh (x)}{b}} \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\frac {\text {Subst}\left (\int \frac {e^x x^3}{-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}+\frac {e^x}{b}} \, dx,x,\text {arcsinh}(a+b x)\right )}{b}+\frac {\text {Subst}\left (\int \frac {e^x x^3}{-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}+\frac {e^x}{b}} \, dx,x,\text {arcsinh}(a+b x)\right )}{b} \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-3 \text {Subst}\left (\int x^2 \log \left (1+\frac {e^x}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right )-3 \text {Subst}\left (\int x^2 \log \left (1+\frac {e^x}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right ) \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-6 \text {Subst}\left (\int x \operatorname {PolyLog}\left (2,-\frac {e^x}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right )-6 \text {Subst}\left (\int x \operatorname {PolyLog}\left (2,-\frac {e^x}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right ) \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+6 \text {Subst}\left (\int \operatorname {PolyLog}\left (3,-\frac {e^x}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right )+6 \text {Subst}\left (\int \operatorname {PolyLog}\left (3,-\frac {e^x}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right ) \, dx,x,\text {arcsinh}(a+b x)\right ) \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+6 \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (3,\frac {x}{a-\sqrt {1+a^2}}\right )}{x} \, dx,x,e^{\text {arcsinh}(a+b x)}\right )+6 \text {Subst}\left (\int \frac {\operatorname {PolyLog}\left (3,\frac {x}{a+\sqrt {1+a^2}}\right )}{x} \, dx,x,e^{\text {arcsinh}(a+b x)}\right ) \\ & = -\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^3 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right ) \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 346, normalized size of antiderivative = 1.26 \[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=-\frac {1}{4} \text {arcsinh}(a+b x)^4+\text {arcsinh}(a+b x)^3 \log \left (1+\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+\text {arcsinh}(a+b x)^3 \log \left (1+\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+3 \text {arcsinh}(a+b x)^2 \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right )-6 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (3,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+6 \operatorname {PolyLog}\left (4,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right ) \]
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\[\int \frac {\operatorname {arcsinh}\left (b x +a \right )^{3}}{x}d x\]
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\[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{3}}{x} \,d x } \]
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\[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=\int \frac {\operatorname {asinh}^{3}{\left (a + b x \right )}}{x}\, dx \]
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\[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{3}}{x} \,d x } \]
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\[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{3}}{x} \,d x } \]
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Timed out. \[ \int \frac {\text {arcsinh}(a+b x)^3}{x} \, dx=\int \frac {{\mathrm {asinh}\left (a+b\,x\right )}^3}{x} \,d x \]
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