Integrand size = 19, antiderivative size = 144 \[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\frac {11 e^{c+2 b^2 x^2} x}{16 b^5 \sqrt {\pi }}-\frac {e^{c+2 b^2 x^2} x^3}{4 b^3 \sqrt {\pi }}+\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{b^6}-\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{b^4}+\frac {e^{c+b^2 x^2} x^4 \text {erfi}(b x)}{2 b^2}-\frac {43 e^c \text {erfi}\left (\sqrt {2} b x\right )}{32 \sqrt {2} b^6} \]
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Time = 0.18 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {6522, 6519, 2235, 2243} \[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=-\frac {43 e^c \text {erfi}\left (\sqrt {2} b x\right )}{32 \sqrt {2} b^6}+\frac {x^4 e^{b^2 x^2+c} \text {erfi}(b x)}{2 b^2}+\frac {e^{b^2 x^2+c} \text {erfi}(b x)}{b^6}+\frac {11 x e^{2 b^2 x^2+c}}{16 \sqrt {\pi } b^5}-\frac {x^2 e^{b^2 x^2+c} \text {erfi}(b x)}{b^4}-\frac {x^3 e^{2 b^2 x^2+c}}{4 \sqrt {\pi } b^3} \]
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Rule 2235
Rule 2243
Rule 6519
Rule 6522
Rubi steps \begin{align*} \text {integral}& = \frac {e^{c+b^2 x^2} x^4 \text {erfi}(b x)}{2 b^2}-\frac {2 \int e^{c+b^2 x^2} x^3 \text {erfi}(b x) \, dx}{b^2}-\frac {\int e^{c+2 b^2 x^2} x^4 \, dx}{b \sqrt {\pi }} \\ & = -\frac {e^{c+2 b^2 x^2} x^3}{4 b^3 \sqrt {\pi }}-\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{b^4}+\frac {e^{c+b^2 x^2} x^4 \text {erfi}(b x)}{2 b^2}+\frac {2 \int e^{c+b^2 x^2} x \text {erfi}(b x) \, dx}{b^4}+\frac {3 \int e^{c+2 b^2 x^2} x^2 \, dx}{4 b^3 \sqrt {\pi }}+\frac {2 \int e^{c+2 b^2 x^2} x^2 \, dx}{b^3 \sqrt {\pi }} \\ & = \frac {11 e^{c+2 b^2 x^2} x}{16 b^5 \sqrt {\pi }}-\frac {e^{c+2 b^2 x^2} x^3}{4 b^3 \sqrt {\pi }}+\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{b^6}-\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{b^4}+\frac {e^{c+b^2 x^2} x^4 \text {erfi}(b x)}{2 b^2}-\frac {3 \int e^{c+2 b^2 x^2} \, dx}{16 b^5 \sqrt {\pi }}-\frac {\int e^{c+2 b^2 x^2} \, dx}{2 b^5 \sqrt {\pi }}-\frac {2 \int e^{c+2 b^2 x^2} \, dx}{b^5 \sqrt {\pi }} \\ & = \frac {11 e^{c+2 b^2 x^2} x}{16 b^5 \sqrt {\pi }}-\frac {e^{c+2 b^2 x^2} x^3}{4 b^3 \sqrt {\pi }}+\frac {e^{c+b^2 x^2} \text {erfi}(b x)}{b^6}-\frac {e^{c+b^2 x^2} x^2 \text {erfi}(b x)}{b^4}+\frac {e^{c+b^2 x^2} x^4 \text {erfi}(b x)}{2 b^2}-\frac {43 e^c \text {erfi}\left (\sqrt {2} b x\right )}{32 \sqrt {2} b^6} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.66 \[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\frac {e^c \left (-4 b e^{2 b^2 x^2} x \left (-11+4 b^2 x^2\right )+32 e^{b^2 x^2} \sqrt {\pi } \left (2-2 b^2 x^2+b^4 x^4\right ) \text {erfi}(b x)-43 \sqrt {2 \pi } \text {erfi}\left (\sqrt {2} b x\right )\right )}{64 b^6 \sqrt {\pi }} \]
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\[\int {\mathrm e}^{b^{2} x^{2}+c} x^{5} \operatorname {erfi}\left (b x \right )d x\]
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none
Time = 0.26 (sec) , antiderivative size = 106, normalized size of antiderivative = 0.74 \[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\frac {43 \, \sqrt {2} \pi \sqrt {-b^{2}} \operatorname {erf}\left (\sqrt {2} \sqrt {-b^{2}} x\right ) e^{c} + 32 \, {\left (\pi b^{5} x^{4} - 2 \, \pi b^{3} x^{2} + 2 \, \pi b\right )} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )} - 4 \, \sqrt {\pi } {\left (4 \, b^{4} x^{3} - 11 \, b^{2} x\right )} e^{\left (2 \, b^{2} x^{2} + c\right )}}{64 \, \pi b^{7}} \]
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\[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=e^{c} \int x^{5} e^{b^{2} x^{2}} \operatorname {erfi}{\left (b x \right )}\, dx \]
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\[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\int { x^{5} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )} \,d x } \]
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\[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\int { x^{5} \operatorname {erfi}\left (b x\right ) e^{\left (b^{2} x^{2} + c\right )} \,d x } \]
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Time = 5.27 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.43 \[ \int e^{c+b^2 x^2} x^5 \text {erfi}(b x) \, dx=\mathrm {erfi}\left (b\,x\right )\,\left (\frac {{\mathrm {e}}^{b^2\,x^2+c}}{b^6}+\frac {x^4\,{\mathrm {e}}^{b^2\,x^2+c}}{2\,b^2}-\frac {x^2\,{\mathrm {e}}^{b^2\,x^2+c}}{b^4}\right )-\frac {3\,x^5\,{\mathrm {e}}^c}{8\,b\,{\left (-2\,b^2\,x^2\right )}^{5/2}}+\frac {11\,x\,{\mathrm {e}}^{2\,b^2\,x^2+c}}{16\,b^5\,\sqrt {\pi }}-\frac {x^3\,{\mathrm {e}}^{2\,b^2\,x^2+c}}{4\,b^3\,\sqrt {\pi }}-\frac {\sqrt {2}\,{\mathrm {e}}^c\,\mathrm {erfi}\left (\sqrt {2}\,x\,\sqrt {b^2}\right )}{8\,b^3\,{\left (b^2\right )}^{3/2}}+\frac {3\,x^5\,{\mathrm {e}}^c\,\mathrm {erfc}\left (\sqrt {-2\,b^2\,x^2}\right )}{8\,b\,{\left (-2\,b^2\,x^2\right )}^{5/2}}-\frac {\sqrt {2}\,\mathrm {erf}\left (\sqrt {2}\,x\,\sqrt {-b^2}\right )\,{\mathrm {e}}^c}{2\,b\,{\left (-b^2\right )}^{5/2}} \]
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